ABCX 9 XCBA What is the value of A, B, C X?

abcx

XCBA is still a four-digit number because XCBA.

So a must be 1, otherwise abcx 9 wouldn't be a four-digit number.

And since the single digit of x 9 is 1, x must be 9

Write the equation as.

1 bc99cb 1

Because b 9 has no carry (otherwise a 9 carry product would not be a four-digit number), b must be 0 (because a=1).

And because the single digit of c 9 8 is 0, c must be 8

i.e. abcx=1089

Check: 1089 9 = 9801

4 digits 9 = 4 digits, (abcx*9=xcba), then ab = 10 or 11;

If ab=10 x 9=a=?1 is x=9 ( 1 9≠1=a cannot be 1), so that there is 10c9 9=9c01That is, 0c 9+8=c0 is required to take 08 9+8= ; Verify; 1089×9=9810.

In line with the topic. If ab=11 x=9 gets 11c9 9=9c11, that is, 1c 9+8=c1 is required to take 07 9+8=71 c=7;Verify; 1179×9=10711.Off topic.

It can only be 1089i.e. a=1b=0 .c=8 .x=9

a=3b=12

c=6, and the second equation should be b+c=18. Thank.

Summary. What is known as ab+c=49 a+bc=50 to find a, b, c?

Two possibilities.

Summary. a=2, b=9, c=0 This problem uses the method of reasoning to be equal to three A, and adding a number is equal to 8, then three A's have 3, 6, 9, so three A's can only be 6, so A=2

ab+ab+aa=8c to find out what abc is.

a=2,b=9,c=0 This problem uses the method of pushing and grasping the reasoning is equal to three A, plus a large number of skin disturbances is equal to 8, then three A's have 3, 6, 9, so three rolling A can only be 6, so A=2

Then a=2, two b+2=20, so b=9, c=0

First look at the last digit, the end of 9 9 must be 1, so a=1 and then look at the first digit, 1bc9 9=9cb1

Indicates that there is no carry in the hundred-digit operation, b=0 or 1

If b=1, considering that 9c11 is divisible by 9, c=7, it is wrong to bring in the checkIf b=0, considering that 9c01 is divisible by 9, c=8, bring in the check 1089 9=9801, which meets the requirements of the question.

So a=1, b=0, c=8

Summary. Hello, glad to answer for you. a+b+c=120 a-b=8 b-c=9, and the values of abc are ., respectively

33 and. From a-b=8 and b-c=9, a-c=a-b+b-c=8+9=17 can be obtained. There is also a formula of a+b+c=120, which denotes a and c as b:

a=b+8, c=b-9, substituting gets: b+8+b+b-9=1203b=121b=

a+b+c=120 a-b=8 b-c=9 to find abc

Why not answer? Hello Youpai, I'm glad to answer for you. a+b+c=120 a-b=8 b-c=9, and the values of abc are ., respectively

33 and. From a-b=8 and b-c=9, a-c=a-b+b-c=8+9=17 can be obtained. There is also a formula of a+b+c=120, which means that a and c represent the god Hu envy as b:

Do rock a=b+8, c=b-9, substitute gets: b+8+b+b-9=1203b=121b=