Q: There are 32 sheep, slaughtered in 7 days, slaughtering single but not double, how to slaughter?

Analysis: The focus is on the principle of "killing singles and not killing doubles", but this principle does not limit how to kill, nor does it explain that "single and double" must refer to sheep.

Answer: 1. Thirty-two sheep, which can be understood as 3+10+2 15, 15 can be divided into seven odd numbers.

2. It is to number the sheep, kill the sheep on the first day, and then divide the remaining 16 in 6 days to divide it very well, (3 + 3 + 3 + 3 + 1 + 3 16).

3. Kill in seven days, and you can order the order number (week) according to the day of the week.

One, three, five, seven) kill, can also be by date (1st, 3rd......In short, as long as it is killed in seven days, it is also in line with the principle of killing a single and not a double.

4. It is to kill sheep across time, in any two days of seven days, in the early morning across zero o'clock to kill a sheep, this can be counted before zero o'clock to kill, can also be counted after zero o'clock killing, 3 + 3 + 3 + 3 + 3 + 8 (+1) + 8, this "1" and the previous "8" add up is singular, and the back of the "8" add is also singular.

There can be many answers, and the most important point is: this question tells us that a question can be solved more than once, and the standard answer is not the only answer.

Or, 1, 3, 5, 7, 9, 7 and one day without slaughtering sheep.

If it is to be slaughtered every day, the addition of seven odd numbers is still an odd number, and 32 is an even number, so there is no solution.

The following is a quote answer, hehe.

36 sheep, on the first day, kill the 1st 3 5 7 9 11 13 15 17 19 ......

Kill the odd number, and kill 18 of them.

On the second day, rearrange the remaining sheep and kill the 1st 3 5 7 9 ......Kill the singular, so that 9 more died.

On the third day, they rearranged again, killing 1 3 5 7 9, so that there were 5 less and 4 left.

On the 4th day, it was rearranged again, killing the 1st and 3rd

Two left. On the 5th day, kill the first one. There is one left.

On the 6th day, kill the last one.

The task was completed in 7 days.

Cut 31 on the first day and one on the seventh.

Summary. 36 sheep, 7 days to kill, please note that "only allowed to kill single is not allowed to kill double", the first day to kill 9, the third day 9, the fifth day 9, the seventh day 9, every 246 do not kill, sheep for the odd, the number of days should also be singular.

Thirty-six sheep, seven days to slaughter, slaughter single not double, how many sheep are slaughtered each?

36 sheep, 7 days to kill, please note that "only allowed to kill single is not allowed to kill double", the first day to kill 9, the third day 9, the fifth day 9, the seventh day 9, every 246 do not kill, sheep for the odd, the number of days should also be singular.

This question is wrong. If there is a correct answer, i.e. 36 = 7 odd sums. But the sum of 7 odd numbers is definitely odd, so there is no answer!

The original question was Zhuge Liang's clever arithmetic. Mathematically prove that there are: suppose 2a + 1 sheep are killed on the first day, 2b + 1 sheep are killed on the second day, and then 2c d e f g + 1;The sum is 2 (a+b+c+d+e+f+g)+7, you can get, the question is wrong.

Every day all the living sheep are lined up as follows; On the first day, the sheep with any four singular numbers, such as the 1st, 3rd, 5th, and 7th, were slaughtered, and there were 32 left; The next day, slaughter the 1st, 3rd, 5th, and 7th ,......29, 31, 16 left; On the third day, slaughter the 1st, 3rd, 5th, and 7th ,......13, 15, 8 left. On the fourth day, the 1st, 3rd, 5th, and 7th animals are slaughtered, and 4 are left. On the fifth day, the 1st and 3rd animals are slaughtered, and there are 2 left.

On the sixth day, the first one is slaughtered, and there is one left. On the seventh day, the remaining 1 is slaughtered.

Every day all the living sheep are lined up as follows; On the first day, the sheep with any four singular numbers, such as the 1st, 3rd, 5th, and 7th, were slaughtered, and there were 32 left; The next day, slaughter the 1st, 3rd, 5th, and 7th ,......29, 31, 16 left; On the third day, slaughter the 1st, 3rd, 5th, and 7th ,......13, 15, 8 left. On the fourth day, the 1st, 3rd, 5th, and 7th animals are slaughtered, and 4 are left. On the fifth day, the 1st and 3rd animals are slaughtered, and there are 2 left.

On the sixth day, the first one is slaughtered, and there is one left. On the seventh day, the remaining 1 is slaughtered.

36 sheep, 7 days to kill, please note that "only allowed to kill single is not allowed to kill double", the first day to kill 9, the third day 9, the fifth day 9, the seventh day 9, every 246 do not kill, sheep for the odd, the number of days should also be singular. Doesn't that qualify?

Summary. Hello, it means to divide 33 into three odd numbers, there are many total scores, one of them, such as 1 on the first day, 3 on the second day, and 29 on the third day.

33 double sheep, slaughter a single or not a double every day, slaughter in three days, how many are slaughtered each day?

Hello, it means to divide 33 into three odd numbers, there are many total scores, one of them, such as 1 on the first day, 3 on the second day, and 29 on the third day.

33 double sheep, that is, 66 sheep, slaughtered every day without slaughtering double, slaughtered in three days, how many are slaughtered every day?

The cardinality plus the cardinality is equal to an even number. The addition of three numbers equals an even number and there must be at least one even number, so your question is problematic.

1, slaughtering a single does not slaughter double" can be understood as slaughtering sheep on the day of the single number, and not slaughtering on the day of the double number.

1357 slaughtered sheep, 246 rested, slaughtered 9 in one day, exactly seven days 2, it can be understood that the number of sheep slaughtered is an odd number, 1, 3, 5, 7, 9, 11, slaughtered in six days, not in line with the topic.

So the answer is the first one.

If there is no solution, think about it yourself.

Analysis: Singular + singular is an even number Even number + even number is an even number of rough rounds, which is a singular number + even number.

If the 7 days are all singular, then the numbers of the 7 days add up to the singular, and 36 is the even number of Tongzao, so no.