Urgent known a b 3 a b 1 0, find the value of a b 2011

By |a+b-3|+(a-b+1)=0, when a+b-3>=0, the original formula =a+b-3+a-b+1=0, a=1, b>=2;

When a+b-3<=0, the original formula =3-a-b+a-b+1=0, and b=2 and a<=1; are obtained

In summary, we can get: a-b<=-1

Therefore, (a-b) 2011<=(-1) 2011

i.e. (a-b) 2011<=-1.

I think you may have made a mistake in this question, and there is no point in coming up with this kind of question.

I think the title should be like this:

Known |a+b-3|+(a-b+1) 2=0, find the value of (a-b) 2011.

Solution: Because |a+b-3|>=0,(a-b+1) 2>=0,and |a+b-3|+(a-b+1)^2=0

Therefore, for the equation to be true, there must be a+b-3=0 and a-b+1=0, so a-b=-1

So(a-b) 2011=-1

a|=1, which one has to be answered: Qingqing a = 1

b|=3, gets: b = 3

When the slow family a=1 and b=3: a+b=4

When a=1, b=-3: a+b=-2

When a=1, b=-3: a+b=-2

When a=-1, b=-3: a+b=-4

|a|=3，|b|=2,Bi Shi a= 3,b = 2;

Hand car AB 0, AB different number

1) When a=3, b=-2, a-b=3+2=5;

2) When the number of Bi is a=-3, b=2, a-b=-3-2=-5

If a=3, b=1, then |a-b|=|3-1|=2 If a = 3 and b = -1, then |a-b|=|3+1|=4 If a = -3 and b = 1, then |a-b|=|-3-1|=4 If a = -3 and b = 1, then |a-b|=|-3+1|=2

This should be discussed clearly, when a = 3, b = 1, the result is equal to 2When a=3, b=-1, the result is equal to 4When a=-3, b=1, the result is equal to 4, and when a=-3, b=-1, the result is equal to 2

It can be seen that if AB has the same sign, the result is 2, and the different sign is 4

This posture is simple, the sum of the two numbers is equal to 0 and the leakage is boring, and the absolute value must be greater than or equal to 0

Therefore, both absolute values are 0

i.e. a+1=0, a=-1

b-3=0,b=3

a=-3 b=1

a+b= -2

The absolute value must be a non-negative number, and if the sum of the two absolute values is zero, then they are each zero.

1. a=2 or -2, b=3 or -3

Because: b a

So: b = -3, a = -2 or 2

2、b＞-a＞a＞-b

I'm glad to answer for you, and I wish you progress in your studies! Moment Forever 523 Answer for you If you agree with my answer, please click the [Choose as satisfactory answer] button below, thank you If you have any other questions, please ask me for help, it is not easy to answer the question, please understand

This is simple, the sum of the two numbers is equal to 0 and the absolute value must be greater than or equal to 0, so both absolute values are 0

i.e. a+1=0, a=-1

b-3=0，b=3