Alas, who has math problems, oops, math problems are killing me

1. Point P in ab"in the focus of the straight line l.

2. It is equal to 60 degrees, and AC=AC can be obtained according to symmetry", angle cab = angle c"ab=30, so angular cac"=60, so triangle acc"is an equilateral triangle, thus getting.

3. Answer 2 is incorrect.

The volume ratio of a cylinder to a cone of contour is 3:1

So the volume of the cone is 64 (3-1)=32 m 3

The volume of a cylinder is 32*3=96 m3

sh-1/3sh=64

sh = 96 i.e. volume of the cylinder = 96

The volume of the cone1 3sh = 32

You don't know this, you can ask the teacher more, in fact, you have to do a few more of these questions after you encounter it, one question, one hundred questions.

Question 1: 8 8

Question 2: 23 28

Question 3: 4 and 3 5

Question 4: 12 7

Question 5: 221 12

Question 6: 5 16

Question 7: 3 Question 8:

8 out of 8

23/75 of 2

7/2316/5

As the title suggests, the triangle OAB is an isosceles right-angled three-argument lease angle.

Let oa=ob=x, with the spike Zhao clan Ming then ab=root number 2x, so, x+root number 2x+x=2*45

x=90 (2+root2)=45(2-root2), then ab=root2x=45(2-root2)*root2=90(root2-1).

The total distance is 90km, let oa be x, then ab is the root number (x) then 2x + root number (x) = 90, and the equation is solved.

According to the title, let the distance shield return of OA be X, then there is:

ob=x, with ab= 2x.

So there is: x+x+ 2x)=2*45

2+√2)x=90

x=45(2-√2)

So ab= 2x=45(2-2) 2=90(2-1).

Let the ab distance be 2a, and from the meaning of the question, we get 2a=(2+

oa+ab+oa=45*=90km

The known triangle OAB is an isosceles right triangle, so AB = root number 2OA = root number 2ob

Let oa=ob=x, then early rent ab=root number 2x

x+x+root:2x=90

The solution yields x=45 (2-root number 2).

ab = root number cover pure 2 * 45 (2 - root number 2) = 90 * (root number 2-1).

Let the OA distance be X

Then the distance of ob from the confession is x, and the distance of ab is x 2

x+x+x Bihong mu 2=2*45

Absolute tremor x 2 = 90 2-90