First, simple math to solve equation calculation problems.

1. According to the proposition, x cannot be equal to 2, nor can it be equal to 0, the equation can be solved, so multiply both sides of the equation by x(x-2) at the same time, then the equation becomes:

x^2-(x-2)=x(x-2)

x^2-x+2=x^2-2x

x=-22, according to the question, x cannot be equal to plus or minus 1, otherwise the equation has no solution, so both sides of the equation are multiplied by x 2-1 at the same time, then the equation becomes:

4+x^2-1=(x+1)^2

4+x^2-1=x^2+2x+1

2x=4-2

x=1 is based on the question, so there is no solution to this equation.

Solution: Denominator is removed, and both sides of the equation are multiplied by x(x-2) at the same time

x²-（x-2）=x（x-2）

Sorted out. x²-x+2=x²-2x

Move the item. x=-2

Tested. x=-2 is the root of the equation.

Remove the denominator and multiply x -1 on both sides of the equation at the same time

4+x²-1=（x+1）²

Sorted out. x²+3=x²+2x+1

Move the item. 2x=2

The coefficient is assigned as 1x=1

It is tested that x=1 is not the root of the equation.

There is no solution to the equation.

Question 2 Multiplication of both sides of the equation x(x-2) gives x 2-(x-2)=x(x-2) So x=-2

Question 3 Multiplication x 2-1 on both sides of the equation gives us 4+x 2-1=x 2+2x+1 Solve x=1 Because the denominator in the original equation cannot be 0, there is no solution.

1 equal sign multiply x(x-2) on both sides

x²-x+2=x²-2x

x=-22 multiplication of both sides of the equal sign (x+1)(x-1)4+x -1=(x+1).

x²+3=x²+2x+1x=1

The first question is x=2 and the second question is x=1, but since the denominator cannot be 0, there is no solution! Hope!

Multiply x on both sides at the same time

Get 2x 2-4x=6

2x^2-4x-6=0

x^2-2x-3=0

x-1)^2-1=3

x-1)^2=4

x-1=±2

x=3 or x=-1

2x-4=6/x

i.e. solve the system of equations {x!.}=0 ;(= is not equal to) {2x2-4x-6=0.}

Solution: x=-1 or x=3

1: Solution: If cucumbers have x kilograms, then tomatoes have 3x kilograms, then:

x+3x=24

4x=24x=6 (kg).

3x = 18 (kg).

A: Buy back 6 kg of cucumbers and 18 kg of tomatoes.

2。Solution: Let car B travel x kilometers per hour, then:

x+45)×5=450

x+45=90

x = 45 (km).

3。Solution: (4 5-3 4) x = 1

1/20x=1

x=20

1.Set the cucumber to weigh x

Question: x+3x=24, x=6, 3x=18 cucumbers weigh 6kg, tomatoes weigh 18kg.

2.Let the velocity of B be x, and the problem is obtained: 45 5+5x=450, 5x=225, x=45

3. 4/5x=3/4x+1, 16/20x-15/20x=1， x=20

1.Solution: Buy cucumbers x kilograms, buy tomatoes 3 kilograms.

x+3x=24

The solution is x=6,3 6=18

A: My mother bought back 18 kilograms of tomatoes and 6 kilograms of cucumbers.

2.Solution: Let car B travel x kilometers per hour, and car A travel at a speed of 50 kilometers per hour.

450÷5=50+x

Solution x=40

A: Car B travels 45 kilometers per hour.

Solution 3: 4x 5=(3x+1) 4

Multiply both sides by 20.

16x=15x+5

Shift item x=5

Let the mass of cucumbers be x grams and the mass of tomatoes be y grams. From the question, y=3x, x y=24 can be obtained by the two formulas, x=6, y=18

SA = V A 5 = 45 * 5 = 225 km

s B = 450 - s A = 450-225 = 125 km v B = s B 5 = 15 km h

4x/5 - 3x/4=1

16x/20 -15x/20=1

x/20=1

x=20

1. Let the cucumber be x, and get 3x+x=24, x=6,,, so the tomato is 18 and the cucumber is 6

2. Let car B be x, and get 45x5+5x=450, so car B is 25

3, 4x fifths = 3x+1 quarters, giving 5 (3x+1) = 4xx4, giving x=5

Let the middle number be x, then the other two are x+2 and x-2;

x+x-2=x+2；

x=4；So they were 642

2.Let the birthday be x, then:

x+1+x-1+x+7+x-7=92;

4x=92;

x=23;Mom's birthday is the 23rd.

3.If the height is xcm, then:

20*17*x=π(10)²*34;

x=3400*

So Gao Wei. 4.Let the profit be x yuan, then:

x=280(1+;

x=280*

For each piece sold, a profit will be made.

1. The number of Pingping's house is: (x-2) (x) (x+2), then there is: x-2+x=x+2, and the solution is: x=4, so the house number is: 246.

2. Let the mother's birthday be x, then there are: (x-7) + (x-1) + (x-1) + (x+7) = 92, and the solution is: x=23, that is, the mother's birthday is the 23rd.

3. Let the height of the part be x, then there is: *10 2*34=20 *17*x, and the solution is: x=10cm.

(1+25%)*RMB.

1. Three even numbers in a row, and the two numbers are equal to the third number, for , therefore, the house number of Pingping's house is 642

x = 92, x = 23.

3. The height is: *10*10*34 20 *17=10cm *(1+25%)*85%) = 298 yuan, 298-280 = 18 yuan, and each piece can make a profit of 18 yuan.

1. The house number of Pingping's house is exactly three consecutive even numbers from large to small, and the sum of the first two numbers is equal to the third number, can you calculate what the house number of Pingping's house is?

This question is not right, it should be the sum of the two numbers that are small equals the number that is large If it is 642, then 6+4=2?

b≠0 is multiplied by 12b 2 on both sides of the equation at the same time.

9×4+3×1＝12b^2

b 13 2 or b - 13 2

Solution: If there are x footballs, then there are 100-x basketballs.

100-x）÷2+（1-30%）x=5850+

x=40 basketball: 100-40=60.

More basketball than football: 60-40 = 20.

First, look at the definition field on the left, where x is less than or equal to 1

Then square left and right.

1-x=x² +25+10x

Shift x +11x+24=0

x+8）(x+3)=0

Solution, get Qi Ran x=-8 or x=-3

They all meet the definition of the dust dismantling domain of Paizai Jujube, so they are all solutions.

Solution: Original = -2x +x -4x+4-2x+6x=-x +4 original =x -4x-x +27=-4x+27 m a=3, m 3a=27, the same way, m 2b=16, m 3a m 2b=m 3a-2b =27 16=27 16 If you are satisfied, please adopt, I wish you good progress in learning.

1. -2x square + (2-x) square - 2x + 6x = -2x square + 4-4x + x square - 2x + 6x = -x square + 4

2. x(x+2)(x-2)-(x-3)(xsquare+3x+9)=x(xsquared-4)-(x-cubic-27).

x-cubic-4x-x-cubic+27

4x+273, 3a to the power of m-2b = 3a of m, 2b power of m = (a power of m) 3rd power (b power of m) 2nd power = 3rd power of 3 2.