Mathematics for the second year of junior high school, real numbers, what is a real number for the s

1、c2、a

square root = +-13

The square root of 28900 = +-170

square root = +

4. 1 = +-1 under the root number

4 9 = -2 3 under the root number

(-5)2 = +-5 under the root number

6) 2 = 6 under the root number

5. Solution: The pole is perpendicular to the ground.

The triangle ABC is a right triangle.

According to the Pythagorean theorem, ab = (6 m) -3 m) = 27 m.

ab = m.

6. The square of the height of the isosceles triangle = the square of 2 - the square of 1 2 * 2).

High is 3 under the root number

Area = 1 2 * Bottom * Height.

1 2 * 2 * 3 under the root number

It's all my own doing! ac

3 (1) The title is unclear ......

2)-2 3 (minus two-thirds).

It is a right-angled triangle hypotenuse, and AB and BC are right-angled sides.

According to the Pythagorean theorem: ab = ac -bc = 6 -3 = 27ab = 27 = 3 3 = m.

6.The height on the bottom edge of an equilateral triangle is (4-1)= 3, then the area of the triangle is 2 3 2 = 3

I'll copy the question again for the time being!!

If you make a mistake, .........

To do these questions must be mastered: the simplification of absolute values, the removal of parentheses, the simplification of the simplest quadratic radical, the approximate value of the quadratic radical, the operation of the quadratic radical, if you don't understand, just read the book first, the following is my thinking process and solution process. ）

I'm a graduate of junior high school.,There are a lot of math terms in the second year of junior high school that I may not remember clearly.,Please forgive me.,Also,There are a lot of details in these questions.,You have to do more questions.,In order to grasp it firmly.,My QQ is 804010899.,If you still have questions.,Just ask me.,(Hehe,It seems to be a little self-inflicted))).

Analysis: (1): Simplification of absolute value: |√3－√6|, because 6 is greater than 3, so |√3－√6|＝√6－√3

2√3－3√5|, because 3 is greater than 2, 5 is greater than 3, so 3 5 is greater than 2 3, so |2√3－3√5|＝3√5－2√3

2): Remove parentheses: (3 3+ 6) 3 3 6

Then they do the math in turn.

Analysis (1) 12 can be reduced to 3 4 2 3

2 48 can be turned into 2 16 3 8 3

Calculate again.

Analysis: 3 (8 729) 3 8) (3 729) 2 9

Calculate 3 (8 729) 3 64+ (16 9)+1

4 ¼（2√2+√3）－⅔pai

Analysis: Calculated using the multiplicative distributive property.

2 and 3 also have a pai approximation (I seem to have forgotten what the approximation is, please forgive me, but your math books should have it, or there is also an approximation of the quadratic radical, you can look through it).

5 Analysis: When x 2 is.

Original (1

Because 1 is less than 2, it belongs to type A is less than B.

Therefore, 1 because 3 is greater than 2, it belongs to type A greater than or equal to B.

So 3 2 2 squared 4

So the original formula 1 4 3

Hope it helps!!

1.Solution: Original = 3 6 2 3 3 5+3 3- 6 = 3 3+3 3-3 5-2 6

2.Solution: Original = 36 + 2 144

303.Solution: Original formula = -2 9 + 2 + 4 3 + 1 = 37 9

4.Solution: Original = ---4 3

5.Solution: x=2

Original (1

3Let me tell you,These mathematical symbols can be typed out with special symbols in the Sogou Pinyin input method! It doesn't have to be so troublesome.

Very bracket 1 is very simple: first simplify, simplify 6- 3+3 5-2 3+3 3- 6

That's 3 5 parentheses 2 12 = 2 3 48 = 4 3 original = 3 * 6 3 = 18 3

The bracket 3 cube root will not be hit(Cube root 8/729 = 9 8 Cube root -64 = 2.)

16/9 of the root number = 3 16 Original = 9 8-2+3 16+1 Calculate by yourself.

Bracket 4 Hehe, hey, there's an accurate computer, anyway, the initial elevation can be used.

Brackets: 5 1 x=1 3 x=2 Element=-1

Give points to the tired symbol is difficult to hit Hold down the shift button (alt key) with your left hand, then press 41420 in turn, then release your left hand, and the root number will come out. I'm tired.

Please, do your math homework yourself

Use your own brain! I haven't learned yet.

A circle with a diameter of 1 unit length rolls from the origin point to the right along the number axis, and the point on the circle reaches the point 0 from the origin'Then 0'The coordinates of , the purpose of doing this exercise is to illustrate that the formula for the circumference of a circle is the product of the diameter of this method of research and problem solving, which embodies the mathematical method of thinking by straightening the curve.

Both rational and irrational numbers are included. Among them, irrational numbers are infinite non-cyclic decimals, and rational numbers include integers and fractions. Mathematically, real numbers are intuitively defined as numbers that correspond to points on the number line.

Originally, real numbers were only called numbers, but later the concept of imaginary numbers was introduced, and the original numbers were called "real numbers" - meaning "real numbers".

To put it simply, I mean to say all the numbers.

Any number is fine.

The area of the square table =

The sum of the area of the two types of tablecloths = 2 1 1 = 2m Put the two tablecloths together into a large square tablecloth with a side length of 2 meters.

Because of 2, this large tablecloth can cover the current table.

1.Respectively, the square of 2 under the 3 root number is 18, the square of 2 under the root number is 12, and the square of 3 under the root number is 12, 18 is greater than 12, so the 2 under the 3 root number is greater than 2, and the root number is under 3

2.The root number is 2/2 of the root number, so it is less than the root number 2

3.The root number is one fraction of the root number and is 5 so the root number is less than one fraction of the root number.

Hey comrade, wouldn't it be nice if you squared them all out?

2010 is about 1936 is 44 squared, then from 1=1 to 1936=44, there must be 44 numbers that are rational. Then the irrational number is 2010-44=1966

You've grown up, child, and since you don't want to embarrass your mother, you have to study hard! Others can learn you, so from now on, pick up the math book of the first year of junior high school and read it word by word, to think carefully

1 + 1 / 1 + 1 / 2) + (1 + 1/2 + 1 / 1 / 3) = 3 2 + 7 6 = 8 3 = 2 + 2 3

1+1/1 + 1/2) sum of square root + (1+2/1 + 1/3) square root + (1+1/3 + 1/4) sum of square root = 3 2+7 6+13 12=15 4=3+3 4

1+1/1 + 1/2) and the square root + (1+2/1 + 1/3) of the square root + (1+1/3 + 1/4) and the square root + ......1 + 1/2009 + 1/1 of 2010).