Help with an elementary school math problem, ask a master to help you do a primary school math probl

1. The time is equal, the difference between the first time and the second time is 42-24=18km The first time against the water and the second time is 14-8=6km, from which it can be seen that the speed of the water is 18 6 = 3 times that of the water, so if it is all along the water, you can go 42 + 8 * 3 = 66km in 11 hours, that is, the speed of the water is 6km, and the same is calculated that the speed of the water is 2km, and the average speed of the water and the water is the speed in the still water, that is: (6 + 4) 2=5. The water speed is Shunshui - hydrostatic speed = 6-5 = 1km

Satisfied? I'm a math teacher, hehe! I just wanted to go online to help people solve it today, and I saw you!!

Because the time is the same twice, the time to travel (42-24=18) kilometers is equal to the time to travel against the water (14-8=6).

42 km downstream, 8 km upstream, 11 hours.

Equivalent. Sail along the water (42 + 8 * 3 = 66) kilometers, and share 11 hours.

Downstream velocity = 6 kmh.

Similarly. Speed against the water = 2 kmh.

So. Water velocity = ( Downstream velocity - Reverse velocity ) 2 = 2 km.

Hydrostatic velocity = downwater velocity - Water velocity = 4 kmh.

The first, subparagraphs 24, 18, 8

The second, subparagraphs 24, 6, 8

Therefore, the ratio of reverse water and downstream speed is 1:3

8 km against the water = 24 km downstream, then if the first time along the water: 42 + 24 = 66 km, 6 is the speed of the downstream.

8+14=22 km, 2 is the speed against the water, (6+2) 2=4 is the speed of the ship, then 2 is the speed of the water.

Math teacher, the water is in the back...

42-24=18km

14-8=6km

18/6*14=42km

24+42=66km

66/11=6km

24 6 = 4 hours.

11-4 = 5 hours.

The speed of the ship and the speed of the water.

Grade 5 should learn simple equations, right? This problem cannot be calculated using arithmetic methods.

The math Olympiad is to make children stupid and adults crazy.

This question embodies the idea of equations.

Is it a problem in elementary school?

Suppose the multiplier is a, and the multiplier is less than 3, and the product is three times less than the multiplier, so the multiplier is 609 divided by 3 equals 203, so the correct product is 203 times 18 = 3654

One factor = 609 (18-15) = 203

The correct product is 203 18 3654

Question 2.

Then you can make up to 6*3*2=36.

Question 1. Volleyball and soccer account for 1-1 5 = 4 5

then x 6<4 5

x "then x = 1,2,3,4

When x=1, soccer accounts for 4 5-1 6=19 30 and total balls 60 [19 30]=

When x=2, soccer accounts for 4 5-2 6=7 15, and the total number of goals is 60 [7 15]=

When x=3, soccer accounts for 4 5-3 6=3 10, and the total number of goals is 60 [3 10]=200

When x = 4, soccer accounts for 4 5 - 4 6 = 2 15 and the total number of goals is 60 [2 15] = 450

It can be seen that when volleyball accounts for 3 6, the total number of balls is 200.

When volleyball accounts for 4 6, the total number of balls is 450.