Urgent distress high IQ personnel, please take a look

11 – represents the "1 1" of the previous line, so 11

21 – represents the "2 1s" of the previous line, so 21

1211 – represents "1 2, 1 1" in the previous line, so 1211111221 – represents "1 1, 1 2, 2 1" in the previous row, so 111221

So the next line should be, "3 1s, 2 2s, 1 1s", so it's 312211 remove the comma and the numbers again).

Programming Intelligence: 1 11 21 1211 111221 The question is simple:

What's the next number?

This topic was posted by Zhou Xingxing, but I can't guess it. But after reading the answer, it is not difficult to understand, the design is really amazing! It is recommended that you memorize it in case you need it!

author : zhou

#include

#include

#include

using namespace std;

int main( void )

string s = "1";

cout ostringstream os;

for( size_t i=0; i<;i )size_t n = 1;

char c = s[i];

for( ;i< s[i+1]==c; +i ) n;

The OS Cout program results in:

It's genius to know the answer, and I'm going to have to watch it for a few minutes to understand.

It depends on the software you're using.

I've seen n more attendance software, and I haven't encountered the software as bad as you said, probably because you don't have to use it.

The "shift" you are talking about is not a shift, but actually a "time period", and a shift can be composed of 3 time periods in the morning, noon and evening.

If you tell me the brand of the attendance machine you use and the software version you use, I can tell you how to set it up.

These three periods should be set into one shift. Shifts in general attendance software support multiple time periods.

Pay attention to the 24-hour clock 8:00-12:00 13:30-17:30 18:00-21:00

Basically, the current attendance machine can be set up for multiple time periods, if your attendance machine does not have it, you can consider replacing it.

Disinfect the home, parvo infection is very strong, isolate the dog, buy a test strip to check the other straight to get the parvo! If you get to go to the hospital as soon as possible! The more you drag on the parvo, the more troublesome it is!!

Wouldn't it be nice to go to all the schools you went to and the places where you worked, and you don't understand where the files have gone!!

In the high school where you graduated, you can ask.

If you didn't go to the archives to get it, it should still be there.

You don't have to.

To pay online, you have to be on your own machine, unless the thief buys it from your machine, otherwise it's for rice.

You can go to Telecom to log out of the Internet.

Proof: AD BC

adc+∠bcd=180°

cdk=1/2∠adc

dck=1/2∠bcd

cdk+∠dck=1/2(∠adc+∠bcd)=1/2×180°=90°

ckd = 180° - (cdk + dck) = 180° - 90° = 90° The same can be said: each corner of the quadrilateral klgh is 90°

So: the quadrilateral klgh is rectangular.

∵ab//cd

abc+∠bad=180°

AE BF is the bisector of Bad ABC.

lgh=∠agb=90°

In the same way, glk=90° lkh=90°

The quadrilateral ghkl is a rectangle.

Proof: Because AE and BF are the angular bisectors of Bad and ABC, respectively.

So bae=1 2 bad; abf=1 2 abc again because quadrilateral abcd is a parallelogram.

So abc= adc; bad= bcd, so abc+ bad=180 degrees, so bae+ abf=1 2( abc+ bad)=90 degrees.

So agb=90 degrees.

In the same way, dkc = nhe= mlf = 90 degrees, so the quadrilateral ghkl is rectangular (the quadrilateral with all four corners at right angles is a rectangle).

In the parallelogram ABCD, DAB+ ABC=180°, and AE and BF bisect DAB, ABC BAE+ BAF=90° respectively, so AGB=90°, and in the same way, DKC=90° and AE and CM are the diagonal bisectors of the parallelogram, and AE CM, so the quadrilateral GHKL is a rectangle.