In a series circuit, the power of each consumer is not equal

In a series circuit, the current flowing through each load is equal, because the voltage value on each load is inversely proportional to its own resistance value, so the greater the resistance of the electrical equipment connected in series in the circuit, the smaller the voltage drop generated on it, and vice versa, the smaller the resistance, the greater the voltage drop. As for the electrical power consumed on each device, it is deduced according to the formula: the power consumed is proportional to the square of its own voltage drop, in other words:

The greater the voltage drop (voltage), the more power it consumes (its value is equal to the square of the voltage). If we want to talk about the relationship between resistance and power consumption, it should be that the resistance of electrical equipment is inversely proportional to the power consumed, that is, the greater the resistance, the smaller the electric power consumed, and the smaller the resistance, the greater the electrical power consumed. This is why the daily electricity is reduced in the power equipment and the power supply in parallel connection of this way of connection, under the premise of stable power supply voltage, the voltage of each electrical equipment on the parallel road is the same, the current flowing through each electrical equipment is determined by its own resistance, the smaller the resistance, the stronger the current capacity, the greater the resistance, the weaker the current capacity.

If you want to use high-power electrical equipment in this circuit, you have to find a way to reduce your resistance in order to pass a larger current, and the power will increase accordingly. As for whether the voltage inequality mentioned in your question will damage the entire circuit, it can be understood in theory, that is, the use of series connection this wiring method will cause the voltage of the electrical equipment connected to the same power supply circuit to be unequal, but in the actual power supply application, the electrical equipment is connected in parallel on the power supply circuit, because as a power supply network, if you want to transmit electric energy at a high power and long distance, and at the same time ensure the power quality, it is generally not allowed to connect the electrical equipment in series into the power system. Especially for high-power electrical equipment, once the system voltage fluctuation is too large, it will bring a serious threat to the safety of the whole system, and the voltage is too high will cause insulation breakdown of electrical equipment and damage to electrical equipment; If the voltage is too low, it will cause the entire power supply system**, and in severe cases, it will also cause the system to collapse. Therefore, voltage quality is an important measure of a power supply system.

As long as the voltage obtained by each load in the circuit is not higher than the rated voltage, there is no problem (except for motors), and the actual voltage obtained is proportional to the resistance of each load, that is: actual voltage = current * resistance. The current is the same throughout the circuit.

If the internal resistance of the power supply is ignored, the actual voltage of each consumer can be determined according to the resistance and the output voltage of the power supply. If the calculated voltage is less than the rated voltage of the consumer, the electrical appliance will not be burned (except for the electrical appliance where electrical energy is converted into mechanical energy). In the case of electric motor installations (devices in which electrical energy is converted into mechanical energy), it is also possible to burn out electrical appliances at a voltage lower than the rated voltage, because there are such cases:

The voltage is lower than the rated voltage, unable to rotate the motor, the electric energy will only be converted into the energy of the coil heating in the motor, and the actual voltage may be high, and the heat generated is likely to make the coil in the motor reach a very high temperature, resulting in the life of the motor becoming shorter, or even burned out.

The voltage of the electrical appliance is not equal and will not destroy the line.

Also: p=i*i*r

The currents are equal, but the resistance of the appliance is not necessarily equal, so the power is not necessarily equal. ，。However, the power output of the generator is constant p=u*i

Because of the voltage, the current is constant. Therefore, the power factor is also unchanged, and the frequency fluctuates around 50Hz. The deviation is in the +

No. The power can vary. Because the resistance of each appliance is not necessarily the same.

It depends on the rated power and voltage rating of the electrical appliances you use.

If both of these matches, there will be no problem.

However, commonly used electrical appliances generally do not use series connection, and are generally in experimental circuits. Also, the series voltage divider will only make the voltage of each appliance less than the total voltage, do the math yourself).

Why do you want to use appliances in series?

error, in the series circuit.

, the more powerful the appliance, the greater the voltage distributed. Because according to the relationship between power and voltage, current; p = u*i, where p is power, u is voltage, and i is current; From the relationship, it can be seen that the current is fixed, and when the power of the electrical appliance becomes larger, the voltage must be increased in order for the relationship to be established.

First of all, let's understand the series circuit, the series circuit is to connect all the electrical appliances one by one in series to form a circuit without branches, which is the series circuit. In the series circuit, the total voltage of the series circuit is equal to the sum of the voltages of each section, and the voltage shared by each consumer is proportional to its own resistance, so we also call the series circuit a voltage divider circuit. Because there is no branch in the series electric slag commes, the current in the circuit is the same, that is, whether the resistance is large or small, the current is equal.

And a little bit of electric power.

Whether in series or parallel circuits.

, the total power is equal to the sum of the electrical power of the individual conductors.

As shown in the figure, it is the simplest series circuit, there is only one current path, and the two small bulbs with equal power selling rate in the figure have p=u*i, which can be obtained, and the voltages at both ends of the two small bulbs are equal; If you replace one of the small bulbs with a larger power bulb, you can take a multimeter at this time.

Measure the two small bulbs separately, and the measured voltage will definitely be different, and the larger power bulb that is replaced will be more than the other. (The reason is already explained above).

The higher the power of the appliance, the smaller the resistance value, and the smaller the voltage distributed in series.

For pure resistive components, the higher the rated power, the smaller the resistance, and the smaller the voltage when connected in series.

p=ui

When connected in series, U=U1+U2, total power p total = U Total I=(U1+U2)I=U1I+U2I=P1+P2

When connected in parallel, total i = i1 + i2, total power p total = ui total = u(i1 + i2) = ui1 + ui2 = p1 + p2

That is, the total electrical power in the series circuit and the parallel circuit is equal to the sum of the power of each subcircuit.

Voltage, current, resistance.

With Ohm's law: voltage, current, resistance.

Under AC, the voltage and current impedance. Here, voltage, current, and impedance are all phased. Complex numbers in mathematics are widely used in electrical engineering, and voltage, current, and impedance are calculated by complex numbers, which is more convenient.

Formula: Ohm's law i=u r, electric bi no current unit a, voltage unit v, resistance unit

Electrical power refers to the work done per unit time, the symbol is p, p w t, w is work, and the unit is j; When the demolition room unit is S. The electrical power can be expressed as p i 2 * r (the square of the current i is divided by the resistance r) = u 2 r (the square of the voltage u divided by the resistance).

1. If there is only one resistor in the same circuit, it can be said that it has nothing to do with the voltage. The voltage is only artificially added at both ends of the resistor, and has nothing to do with the size of the resistance.

Second, if there are other electrical appliances in the same circuit in addition to this resistor, then it will have an impact on the voltage. However, its effect only affects the distribution of voltage across the appliance. That is, the greater the resistance, the greater the power supply voltage allocated by the resistor itself, and the smaller the voltage at both ends of other electrical appliances.

3. Essentially, resistance does not hinder voltage. Resistance is the obstacle of the current, you can analyze it from the micro aspect, the current is a carrier, they pass through the resistance together, just as the uneven road is to stop them. The ratio of the number of carriers in a group blocked by the resistor is certain, so if you want to increase the number of currents passing through, you must increase the voltage to increase the number of carriers.

However, the ratio of the number of resistors has not changed, and the proportion is still the same.

Although the components in a series circuit have equal current, they are subjected to the same voltage, and the natural power is not equal.

Because the electric power formula p 山武游ui i r u orange ruined r

The current is equal, but the resistance of the electrical appliance is not necessarily equal, and the pin is connected to the series circuit r according to p ui i r, the larger the p is.

For example, when a 20W bulb and a 100W bulb are working in series, the 20W one burns out due to the excessive current flowing through the filament, and even if the 20W one does not burn, the 100W one will not emit light normally.

Electrical power. In physics, the work done by an electric current per unit of time is called electrical power. It is a physical quantity used to express the speed of electrical energy consumption, expressed by p, and its unit is watt, abbreviation"tile", the symbol is w.

As a physical quantity that indicates how fast or slow the work of an electric current is done, the magnitude of the power of an electrical appliance is numerically equal to the amount of electrical energy it consumes in 1 second. If in"t"(Si unit is S) The electrical energy "W" (Si unit is J) consumed for such a long period of time, then the electrical power of this appliance is p=w t (definition) The electrical power is equal to the product of the voltage at both ends of the conductor and the current passing through the conductor.

p=u·i）。For purely resistive circuits, the electrical power can also be calculated using the formulas p=i 2*r and p=u 2 r.

Each electrical appliance has a normal working voltage value called rated voltage, the power of the electrical appliance working normally under the rated voltage is called the rated power, and the power of the electrical appliance working under the actual voltage is called the actual power.

Yes, for example: 2 nominal 6V light bulbs, if A is 3W and B is 6W, if they are connected in series in a 12V circuit, because the resistance of the 3W bulb must be large, the voltage generated must be greater than 6V, and it will soon burn out and the circuit will be interrupted.

This problem is not fully described, I will guess according to your meaning to explain it, the power is compared to a stone, 2 people lift together, only 2 people have the same strength when they can lift the heaviest stone, if a force is big, a force is small, how much weight can be lifted by the strength of the small decision, the strength of the big one is useless,

Let the two resistors be R1R2 and the supply voltage is U

Then the circuit current: i=i1=i2=u (r1+r2)p1=i1 2*r1

u/(r1+r2)]^2*r1

U 2R1 (R1+2R1R2+R2)=U 2R1 [R1-R2) 2+4R1R2]R1=R2, the denominator is the smallest and P1 is the largest.

P1 max = U2 4R2

According to P=U2R, the rated voltage of the two lamps is equal, so Ra Rb=Pb Pa=2 1.

Note: The ratio of electrical power in a series circuit is equal to the ratio of resistance, which is still true here.

It's just that after these two lamps are connected in series in the 220V circuit, the actual voltage is not equal to the rated voltage, and the actual power is not known, so it is impossible to calculate the ratio of electrical power equal to the ratio of resistance.

The power ratio is equal to the ratio of resistance.