There are only four Sundays in February every year, right or wrong

Wrong.

February has a maximum of 5 Sundays, with the first day of February being Sunday, and then leap years, for a total of 29 days, leaving 28 days, exactly 4 weeks.

February is the second month of the Gregorian year, with 28 days in a common year and 29 days in a leap year. There have been 3 times in history, with 30 days in February. In the Northern Hemisphere, February is the third month of winter.

In the twelve earthly branches, the second month was built.

Mythological stories

The 365-day month arrangement in a normal year is completely in line with our thinking, that is, according to the big month, the small month, the big month, the small month, the big month, the small month, the big month, the small month, the big month, the small month, the small month, the big month, the small month, the small month, the right six big months and six small months. The Gregorian calendar was established in 46 BC by Emperor Rosa. Originally, he set a year of 12 months, 31 days in a single month and 30 days in a double month, so that there were 366 days in each year.

However, Rome at that time had to execute a group of prisoners every February, so February was considered an unlucky month. As a result, Caesar reduced February by one day, leaving 29 days. Later, Caesar was killed, and Augustus became emperor, and he found that Caesar's birth was born in July with 31 days, and his birth was only 30 days in August, so he subtracted one day from February to August.

This leaves 28 days in February and 31 days in August. At the same time, he changed the number of days in the following months, and it became like this. However, there is no other historical evidence for this, and it is likely to be just a myth, albeit a very old one.

In a normal year, there are only 28 days in February, so there can only be a maximum of 4 Sundays. February in leap years has 29 days, and if February 1 is a Sunday, February of that year is 5 Sundays.

In math judgment problems, everything that has an absolute consciousness of "only a certain certainty" is wrong.

In a normal year, there are only a maximum of 4 Sundays, while in a leap year there are 5 Sundays.

March is a total of 31 days.

5 Tuesdays: A continuous period of time, starting on Tuesday and ending on Tuesday, for a total of 5 Tuesdays, for a total of 29 days. In these 29 days, there are 4 Mondays, because the first Tuesday is missing from it, and the next 4 Tuesdays have Mondays next to it.

There are 2 more days to be scheduled around this 29-day period.

And ahead, it is not suitable to arrange the leakage of socks, because there is no more Monday uproar, once the arrangement is extended forward to add Monday. These two days can only be arranged in the back as a week.

3. Thursday.

Thus, the 31 days begin on Tuesday and end on Thursday.

Therefore, the last day of March must be Thursday!

30 days in April 7=4 weeks. 2 days (4+1=5, Tuesday, Wednesday) Answer: April 1 is Tuesday.

April 1 is a Tuesday (because the fifth Tuesday must be April 29).

Summary. There are 5 Tuesdays and 4 Wednesdays in February of a certain year, and you know what day of the week is February 1 in this year, whether this year is a normal year or a leap year, and how to do this question.

Hold on. February 1 of this year falls on a Tuesday, and this year is a leap year.

Analysis: There are 7 days in a week, so the cycle is 7, when Tuesday has five days, and Wednesday has four days, the last day of the empty stool at the end of the month is Tuesday, which happens to be the 29th, then February 1 is also Tuesday, to meet the theme of the fight.

Hope mine can help you!

How did this picture come about, show it to the child for fear that he will not understand.

A few years old?

3rd grade. This chart is pushed up from the 29th, with a period of 7, exactly to the 1st.

You can also push up from the 28th, but February 1 is a Wednesday, and it is not enough to meet the "there are 5 Tuesdays".

The third-graders were able to understand it.

It's Tuesday. Solution: Assuming that January 1st, 8th, 15th, 22nd, and 29th of the year are Thursdays, then January 2nd, 9th, 16th, 23rd, and 30th are Fridays, and there are five Fridays, which is not in line with the topic; In the same way, if the 2nd day falls on Thursday, there will be 5 Fridays, which is also not in line with the topic; Assuming that the 3rd is a Thursday, then there are exactly 5 Thursdays and 4 Fridays, so that January 1 of the year is a Tuesday.

Many of the same types of math problems can be solved in this way.

The Law of Division:

The arithmetic nature of division.

1. The dividend expands (shrinks) n times, and the divisor remains unchanged, and the quotient also expands (shrinks) n times accordingly.

2. The divisor expands (shrinks) n times, the dividend remains unchanged, and the quotient shrinks (expands) n times accordingly.

3. The dividend-being divided by two divisors consecutively is equal to the product of the two divisors.

1. Dividend divisor = quotient.

2. Quotient = divisor.

3. Divisor quotient = dividend.

4. Divisor = (Dividend - Remainder) quotient.

5. Quotient = (dividend - remainder) divisor.

[Solution].

Assuming that the 1st, 8th, 15th, 22nd, and 29th are Thursdays, then the 2nd, 9th, 16th, 23rd, and 30th are Fridays, and there are 5 of them, which is not in line with the topic; Similarly, the 2nd is a Thursday, and there will be five Fridays, which is also undesirable; Assuming that the 3rd is a Thursday, there are exactly 4 Fridays, and January 1 is a Tuesday.

April 1 is a Monday.

Solution: There are 30 days in April, 30 7=4 (weeks) ......2 (days), because, in April, there are 4 Wednesdays and 5 Tuesdays, therefore, April 30 is a Tuesday, therefore, April 1 is a Monday.

A: April 1 is a Monday.

There are 30 days in April.

30 7 = 4 weeks. 2 days in April with 4 Wednesdays and 5 Tuesdays.

April 30 is a Tuesday and April 1 is a Monday.

Five Tuesdays can be drawn that the last day of this April is Tuesday.

In the form of a drawing, April 1 is? Wednesday.

April 1 should be a Saturday.

Analysis: 1, there are only 30 days in April, and there are 7 days in a week.

2. There are 5 Sundays in April, and the 1st is not a Sunday.

3. Assuming that the 30th is a Sunday, then it can be concluded that the 23rd, 16th, 9th, and 2nd are also Sundays.

4, then the 1st is Saturday.

5. If the 1st is Monday, Tuesday, Wednesday, and Thursday, the question conditions are not met.

7, so the final answer is Saturday.

There are 29 days in February in leap years

29 7 = 4 (Raid Kai Zhou)....1 (day), 4+1=5 (mu Zen coarse week);

Therefore, in leap years, there are a maximum of 5 Sundays in February;

So the original title is wrong

So the answer is: