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Anonymous users2024-02-111. Innumerable, first divided into 3 equilateral triangles, and then each equilateral triangle can be divided into three equilateral triangles.
2, (1) If A is right, it is not B. B, C, and D are all wrong, so it's not A, it's not B, it's D.
2) If B is right, then A is false, so D is also true3) If C is right, then D is also right.
4) If what D said is right, then one of A and C is right, so in summary, Ding took the first
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Anonymous users2024-02-101.Countless. As long as it's a square number.
2.Second. If there are too many reasons for reasoning, I won't write about it.
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Anonymous users2024-02-094 pcs. It was A and C who both became suspicious of B, and D was very objective, so B and D were excluded. C didn't respond to himself, and neither did anyone else. Then there is only A!!
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Anonymous users2024-02-08n more than one because the three sides are equal as long as n are equally divided.
If A is right, then B may or may not be right, and C is wrong if B is wrong, and D may be right.
If B is right, then A is false, so D is also true.
If C is right, then D is right.
If what Ding said is right, then one of A and C is right, so in summary, Ding took the first place
Note: The analysis is not necessarily correct, please point to the high finger, the little brother is ugly first).
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Anonymous users2024-02-07Solution: Simplification of the original formula =-(6a+18) (a -9)=-6(a+3) (a+3)(a-3).
6 3-a Because the value of this fraction is a positive integer, a 3
And 3-a should be a factor of 6, so 3-a is equal to 1, 2, 3 or 6. (The denominator is not 0, so (3-a)(3+a) cannot be equal to 0).
So a=0,1,2
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Anonymous users2024-02-061.Multiply both sides by x(x-1) at the same time to get:
3(x-1)+6x=x+m, simplify, get x=(m+3) 8, if x has a solution, first require x not to be equal to 0 and not equal to 1 (see the denominator of the original equation), that is, m is not equal to -3 and not equal to 5
2.Solve the second equation and get x=2
Bringing in Equation 1, we get 2m (m+1)-2=1
i.e. m=-1
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Anonymous users2024-02-051)c2) solves (x+4) x=3 to obtain x=2, and substitutes -2 into mx (m+1)-2 (x-1)=1 to solve m
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Anonymous users2024-02-04hg ad, proof:
If you set cad=x°, then bad=x°
be ac (known).
AEB = 90° (vertical definition).
MEA + EAM + AME=180° (triangle inner angle and definition) AME=90°-X° (equivalent substitution).
AOC = 90° (known).
CAO+ AOC+ OCA=180° (triangle inner angle and definition) ACO=90°-X° (equal substitution).
bho = 180°- hob- obh = 2x° (equal substitution) bhc = 180°- bho = 180°-2x° (equal substitution) hg bisect bhc (known).
bhg = 1 2 bhc = 90°-x° (definition of angular bisector) ame = bhg (equivalent substitution).
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Anonymous users2024-02-031, ac= (ao oc) = (16 9) = 5 abc area = ab*oc 2 = 10 4 2 = ac*be 2 = 5be 2, be = 8
2, ab=10, be=8, ae=6, e on the extension of AC, h on the extension of OC, CHB= cab
HG is vertically related to AD.
For the proof of question 2, you must draw a correct diagram according to my idea, from which it is easy to prove that AD is perpendicular to hg
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