My sister s question won t be solved.,If you know, let s talk about it.

Updated on educate 2024-06-06
30 answers
  1. Anonymous users2024-02-11

    That is to say, to take out and discrete, need one.

    So there's one that needs to be one.

    The number of the first group is a multiple of the number of the second group.

    If it's an elementary school, it's better not to use equations to solve it at every turn. This is not good for the cultivation of problem-solving ability!

  2. Anonymous users2024-02-10

    Let the first group have x and the second group have y, the sum of the total numbers of the first group is a, and the sum of the total numbers of the second group is b, according to the question, a x=, b y=, (a+b) x+y=

    Simplify. a=, b=, bring these two formulas into the third formula.

    Obtained. x/y=

    Answer: The number of the first group is a multiple of the number of the second group.

  3. Anonymous users2024-02-09

    Suppose the first group is x times the second group, and the second group is set to 1, then the ground group is x, and solving x is actually a weighting problem.

  4. Anonymous users2024-02-08

    6 times. Suppose a group of x and two groups of y, then.

    Solve the equation to obtain: x=6y

    So...

  5. Anonymous users2024-02-07

    Let the first group have x and the second group has y.

    Solution x y=

  6. Anonymous users2024-02-06

    Let the first group of numbers x, the second group of y, from the meaning of the problem (, solve this equation, get x=, so the number of the first group of numbers is a multiple of the number of the second set of numbers.

  7. Anonymous users2024-02-05

    The first group of x and the second group of y.

    That is, the item is transferred. x/y=

  8. Anonymous users2024-02-04

    Set: $ x for football, $ y for basketball.

    You have to pay 244 yuan to buy 5 soccer balls and 3 basketballs.

    Get: 5x+3y=244---

    You have to pay 278 yuan to buy 4 soccer balls and 6 basketballs.

    Get: 4x+6y=278---

    2. Get: 10x+6y=488---

    Get: 6x=210

    x=35 substituting x=35 to get: y=23

    A: $35 each for football and $23 for basketball.

  9. Anonymous users2024-02-03

    So many topics !! !!

    1.The circumference of the rectangle is equal to (length + width) multiplied by 2, and according to this formula you can solve the length of the rectangle.

    2.You didn't make this question clear, what is the third point on??

    In addition to this, the size of the other three is that the dot is on top) is larger, the dot is on top, and the size is larger.

    3.The answer is 8That's 12 out of 5. The number of the hail ridges is 12/5 multiplied by 10/3

    4.Because there is no common divisor for the three numbers, the least common multiple of these three numbers is 5 times 4 times 3 = 60

    5.The formula for the area of a triangle is base multiplied by height divided by 2So the base of this triangle is 4

    6。It should be 2, 40 is at 20

    7.The area of the trapezoid is the upper bottom + the lower bottom multiplied by the height divided by 2, so the area of the trapezoid is square meters.

    8.The length of the third side is 1 minus 3/10 and then 2/5, so it's 3/10, so this triangle is an isosceles triangle.

    9。I have been blinded by this.

    It should be 3+17+33+47

    10 Because this number is a multiple of 2, a should be even, and because it is a multiple of 3, 7+a+a should be divisible by 3, so a should be 4

    11 Because the area of the shaded part is 24, and the base of the part is known to be 8, the height is 6, so the trapezoidal area is (8+10) multiplied by 6 divided by 2=54

    The base of 12 is 5 and the height is 8, so the area is 5 times 8 divided by 2 = 20

    13.The height is 8.

    The upper and lower bases add up to 10, so 10 times the height divided by 2 equals 40. So the height is 8

    I'm exhausted. 、、

  10. Anonymous users2024-02-02

    1.The length of a cuboid is 8 cm, the width is 2 cm, and the height is 3 cm. The sum of the edges and lengths of this cuboid is (52) cm and the surface area is (92) cm2.

    2.The sum of the edges and lengths of a cuboid is 84 cm, and the sum of its length, width, and height is (21) cm.

    3.The average of the three numbers A, B, and C is that the number A is known, the number B is, and the number C is ( ).

  11. Anonymous users2024-02-01

    1.What is the length of a box with a circumference of 5dm and a width of?

    2.Put the ,,, four numbers in order from smallest to largest.

    This question is not correct (<

    3.Three-tenths of (8).

    4.What is the least common multiple of 5,3,4? (60)

    5.The area of a triangle is 12 square meters, the height is 6 meters, and its base is (4) meters.

    6.A triangular plot of land with a height of 6 meters and an area of 20 square meters harvests 40kg of rice, and the average rice per square meter of land is (2) kg.

    7.A trapezoidal sum of the upper and lower bottoms is, the height is 2m, and the area is ( ) square meters.

    8.Xiao Li used a 1m long iron window to enclose a triangle, and measured that one side of the triangle was three-tenths of a meter long, the other side was two-fifths of a meter long, and how many meters was the third side long? What kind of triangle is it? (Isosceles triangle.)

    9.Fill in the parentheses with different prime numbers to make the equation hold.

    10.The three-digit number 7aa is both a multiple of 2 and a multiple of 3, then a is (6).

    11.The trapezoidal shape is 8 cm long at the top and 10 cm at the bottom, and the area of the shaded part is 24 square centimeters. Find the area of the trapezoid. (This is missing a picture).

    12.The base of the triangle is 5 dm, the height is 3 dm longer than the base, and the area of this triangle is (20) square decimeters.

    13.The upper bottom of a trapezoid is 8cm, the area is 40 square centimeters, and the height is ( ) cm. (one condition less).

  12. Anonymous users2024-01-31

    (I can't see the circular dot mark of the two numbers in the middle.)

    m, right triangle.

    11. No picture?

    13. The conditions are not enough, and there is less bottoming.

  13. Anonymous users2024-01-30

    2. Wrong question.

    7: m, isosceles triangle.

    11: I can't see the picture.

    13: Can't figure it out. Haha, be entertained.

  14. Anonymous users2024-01-29

    You are good at math yourself, and you say that you are too lazy to think about it, so you should study hard! Your sister is too stupid to ask these questions。。 I'm speechless.

  15. Anonymous users2024-01-28

    My sister suddenly said: It suddenly rained in the sky, I took some scoops, and there was my clear face in it, and I took a sip with my face up, which was refreshing; --

  16. Anonymous users2024-01-27

    1. Last year's output value was A, and this year's output value increased by 12%.

    2. The peach tree is a, and the apple tree is 3a, 200% more

    3. The correct rate just now is 95%, which is obviously 94%, which is just high.

  17. Anonymous users2024-01-26

    1. Solution: There are X rows of large sofas and Y rows of small sofas.

    6x+4y=46 x+y=10

    x=3 y=7

    A: There are 3 rows of small sofas and 7 rows of small sofas.

    2,,Solution: 150 3=50

    A: A has 54 sheets, B has 52 sheets, and C has 44 sheets.

    Remember to give points ......Thank you ......

  18. Anonymous users2024-01-25

    There are 5 rows of large sofas and 4 rows of small sofas.

    A-4 = B - 2 = C + 6

    A + B + C = 150

    A = B + 2 C = B - 8

    B + 2 + B - 8 + B = 150

    B = 52 A = 54 C = 44

  19. Anonymous users2024-01-24

    x=1 y=10 Let's set it yourself.

    2.Equal to 50 at the same time, no one, and then you flip it over and there you have it...

  20. Anonymous users2024-01-23

    The addition of 10 square meters, its shape is also rectangular, and we know that one side of this rectangle is 2 meters.

    So we get the width of the original rectangle as 10 2 = 5 meters.

    So the total area is 5 (6+2) = 40 square meters.

  21. Anonymous users2024-01-22

    Area of the rectangle = length and width.

    When the length increases by 2 meters, the area increases by 2 width = 10, then width = 5

    So now the area of the garden = (6 + 2) 5 = 8 5 = 40 square meters.

  22. Anonymous users2024-01-21

    Solution: The original width of the nursery is x meters.

    6x=(6+2)x-10

    6x=8x-10

    2x=10x=5

    So now the area of this nursery is: 8x5=40m

  23. Anonymous users2024-01-20

    If the width of the rectangular nursery is x, there is.

    8x-6x=10

    2x=10x=5

    The current area is 8*5=40 square meters.

  24. Anonymous users2024-01-19

    When the campus was built, the length of the nursery was increased by 2 meters, and the width did not change.

    then the width is equal to 10 2 = 5 meters.

    Now the area of this nursery is s=(6+2)*5=40 square meters.

  25. Anonymous users2024-01-18

    This only increases the length, not the width, divides the increased area by 2 meters to get the width, 5 meters, and then multiplies 5 times 6 to get the area.

  26. Anonymous users2024-01-17

    Width = 10 2 = 5

    Area = (6 + 2) x 5 = 40 square meters.

    Please be prompt if it helps

  27. Anonymous users2024-01-16

    Set the width of the nursery to x

    2x=10x=5

    Now the area of the nursery is (6+2)*5=40

  28. Anonymous users2024-01-15

    Set the width to x (6+2)x-10=6x

    2x=10x=5 Length=8, Width=5

    Now the area of the nursery = 8 * 5 = 40m

  29. Anonymous users2024-01-14

    Set the width to x meters.

    6+2)x-10=6x

    2x=10x=5

    If you agree with my answer, please click the "Pick Satisfied" button below, thank you!

  30. Anonymous users2024-01-13

    A had 172 and B had 132, and if B had 1 person, and A would have 180 people.

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