A few simple high school chemistry overdose calculation questions

Are you self-taught? Why else wouldn't it be so simple?

cl2 == 2 hcl

The reaction is 1:1, so it happens to react, the mass is conserved, and the last 4+71=75 g reaction donates electrons.

The reaction donates electrons.

The reaction donates electrons.

2mol l, the volume is 250ml, containing h+ (2*250 1000)*2 = 1 mol

The volume is 250 ml H+ (= mol, the volume is 250 ml H+ (=

It's cold water, then the answers are:

4.10:1 :1 (Why 10:1:1?) Because na can react with water).

If it is a hot solution, mg also reacts with water.

Learning progress.

，。, you should take this question to junior high school students!

1.Copper is.

Because one cu loses 2 electrons.

The total given electrons are.

And n from +5 to +2 and +4 valence.

Let the generation of no2 xmol no ymol so the obtained electron is x+3y mol=

So x+3y=

And the amount of the total gaseous substance is.

x+y=according to Got it.

x=y=i.e. no is.

NO2 is. 2so2+o2=2so3

Starting 8 6 0 Change +

Finally so in the end SO2 is.

O2 is so3 is.

The total mass is unchanged as 8 (32 + 16 + 16) + 6 32 = 512 + 192 = 704g

The amount of total substance is:

The average molecular weight is 704

Yes, no and no 2 gases are altogether.

3cu---2no

3x 2xcu---2no2

2x+ gets x=

So no2 has, no has.

Initial 8 6 0 turns.

Flat unit mol

So SO2——,O2——,SO3-

The average relative molecular mass is (8 64 + 6 32) (

1.is the answer.

2.n=m= is the answer.

3.n=26 zinc molecular weight, v= is the answer.

4.That is, it is composed of 3 parts of potassium chloride mixed with 1 part of sodium chloride, so w = 3* (3 * potassium chloride molecular weight + 1 * sodium chloride molecular weight) is the first answer.

That is, there is potassium chloride + sodium chloride: m = potassium chloride molecular weight + sodium chloride molecular weight is the answer.

v=vm*n=

m=m/n=

So the relative molecular mass of this gas is 64

1) What is the volume of gas generated in the standard condition?

2) What is the amount of substance concentration of the resulting solution solute?

It's a trick question.

According to the title, Ca2+, CO32-, and HCO3- are all converted into precipitates, and you can write the reaction as:

na2co3 + cao + h2o = caco3↓ +2naoh……①

nahco3 + naoh + cao = caco3↓ +2naoh……②

NaOH in solids can be considered to be unchanged.

The mass of the original solid mixture is 29g after the reaction of the solution evaporated, and the solid mass is increased by 29g - = , it can be seen that the reaction consumes H2O as, and the reaction consumes Na2CO3 and the mass is xg:

na2co3 + cao + h2o = caco3↓ +2naoh

x can easily calculate the mass of Na2CO3 in the mixture as: .

Solution: Let the amounts of Na2CO3, NaHCO3, Cao, and NaOH be A, B, C, and D, respectively

cao+h2o=ca(oh)2

NaHCO3+NAOH=NA2CO3+H2ONa2CO3+CA(OH)2=2NAOH+CACo3 (precipitation) can be seen from the title.

The increase in the solid mass is the mass of water in CaO+H2O=Ca(OH)2 minus the mass of water in NaHCO3+NaOH=Na2CO3+H2O18b-18c=

Therefore, B-C = exists because Ca2+ (calcium ion), CO3 2- (carbonate ion), and HCO3- (bicarbonate ion) are all converted into precipitation.

b = a + c (conservation of mass).

Hence a=b-c=

Then the mass of Na2CO3 is.

2mol L of HNO3 is definitely emitted

1）3cu ~ 2no

That is, 192 gcu emits 60 gno, so for every 192 gcu added, the mass of the solution is net increased by 132 g

m(cu)=

3cu ~ 8hno3

In this case, the amount of the substance that consumes Hno3 is nanti(Hno3) = (2) The amount of Hno3 that is reduced is equal to the amount of the substance that is released.

n also(hno3)=n(no)=,m also(hno3)=(3)n(no3-)=n(hno3)-nn(hno3)=,c(no3-)=

3cu ~ 8h+

nanti(h+)=,n(h+)=,c(h+)=,c(h+)=(4)n(cu2+)=,n(naoh)=2n(cu2+)=2*,v(naoh)=

Analysis: annual water flow q 3600 24 365, the thermal energy of these water ep mgh vgh 103

Convert electrical energy to e ep Answer:

Solution: 1) The mass fraction of spike cherry is:

2) c=n v=(m m) (m) (m) m=3) The mass of potassium nitrate required is:

m=1000*

Potassium nitrate mass: