High School Chemistry Please explain each option in detail, how to write the equation, and what the

The equation is written below:

Whether the mixture can be separated by filtration mainly depends on whether the two are miscible or not, if they are miscible they cannot be separated by filtration, if one substance is soluble in water and the other substance is insoluble in water.

Option A: The product of the reaction between copper sulfate and sodium hydroxide is copper hydroxide precipitate and sodium sulfate solution, which can be separated by filtration.

Option B: Iron powder reacts with dilute sulfuric acid to produce ferrous sulfate solution and hydrogen, copper powder and dilute sulfuric acid do not react, and can be separated by filtration.

Option C: Sodium hydroxide and dilute hydrochloric acid react to produce sodium chloride solution and water, which are miscible and cannot be separated by filtration, but can be separated by distillation.

Option d: The product of the reaction is potassium chloride and oxygen, manganese dioxide does not participate in the reaction as a catalyst, potassium chloride is soluble in water, manganese dioxide is insoluble in water, and can be separated by filtration.

Option A: CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4 copper hydroxide precipitation.

Option B: Fe+H2SO4=FeSO4+H2 does not produce precipitation, but only insoluble copper remains.

Option C NaOH + HCl = NaCl + H2O no precipitation.

Option D 2kClO3 = (, mNO2) = 2kCl + 3O2 There is still Mno2 left as a catalyst

A: CuSO4+2NaOH====Cu(OH)2(precipitate)+Na2SO4 precipitate is copper hydroxide.

B: Fe + H2SO4 = = = = Fe So4 + H2 (gas) should be copper does not react with dilute sulfuric acid, so the precipitate is copper.

C: NaOH+HCl====NaCl+H2O has no precipitation.

D: 2kClO3=2kCl+3O2 is equal to the above Mno2 as a catalyst, and the lower symbol indicates the heating precipitate into manganese dioxide. Therefore, C

CuSO4+2NaOH=Cu(OH)2 +Na2SO4 blue precipitate generation, the upper part is a clear solution Mass conservation law experiment.

Ca(OH)2 + CO2 = CaCO3 + H2O Clarified lime water becomes turbid, apply CO2 inspection and lime mortar to paint the walls.

Ca(HCO3)2δ CaCO3 +H2O+CO2 white precipitates eggplant, produces gas that makes the clarified lime water turbid, and scales are formed. Formation of stalactites.

HCl+AGnO3= AGCL+HNO3 Produces white precipitate, insoluble in dilute nitric acid The principle of testing Cl—.

Ba(OH)2+ H2SO4=BASO4 +2H2O produces a white precipitate, insoluble in dilute nitric acid The principle of testing SO42—.

BaCl2+ H2SO4=BaSO4 is high +2HCl to generate white precipitate, insoluble in dilute nitric acid The principle of testing SO42—.

Ba(NO3)2+H2SO4=BASO4 +2HNO3 Generate white precipitate, insoluble in dilute nitric acid The principle of testing SO42—.

FeCl3+3NaOH = Fe(OH)3 +3NaCl solution fades yellow and has reddish-brown precipitate.

AlCl3+3NaOH = Al(OH)3 +3NaCl has a white precipitate to form.

mgcl2+2naoh = mg(oh)2↓+2nacl

CuCl2+2NaOH = Cu(OH)2 +2NaCl solution fades blue and has a blue precipitate.

CaO+ H2O = Ca(OH)2 white bulk solid becomes powder, quicklime to prepare lime slurry.

Ca(OH)2 + SO2=CASO3 + H2O has a white precipitate to generate in junior high school.

Ca(OH)2+Na2CO3=CaCO3 +2NaOH has a white precipitate to produce industrial caustic soda and a small amount of laboratory caustic soda.

Ba(OH)2+Na2CO3=BaCO3 +2NaOH has a white precipitate to form.

Ca(OH)2+K2CO3=CaCO3 +2koH has a white precipitate to form.

AgNO3+NaCl = AGCl +Na NO3 white precipitate insoluble in dilute nitric acid (similar reaction to other chlorides) It is used to test chloride ions in solutions.

BaCl2 + Na2SO4 = BaSO4 + 2NaCl white trembling like color, insoluble in the precipitation of dilute nitric acid (similar reaction to other sulfates) It is used to test sulfate ions.

CaCl2+Na2CO3= CaCO3 +2NaCl has a white precipitate to form.

MgCl2+Ba(OH)2=BaCl2+Mg(OH)2 is formed with a white precipitate.

The precipitation symbol must be marked with no solids in the reactants, otherwise the precipitate symbol cannot be labeled even if the product contains insoluble substances. For example, the transformation between precipitates: 2AGcl+I2=2AGI+CL2, AGI is originally precipitated, but since AGCL is also precipitated, it cannot be marked with a precipitation symbol.

Another example: H2SO4 + BA(OH)2=BASO4 +2H2O, because barium sulfate is insoluble in water and there is no solid in the reactants, so it needs to be marked with a precipitation symbol.

Common precipitation: potassium sodium ammonium salt and nitrate are soluble, carbonate has barium carbonate, calcium carbonate is insoluble, magnesium carbonate is slightly soluble.

Sulfates include barium sulfate, lead sulfate insoluble, calcium sulfate, and silver sulfate slightly soluble.

Hydroxide** potassium, sodium, ammonium, barium are soluble, and the rest are insoluble or non-existent or extremely unstable (such as silver hydroxide).

Silver ions are insoluble except for nitrate.

That's all there is to it, you need to memorize it, work hard.

Below pay you a connection to the dissolution table.

The need to mark the precipitation symbol refers to the solids formed by the reaction of the solution, i.e., the insoluble substances.

When we say precipitation, we generally mean water-insoluble substances.

General water insoluble substances are:

Silver chloride: white precipitate.

Barium sulfate: white precipitate.

Calcium carbonate: white precipitate.

Iron hydroxide: reddish-brown.

Magnesium hydroxide: white precipitate.

Wait a minute...

There are so many that there is a solubility table at the back of the textbook that you can find there.

CO2, SO2 and lime water, Ba(OH)2 solution:

CO2 + Ca2+ +2OH- = CaCO3 +H2OCAco3 + CO2 + H2O = Ca2+ +2HCO3-SO2 + Ca2+ +2OH- = CaSO3 +H2OCASO3 + SO2 + H2O = Ca2+ +2HSO3- (Ba(OH)2 solution is the same principle).

agNO3 and NH3·H2O

ag+ +nh3·h2o = agoh↓ +nh4+agoh + 2nh3·h2o = [ag(nh3)2]+ oh- +2h2o

HCL and Naalo2:

H+ +alo2- +h2o = al(oh)3 al(oh)3 + 3h+ = al3+ +3h2onAOH and alCl3:

al3+ +3oh- = al(oh)3 al(oh)3 + oh- = alo2- +2h2o, that's basically it......

Oh yes, and CA (clo)2 and CO2:

ca2+ +2clo- +co2 + h2o = caco3↓ +2hclo

CaCO3 + CO2 + H2O = Ca2+ +2HCO3- (Note that if it is Naclo, there will be no Na2CO3 generation, it is NaHCO3).

CO2+Ca(OH)2=CaCO3+H2OC2+CaCO3+H2O=CA(HCO3)2ALC3+3NaOH=3NaCl+Al(OH)3AL(OH)3+NaOH=NA[Al(OH)4]AGNO3+NH3·H2O=AGoH4NO3AGOH+2NH3·H2O=AG(NH3)2OH+2H2OThere are many similarities to accumulate by yourself, It is impossible to put them all here, and the above are a few examples, I hope to adopt them.

h2so4+bacl2=2hcl+baso4↓

so4(2-)+ba(2+)=baso4↓

Numeric subscript Superscript in parentheses.