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For the simplest true fraction of the same denominator with any denominator greater than 2, the number of elements must be even, and the sum must be half of this even number. The denominator is subtracted from all non-simplest true fractions (including the false fraction with the same numerator and denominator), and the difference is the even number.
Find the denominator as the sum of all the simplest true fractions of 12.
There are 6 multiples of 2 in 12, 4 multiples of 3, and 2 multiples of (2 3), and the number is known to be 2
The denominator is 105, and the sum of the simplest true fractions is 24
Why? Analysis and Answer: These fractions are the simplest fractions, so the numerator should be less than 105, it can only be a natural number in 1-104, and the molecule and 105 should be coprimitive.
Because, so the denominator cannot be a multiple of 3 or a multiple of 5 or a multiple of 7. Therefore, to ask for the number of simplest true fractions is actually to find out how many of the 104 natural numbers from 1 to 104 are not divisible. Therefore, it is necessary to find out how many numbers are divisible by 3 or divisible by 5 or divisible by 7.
Numbers divisible by 3: (pcs).
Numbers divisible by 5: (pcs).
Numbers divisible by 7: (pcs).
Numbers divisible by both 3 and 5:
Numbers divisible by both 3 and 7:
Numbers divisible by both 5 and 7: each).
Answer: There are 48 fractions with a denominator of 105. Solution:
By 105 = 3 5 7, that is, 35 multiples of 3 in 105, 21 multiples of 5, 15 multiples of 7, multiples of (3 5), (5 7), (3 7) are respectively, and 1 multiple of (3 5 7). Know.
A: The denominator is 105, and the sum of the simplest fraction is 24
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The denominator is 105, and the numerator is 1-104, and it is not a multiple of 5, 3, and 7, so the denominator is 105, and the numerator is.
1,2,4,8, (4 pcs).
11, 13, 16, 17, 19, (5).
22, 23, 26, 29, (4).
31, 32, 34, 37, 38, (5).
41, 43, 44, 46, 47, (5).
52, 53, 58, 59, (4).
61, 62, 64, 67, 68, (5).
71, 73, 74, 76, 79, (5).
82, 83, 86, 88, 89, (5).
92, 94, 97, (3).
101, 103, 104, (3).
4+5+4+5+5+4+5+5+5+5+3+3+3=48.
The lowest true fraction with a denominator of 105 has 48.
The sum of these molecules is 2520
Their sum is 24
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Summary. The denominator is 105, and the simplest true fraction is 1-104, and it is not a multiple of 5, 3, 7, then the denominator is 105, and the numerator is.
1,2,4,8, (4 pcs).
11, 13, 16, 17, 19, (5).
22, 23, 26, 29, (4).
31, 32, 34, 37, 38, (5).
41, 43, 44, 46, 47, (5).
52, 53, 58, 59, (4).
61, 62, 64, 67, 68, (5).
71, 73, 74, 76, 79, (5).
82, 83, 86, 88, 89, (5).
92, 94, 97, (3).
101, 103, 104, (3).
4+5+4+5+5+4+5+5+5+5+3+3+3=48.
How many fractions are there at least true with a denominator of 105? What is the sum of them?
Hello, there are 48 minimum true fractions with a denominator of 105, and their sum is 24 The denominator is 105, how many simple true fractions are there that is, the numerator is 1-104, and it is not a multiple slip of 5, 3, 7, then the denominator is 105, and the numerator is 1, 2, 4, 8, (4) 11, 13, 16, 17, 19, (5) 22, 23, 26, 29, (4) 31, 32, 34, 37, 38, (5) 41,43,44,46,47, (5)52,53,58,59, (4)61,62,64,67,68, (5)71,73,74,76,79, (5)82,83,86,88,89, (5)92,94,97, (3)101,103,104, (3)4+5+5+5+5+5+5+5+5+5+3+3=48.
The sum of these molecules is 2520
So the answer is 48, and the sum is 24 ha.
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Summary. The simplest true fraction with a denominator of 105 is 105-7=98.
How many fractions are there at least true with a denominator of 105? What is the sum of them?
Hello. The simplest true fraction with a denominator of 105 is 105-7=98.
There are 3, 5, 7, 15, 21, 35, 105, a total of 7 numerators that can be divided into 105, and the sum of their numerators is from one to 105, and then these seven numbers are subtracted.
And is 5374 105
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98 (find the approximation).
Parting mode and solving prime factor:
So no: 3 105,5 Hashikei 105 7 105 15 105 21 105 35 105 105 Min Ma Shen 105
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How many fractions are the simplest true fractions of the denominator is 105, that is, the numerator is 1-104, and it is not a multiple of 5, 3, 7, then the denominator is 105, and the numerator is 1, 2, 4, 8, (4) 11, 13, 16, 17, 19, (5) 22, 23, 26, 29, (4) 31, 32, 34, 37, 38, (5) 41, 43, 44, 46, 47, (5) 52, 53, 58, 59, (4) 61,62,..
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There are 3,5,7,15,21,35,105 that can be about 105, a total of 7 teasing.
The denominator is the simplest true fraction of 105 in 105-7=98.
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The simplest true fraction with a denominator of 10 is:
So. Well, their sum is 2.
Hope it helps, thank you!
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The denominator is the simplest true fraction of 10, which has 1 10, 3 10, 7 10, 9 10
So, the sum of the simplest true fractions with a denominator of 10 is 2.
The main thing is to find these simplest and true scores, and calculate them carefully.
The denominator is 10, and the numerator is picked from 1-9, and even numbers are definitely not good, and 5 is not good, and there are only four left.
It's not difficult, FYI.
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105=3x5x7
There is a factor of 3 in 105: 105 3 = 35.
There are 105 with a factor of 5: 105 5 = 21.
There are factors 7 in 105: 105 7 = 15.
105 has a factor in 105 15 = 7 105 has a factor in 105 105 has a factor in 105 105 has a factor in 105 105 has a factor in 105 105 has a factor in 105 105 105 has a factor in 105 105 105 105 105 has a factor in 105 105 105 has a factor in 105 105 has a factor in 105 105
105 35 = 3 105 There are factors in 105 105 = 1 35 + 21 + 15-7-5-3-1x2
54 pcs.
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105 = 5*7*3, and his prime factor is that as long as it is not a multiple of 5,7,3, it is satisfied.
Within 105, there are 20 multiples of 5, 34 multiples of 3, 14 multiples of 7, 14 common multiples, and common multiples.
As well as 105 itself.
The remaining 105-20-34-14-1+6+4+2=48 is 48, that is, there are 48.
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