The total power of 450KW is needed with how many square mm3 2 cables, and the total power of 600KW i

What is the nature of the load? Is it civil or industrial? It's hard to estimate yet. If it is industrial electricity, use 380V voltage to supply power, it is recommended to take the coefficient at the same time, do not know the specific situation, take a higher insurance point), power factor to take. Then the calculated power is:

p=400*

The full-load current is:

i=292/

According to the principle of conductor selection, 522*13=679(a) cable is selected.

2 (YJV -1000V 4*185+1*95) is two 185 cables, and it is recommended that 4 cores are 185, and the 5th core is 95 (due to single-phase load, the cross section of the neutral line and the phase line is equal).

If it is 10kV, the cable should be re-selected, but the calculation method is the same.

When 600kw, calculate and select according to the above method.

This is related to the voltage at both ends of the cable, the higher the voltage, the smaller the current, and the thinner the wire.

If it is 380V, the current in the cable is 1180A and 1579A respectively, the current is not large, if copper wire is used, the cross-sectional area of copper wire is about 1000 square millimeters. Copper wire with a diameter of about 35 mm is sufficient. If you use copper bars, you can use 10*100.

The total power is 380kw, Q: How big square of cable to use.

Hello dear, 380 kilowatt motor needs 150 square meters of copper wire single-phase three-phase? Three-phase, 380x1000 3 10000 = amps. That is, you can use square copper wire to field shirts.

3*150+1*70 The safe current carrying capacity of the large cross-section copper core wire per square is about, and the wire cross-section is required: S 1368 3 456 (square), and the cable specification can be selected

3*150+1*70。The safe current carrying capacity of the copper core cable is slightly larger than that of the aluminum core, and the selection of the cable can be one size smaller than the aluminum core cable, and the line loss is generally not considered, and the starting current of high-power electrical appliances should be considered. If all the 130kw total power is used at the peak, and there is a high-power electrical appliance with a cavity, you may wish to consider a larger cable, and the starting current of the general motor is 3-5 times of the current in normal use.

The total power of three-phase four-wire is 300kw, how many square cables do you need to use?

Hello dear, the total power of three-phase four-wire is 300kw, how many square cables do you need to use? For 300kw load, at least 240 square copper core cables and 360 square aluminum core cables should be selected. Calculation steps:

p=，i=p/(。p: slag rate; u：

Voltage; i: current; COS: Power factor, 1 for resistive load, and 1 for inductive (such as motor) load.

According to the wire current comparison table, at least 240 square meters of copper core wire should be selected for 300kw load. The 240 square copper core wire is laid with a safe interception flow of about 570a. I hope mine can help you like that; Once again, I wish you good health and a happy mood! 

Summary. 450kw requires 400 square meters of copper wire. According to p=have:i=p (calculated with three-phase mains, the power factor is taken.

450kw with how big the cable.

450kw requires 400 square meters of copper wire. According to p=have:i=p (calculated with three-phase mains, the power factor is taken.

Hope it helps you and I wish you a happy life!

The total power is 380kw, Q: How big square of cable to use.

Glad to be able to your questions. Need 3*150 square town tour + 1 70 square four-core cable. Current of 380kW load (in COS):

I p large cross-section copper core wire per flat Yu hidden pin side of the safe current carrying crack, wire cross-section: S 1368 3 456 (square) cable specifications can be selected: 3 * 150 + 1 * 70

120 square millimeters in two groups.

3-phase 380V, 400KW according to 800A current, 3 * 240 + 1 * 120mm square copper core wire safety current carrying capacity of about 400 A, if the line is not more than 100 meters, the load is not heavy, choose 2 3 * 240 + 1 * 120 square copper core cables in parallel: if the distance is long, the load is heavy, it is best to choose 2 3 * 300 + 1 * 150 square copper core cables in parallel.

3-phase 380V, 400KW according to 800A current, 3 * 240 + 1 * 120mm square copper core wire safety current carrying capacity of about 400 A, if the line is not more than 100 meters, the load is not heavy, choose 2 3 * 240 + 1 * 120 square copper core cables in parallel: if the distance is long, the load is heavy, it is best to choose 2 3 * 300 + 1 * 150 square copper core cables in parallel.

The total power is 380kw, Q: How big square of cable to use.

Dear, I am glad to answer for you: the total power of the answer is 380kw, ask: with a 150 square cable 380 hoop motor (low-voltage three-phase 380V) the current is about 760A, the current is relatively large, it is recommended to use the blind skin in the air (ambient temperature 40), within 150 meters:

VV or grinding YJV 3X240+120 copper core PVC or XLPE insulated PVC sheathed power cable, take two cables in parallel to meet the use requirements. Z4-400-32 380KW 400V 500rpm motor can drive a variety of different machinery, such as ventilators, compressors, water pumps, crushers, ball mills, cutting machine tools, transportation machinery and other equipment, which can be used as prime mover in coal mines, machinery industry, power plants and various industrial and mining enterprises.

Summary. Based on the total power of 235 kW and the voltage of 380 volts, the required current can be calculated using the following formula: Current (amps) = Total power (kW) Three-phase voltage (volts) 235000 380 385 amps Next, based on the relationship between the current and the cross-sectional area of the cable conductor wire, the required cable cross-sectional area can be estimated using the following **:

Conductor wire |Maximum allowable current |Recommended cable cross-sectional area ||35 mm² |240 a | mm² |50 mm² |300 a | mm² |70 mm² |380 a | mm² |95 mm² |480 a | mm² |120 mm² |600 a | mm² |150 mm² |720 a | mm² |185 mm² |900 a | mm² |Therefore, for circuits with a total power of 235 kW at 380V, copper cables with conductor cross-sections in the range of square millimeters (mm) are recommended. The specific cable selection and installation also need to be determined according to the actual situation and regulations.

Because only the total power is given, but no information such as voltage, dust fiber and current is given. In order to determine the size of the required cable, it is also necessary to know the parameters such as the rated electric power, air pressure and rated current of the cable, and then calculate the cross-sectional area of the cable according to these parameters.

380V copper cable.

According to the total power of 235 kW and the voltage of 380 volts, the required current can be calculated using the following formula: current (amps) = total power (kW) Three-phase voltage (volts) 235000 380 385 amps Next, according to the relationship between the current and the cross-sectional area of the cable conductor, the following ** can be used to estimate the required cable interception area: |Conductor wire |Maximum allowable current |Recommended cable cross-sectional area ||35 mm² |240 a | mm² |50 mm² |300 a | mm² |70 mm² |380 a | mm² |95 mm² |480 a | mm² |120 mm² |600 a | mm² |150 mm² |720 a | mm² |185 mm² |900 a | mm² |Therefore, for circuits with a total work ratio of 235 kW at 380V, copper cables with conductor cross-sectional areas in the square millimeter (mm) range are recommended.

The specific cable selection and installation also need to be determined according to the actual situation and regulations.

To determine the size of the required cable, the rated current capacity of the cable and the maximum current capacity required need to be considered. Here are the steps to calculate the required cable size for the three-phase 450kw:1

The voltage for calculating the three-phase voltage of the three-phase power supply is usually 380V, so we will use this value. 2.The formula for calculating the three-phase current three-phase power is:

p = 3 v i cos( ) where 3 is the square root of 3, v is the voltage hole, i is the current, is the power factor. Substituting 450 kW and 380 V into this formula, assuming that the power factor is, then the current i is: i = p 3 v cos( )450000 3 380 826 a3

The cable size is selected according to the International Electrotechnical Commission (IEC) standard, which has a current capacity of about A per square millimeter of cable. Therefore, the minimum cable area required can be calculated by dividing the required current: cable area = i = 826 551 square millimeters It should be noted that the above calculation results of bond infiltration are only estimates, and many factors should be considered in practical applications, such as cable length, temperature, etc.