Two line test application problems are solved, and one line test problem is solved

1. If 12 are all qualified, you should get 120 yuan, which whenever there is an unqualified appearance, the 10 yuan you should get not only can't get, but also have to deduct 5 yuan, inside and outside is 15 yuan gone, now the actual 90 yuan, 30 yuan less than 120 yuan, 30 divided by 15 is equal to 2, so 2 of the 12 are unqualified.

2. If doubling means exactly doubled, that is, the excess part of the water fee is 5 yuan per ton, that is, the excess part is overcharged per ton.

15 tons of water, all according to each ton of yuan, should be paid yuan, the actual collection of 62 yuan, 62 minus equal, that is, more than the standard part of the water and pay an additional yuan, and because the excess part of each ton is overcharged, so more than the standard used tons (divided by equal to, so the standard water consumption is tons.

If the person uses 12 tons of water next month, of which, the ton is the standard water consumption, and the remaining ton (belongs to the water that exceeds the standard, the water money for the standard water consumption is yuan, and the water money that exceeds the standard is yuan, 13 + 34 = 47 yuan, so the person pays 47 yuan for water next month.

These are two application questions: Xiaoqiang asked his grandfather how old he was, and he said:"My age plus 17 is divided by 4, the first question is backwards, first divide 100 by 10 plus 15, then multiply by 4, and finally subtract 17.

B: Division B, C is the slowest.

1 Zhang 3 Department 27 dan = m Li 4 Department 28 dan = 14 m Wang 5 Department 34 dan = 17 m.

Since the trees are all whole roots, Zhang San's department sawed a total of rice, so their trees can only be meters long, so Zhang San's department B.

2 Correspondingly, the 17-meter-long Wang Wu department cannot be 2 meters long, it can only be 1 meter long wood, and Wang Wu is the C department.

3 The remaining woods of Li Si's department are all 2 meters long, and Li Si is from the first department.

m = 9 pieces of wood 2 times per wood a total of 18 saws;

14 m = 7 pieces of wood 3 times per wood sawed a total of 21 times;

17 meters = 17 pieces of wood, each piece of wood sawed once, a total of 17 times.

So department C is the slowest.

Note: As you can know from the title, no matter how long the whole piece of wood is, it is required to be sawn into rice specifications. From this:

1 meter of wood only needs to be sawn once, and it becomes 2 meters of size; The rice needs to be sawed 2 times to become 3 rice specifications; The 2-meter one needs to be sawed 3 times and divided into 4 meters.

As in the title: Zhang San 27 Li Si 28 Wang Wu 34 odd numbers are part B Therefore, Zhang San is part B.

The even number and divisible by four is part A, so Li Si is department A, Wang Wu is department C, and Zhang Sansaw has the least and slowest wood segment.

So the answer is D :)

Down payment of 90*10,000.

Loan 90*00,000.

Think backwards, use equations first.

Solution: Let car B travel x kilometers per hour.

95*（10/9）＋（10/9）x＝220x＝103

Down payment of 660,000 loan of 1,540,000 103 kilometers per hour.

This question was done by elementary school students!

Solution:1

Set up two cars to meet in x hours.

I tidy it up and get it. 99x=693

x = 7 two cars drive out and meet for 7 hours.

2.Let's assume that the cost of each product is $x.

x(1-5%)=

I tidy it up and get it. 95x=3740

x = the original cost of each product is yuan.

: Because the question asks about time, set the time to x.

Column: 45 (1+.)

If the time is x, then the distance traveled by the truck should be 45x, and the passenger car is a multiple, so the passenger car should be 45x, and there are two 45s here, using the distribution rate of multiplication, take out 45 x = 1, so it is equal to 45 (1+

45×99x=693

x=7A: The two cars meet 7 hours after they leave.

Let's assume that the cost per product is x.

Column: x(1-5%)=

Since the current cost is 5%, it is also reduced by 5%, that is, 1-5% = 95%. , whose 95%? is 95% of the current cost. In other words, 95% of the current cost = .

So: 95%x=

x=A: The current cost is yuan.

1 The speed of a passenger car is twice that of a train, so 45 693 (45 54) = 693 99 = 7 hours.

2。A decrease of 5% means that the current ** is 1 5% of the original, that is, the yuan is 95% of the original

So meta.

1.There are 95 students in the seventh grade class. The average attainment rate in physical education is 60%, and if the attainment rate in the first class of the seventh grade is 40%...The attainment rate of Class 2 in Grade 7 is 78%...Q: How many students are in each of the 7th grade classes?

There are x people in class 1 of the seventh grade, and there are y people in class 2 of the seventh grade.

x+y=95

40%x+78%y=95*60%

x=45y=50

There are 45 students in Class 1 of Grade 7 and 50 students in Class 2 of Grade 7.

2.Hospital A. The two raw materials B are nutritional products for patients after surgery, and each gram of raw material A contains one unit of protein and one unit of iron.

Each gram of B raw material contains units of protein and units of iron. If the patient needs 35 units of protein and 40 units of iron per meal. Then every meal A.

How many grams of the two raw materials are just enough to meet the needs of the patient?

Set x grams of raw material A and y grams of raw material B for each meal.

x+x=28

y=30 28 grams of raw material A and 30 grams of raw material B per meal just meet the needs of patients.

There are four natural numbers A, B, C, and D, and their sum does not exceed 400, and a divided by b quotient is 5 and 5, a divided by c quotient is 6 and 6, and a divided by d quotient is 7 and 7. So, the sum of these four natural numbers is: (

a/b=5...5(b>5)

a/c=6...6(c>6)

a/d=7...7(d>7)

a=5b+5=6c+6=7d+7

It can be seen that a is divisible at the same time.

a is the least common multiple of 5,6,7, 5*6*7=210

The sum of these four natural numbers is 210+(210-5), 5+(210-6), 6+(210-7), 7=210+41+34+29=314

The average score of A, B, and C is 95 points, and the part of A, B, C, is 95*3=285 points.

The average score of B, C and D is 94 points, and the total score of B, C and D is: 94 * 3 = 282 points.

A is more than D: 285-282 = 3 points, because E is the third place to take the test 96 points, so, D has two possibilities, one is D is less than E, given that A is the first place, and D is three points more, A can only be 98 points and D is 95 points, B, C has a person who takes 97 points, in this way, the other score in B and C is: 285-98-97 = 90, which is contradictory to everyone scoring more than 91, so D must be in front of E. i.e. d is the second place.

D is the second place, the score is more than 96 points, combined with A is 3 points more than D, you can know that D's score is 97 points, and A's score is: 100 points.

a167 b168 c169 d170

2 3,1 Tanzakura 2,3 7,7 18,(

a5 9 b4 11 c3 13 d2 51 2=5 and letter judgment change 10

8 22 = 4 11 (numerator + 1, denominator + 4) choose b

Time = total travel time for one vehicle + difference between the departure time of the first and last vehicles.

This time difference is equivalent to the distance between ten cars.

360 V+10(V10) 2 V=360 V+The minimum value is v=60

12 hours. It's really a problem, and the interval between cars is 36 kilometers.