Elementary School Score Questions! Urgent! Primary School Math Percentages Hurry, Hurry, Hurry!

Fraction (21).

2.There are 33 boys and 27 girls in a class. (with fractions).

The number of boys is the number of girls (11 9), and the unit "1" here is (number of girls).

The number of girls is the number of boys (9 11), and the unit "1" here is (number of boys).

The number of boys is the class size (11 20), and the unit "1" here is (class size).

The number of girls is the class size (9 20), and the unit "1" here is (class size).

3.Fill in the appropriate scores.

5 cm = (1 2) dm 30 minutes = (1 2) 42 kg = (21 500) tons.

42 kg = (21 500) tons 5 hours = (5 24) days 51 minutes = (51 100) yuan.

37 square decimeters = (37 100) square meters 513 grams = (513 1000) kilograms.

917dm3 =( 917/1000)m3

The most important is a coloring problem: the scores are represented by color in the diagram.

There are two circles, each of which is divided into 4 equal parts.

You want to color these two round seven-quarters

Paint any 7 pieces.

33 out of 1 (or 6 out of 1 out of 27) Number of female students.

27 out of 33 Male students.

33/60 Class size.

27/60 Class size.

3.1 in 2 2 42 in 1000

5/24 51/100

37/100 513/1000

917/1000

4.One circle is fully coated, and the other is painted in 3 parts.

Elementary School Score Questions! Urgent!

Bounty Points: 100 - 14 days and 23 hours until the end of the question.

Fraction (21).

2.There are 33 boys and 27 girls in a class. (with fractions).

The number of boys is the number of girls (33/27), and the unit "1" here is (number of girls).

The number of girls is the number of boys (27/33), and the unit "1" here is (number of boys).

The number of boys is the class size (33/60), and the unit "1" here is (class size).

The number of girls is the class size (27/60), and the unit "1" here is (class size).

3.Fill in the appropriate scores.

5 cm = (1 2) dm 30 minutes = (1 2) 42 kg = (21 500) tons.

42 kg = (21 500) tons 5 hours = (5 24) days 51 minutes = (51 1000) yuan.

37 square decimeters = (37 100) square meters 513 grams = (513 1000) kilograms.

917dm3 =( 917/1000)m3

The most important is a coloring problem: the scores are represented by color in the diagram.

There are two circles, each of which is divided into 4 equal parts.

You want to color these two round seven-quarters

It's divided into 8 pieces in total, isn't it? Except for one that is not painted, all the others are painted.

Urgent! Help! It's just what I want, and you can add a high score!

2.1 and 6/27 27/27 is 1

27/33

33/60

27/60

3.5cm = 5 10 = 1 2dm 30 minutes = 30 60 = 1 2 42 kg = 42 1000 = 21 500 tons.

5 hours = 5 24 days 51 minutes = 51 100 yuan.

37 square decimeters = 37 100 square meters 513 grams = 513 1000 kg 917 dm3 = 917 1000 m3

The sum of length and width is.

40 2 20 (cm).

Width is unit 1 and length is 1 50 150

Width 20 (1 150) 8 (cm).

The length is 8 150 12 (cm).

The area is 12, 8, 96 (square centimeters).

Analysis: Let the length of this rectangle be x, then there is.

Width = 2 x 3, circumference = 2 (x + 2 x 3) = 40cm, you can get x = 12cm, that is, the length is 12 cm, the width is 8 cm, so the area = 12 * 8 = 96 square centimeters = square meters.

Dividend divisor = 3......2

Dividend + Divisor + Quotient + Remainder = 87

Then the dividend + divisor = 82

Divisor = (Dividend - Remainder) (Quotient + 1).

The divisor is (82-2) (3+1)=20

Presented = divisor quotient + remainder.

The dividend is 20 3+2=62

The dividend plus the divisor is equal to 87-3-2 = 82

The divisor is (82-2) (3+1)=20

The dividend is 20 3+2=62

Dividend + Divisor + Quotient + Remainder = 87, Quotient = 3, Remainder = 2 Dividend + Divisor = 87-3-2 = 82

Dividend -2) = 3 times the divisor, 82 is equivalent to 3 divisors + 1 divisor + 2 divisors = (82-2) (3+1) = 20

Dividend = 3 20 + 2 = 62

Dividend plus divisor = dividend plus divisor plus quotient plus remainder --quotient - remainder = 87-3-2 = 82

Dividend = divisor * 3 + 2 Dividend + divisor = divisor * 3 + 2 + divisor = divisor * 4 + 2 = 82 Then the divisor = 82-2 and divided by 4 equals 20

Dividend = 20 * 3 + 2 = 62

You don't need to write the above when answering the text question, just write this: divisor = (87-3-2-2) (3 + 1) = 20, dividend = 20 * 3 + 2 = 62.

I've run out of points, so if you have more points, give me more, please.

87-2-3=82

Because: the dividend divided by the divisor is equal to 3 and the remainder is 2, that is, the dividend is 3 times more than 2 times the divisor; So there is a divisor of 4 times plus 2 equals 82; So (82-2) 4=20, i.e. the divisor is 20, then the dividend is equal to 20*3+2=62

After the remainder is removed from the divisor, the addition of the divisor is equal to 87-3-2=82, which is 1+3=4 times the divisor.

The divisor is 82 4=

Add the remainder to get the dividend.

Divide by equals 3 and balance 2

87-3-2=82

The divisor is (82-2) divided by (3+1)=20

The dividend is 20 3+2=62

The equation sets the divisor to xThe dividend is 3x+2

3x+2+3+2+x=87,x=20

The dividend is 62 and the divisor is 20

87-2-3=82, 82-2 divided by 4=20 is the divisor, so the dividend is 20*3+2=62

62 and 20

According to the condition of the question, the sum of the two is 82, and subtracting the remainder is the divisor and the divisor of triples, so the divisor is 20

The original number of people in the navigation module is 8x, and the number of people in the car module is 7x. Column: (8x-4) divided by (7x+4)=4 divided by 5 Solution: x=3 then 8x=24 (person) Remember the praise and reward.

Solution: Let the number of the aviation module in the last semester be 8x, and the number of the car module is 7x (8x-4) (7x+4)=4 5

Solve x=3

The number of people in the aircraft module: 8x=24 (people).

A: Originally, the number of people in the module was 24.

It turned out that the aviation module accounted for 8 15 of the total number of people

After 4 people are changed to car modules, the ratio is 4 9

Then the proportion of these 4 people to the total number of people is (8 15-4 9) = 4 45, and the original aircraft module accounts for 8 15 of the total number of people

After 4 people are changed to car modules, the ratio is 4 9

Then the proportion of these 4 people to the total number of people is (8 15-4 9) = 4 45, then the total number of people is:

4 (8 15-4 9) = 4 (4 45) = 45 then the original number of aircraft modules is:

45*(8 15)=24 people.

Then the total number is:

4 (8 15-4 9) = 4 (4 45) = 45 then the original number of aircraft modules is:

45*(8 15)=24 people.

According to the title, we can know that here, the total number of aviation modules and car modules is unchanged, then, the original aviation module accounted for 8/15 of the total number of people, and now, accounting for 4/9 of the total number of people, it is because the 4 students were transferred, so use 4 (8 15-4 9), calculate the total number of unit 1, and then use the total number of people in unit 1 45 multiplied by 8 15 to calculate the equal of 24 people.

A: Originally, there were 24 people in the aircraft module.

If there are x people in the model aircraft and y people in the car model in the last semester, then according to the proportion of the previous semester, it is obtained: x:y=7:

8. After the transfer of personnel in this semester, the number of model aircraft is X-4, and the number of model cars is Y+4, then according to the ratio of the number of people in this semester, it is obtained: (X-4):(Y+4)=4:

5. The above two proportions are obtained, x=24, y=21, so the aviation module originally had 24 people.

Let the number of people in the original aviation module be 8x, then the number of people in the original car module is 7x, the number of people in the adjusted aviation module is (4 9) * [8 + 7) x] = (20 3) x, and the number of people in the adjusted car module is (5 9) * [8 + 7) x], then:

8x-4=（20/3）x

The solution is x=3 So, the original number of people in the aeronautical module is 8x=8*3=24

The number of aircraft modules in the last semester is 8y, and the number of car modules is 7y

Then: (8y-4) (7y+4)=4 5

y=3, so the original number of aircraft modules is 8 3=24

As can be seen from the title, the original aviation module accounted for 8 15 of the total number of people

After 4 people are changed to car modules, the ratio is 4 9

Then the proportion of these 4 people to the total number of people is (8 15-4 9) = 4 45, then the total number of people is:

4 (8 15-4 9) = 4 (4 45) = 45 then the original number of aircraft modules is:

45*(8 15)=24 people.