A simple equation, how to do the equation is the simplest

Updated on delicacies 2024-06-08
10 answers
  1. Anonymous users2024-02-11

    Segmented discussion: 0 points are -1, 3, and 3

    When k<-1 3, k=-7

    When -1 3=3 k= -7 is rounded.

    Therefore, k is -7 or 1

  2. Anonymous users2024-02-10

    k-3|/|3k+1|=1/2

    i.e. formed: 2|k-3|=|3k+1|

    According to the law of absolute values, the problem needs to be solved in three situations:

    1. When k>3.

    2|k-3|=|3k+1|2k-6=3k+1k=-7 (not hypothetical, discarded).

    2. When-1 32|k-3|=|3k+1|It is -2k+6=3k+1k=1 3, when k<-1 3

    2|k-3|=|3k+1|to -2k+6=-3k-1k=-7

  3. Anonymous users2024-02-09

    You've learned the number line! The strip is marked as the number line of k.

    First, mark the points where k is -1, 3, and 3 on the number line.

    There are three scenarios under the analysis.

    1,k<-1/3

    2(k-3)=-(3k+1)

    2(k-3)=3k+1

    I can't hit the number that is greater than or equal to, I'm sorry, you can add it yourself!

  4. Anonymous users2024-02-08

    Here are some simple steps to solve the equation:

    Step 1: Simplify the equation to a univariate linear equation

    For a quadratic equation of Yushan, the calculation can be simplified by turning it into a unary quadratic equation. For example, reduce the equation ax2 + bx + c = 0 to the form x 2 + px + q = 0.

    Step 2: Calculate the root of the equation

    For unary linear equations, the root of the equation can be calculated using the method of averaging. For more complex equations, you can use a solution formula or a computer program to calculate it.

    Step 3: Verify the solution

    After obtaining the solution of the equation, it needs to be substituted into the original equation for verification to ensure that the solution is correct.

    Here's an example of solving a quadratic equation:

    Example: Solve the equation x 2 + 5x - 6 = 0

    Solution: Reducing the equation to the shape of x 2 + px + q = 0, we get: (x + 6)(x - 1) = 0, so p = 5, q = 6.

    Because δ = p 2 - 4q = 49 > 0, there are two unequal real roots.

    Using the root finding formula x = p sqrt(p 2 - 4q)) 2, we get: x1 = 1, x2 = 6.

    Substituting the solution into the original equation to verify which one is correct, we can see that the solution is correct.

    In summary, the easiest way to solve an equation is to turn it into a one-dimensional equation and use a root-finding formula or computer program to calculate the root of the equation. After obtaining the solution, it needs to be substituted into the original equation for verification to ensure that the solution is correct.

  5. Anonymous users2024-02-07

    Simple equations mean that students are exposed to equations when they first learn them, which are generally simple unary equations, and they mainly learn the solution of equations and the application of simple equations.

    Simple equations. Algebraic: A letter or number connected by notation (addition, subtraction, multiplication and division).

    Equations: Equations with unknowns are called equations.

    Column equation: Concatenate two or more equal algebraic expressions with an equal sign.

    Column equation key problem: Represent the same number with more than two different algebraic formulas.

    Equation properties: add or subtract a number from both sides of the equation at the same time, and the equation does not change; Multiply or divide by a number (divided by 0) on both sides of the equation at the same time, and the equation does not change.

    Shift: Move a number or formula from one side of the equation to the other after changing the symbol;

    Shift rule: add and subtract first, multiply and divide after pure foci; Go to braces first, then middle brackets, and finally parentheses.

    Add and remove parentheses rule: In the equation that only adds and subtracts, if the parentheses are preceded by a "+" sign, the parentheses are added and removed, and the operation symbols in the parentheses remain unchanged; If the parentheses are preceded by a " " sign, add or remove the parentheses, and the operation symbols in the parentheses will be changed; If there is no "+" or "" before the number in parentheses, it is treated as having "+".

    Key issues of shifting: the nature of the equation, the rules of shifting, and the rules of adding and removing brackets.

    Steps to solve the equation: remove the denominator; remove parentheses; Transposition; merging similar items; Solving;

    System of equations: A set of equations consisting of several binary linear equations.

    Steps to solve a system of equations: elimination; Follow the steps of the unary linear equation.

    Methods of elimination: addition and subtraction; Substitution of the elimination element.

  6. Anonymous users2024-02-06

    There are generally two ways to solve a quadratic equation.

    One. Formulation. x^2-14x-24=0

    x-7)^2-83=0

    x-7= 83 under the root number

    x=7 + 83 under the root number or x=7 - 83 under the root number

    Substituting the value of this question into it gives x=7 + 83 under the root number or x=7 - 83 under the root number <>

  7. Anonymous users2024-02-05

    x^2-2x+3)^2-4(x^2-2x+3)-5=0x^2-2x+3-5)(x^2-2x+3+1)=0x^2-2x-2)(x^2-2x+4)=0x^2-2x+4=(x+1)^2+3>0

    Therefore, the finches in the hall are in charge of Zheng early.

    x^2-2x-2=0

    x=1±√3

  8. Anonymous users2024-02-04

    (x-1)²=169

    Let's start by discussing which numbers are squared to 169

    Obviously, 13 = 169

    And because the square can make the opposite of a number the same as the result of the square of the number, (-13) = 169

    So the x values in the question are 13+1 and -13+1

    for 14

  9. Anonymous users2024-02-03

    (x-1)^2=169

    x-1 = plus or minus 13

    x1=14 x2=-12

    Hope it helps. If you don't understand, you can ask me.

  10. Anonymous users2024-02-02

    The first time to the train station is x1, there is a formula: 30 (x1-15)=18 (x1+15), x1=60 minutes;

    Then find the distance of the train station: 18 (60+15)=1350 km;

    Finally, let its velocity be x2, and there is a formula: x2 (60-10)=1350, and x2=27 minutes.

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