Mathematical calculation problems. The second year of junior high school. Be more detailed, everyone

Updated on educate 2024-04-20
14 answers
  1. Anonymous users2024-02-08

    Root number 5 (root number 15-4 root number 3 5) = root number 3 (root number 1 + 2 root number 3) (3-root number 3) = 5 root number 3-3

    2 + root number 3) (2 - root number 3) = 1 (5 + 3 root number 2) square = 43 + 30 root number 2

    Root number 3 minus 1 point root number 2 = root number 3 - 1/2 root number 2 2 + root number 2/3 - root number 3 = 2 + 1/3 root number 6 - root number 3 10 root number 3 + 2 root number 7-4 root number 3 = 2 root number 7 + 6 root number 3 5 root number 12-7 root number 8 - root number 48 = 6 root number 3-14 root number 2

    Root number 8 - (3 root number 32-2 root number 18) = -4 root number 2 (5 + 2 root number 7) - (4 + root number 7) = 1 + root number 7

    2 + root number 5) (root number 5 of 3-2) = 6 root number 5-20

    3 + root number 7) (3 - root number 7) = 2

    3 + 2 root number 3) square = 21 + 12 root number 3

    root number 5 - root number 10) = -15

  2. Anonymous users2024-02-07

    Root number 3 minus 1 point root number 2,

    2 + 2/3 of the root number - 3 of the root number

    10 root number 3+2 root number 7-4 root number 3

    5 root number 12-7 root number 8 - root number 48

    Root number 8- (3 root number 32-2 root number 18).

    5+2 root number 7)-(4 + root number 7).

    2 + root number 5) (root number 3-2 of 5).

    3 + root number 7) (3-root number 7).

    3+2 of the root number 3).

    root number 5 - root number 10).

  3. Anonymous users2024-02-06

    What is this? Elementary school students don't understand, it's really a little hard to understand.

  4. Anonymous users2024-02-05

    1. Find the square root and the square root of the arithmetic number of the following numbers.

    1: 10 4 square root 10, arithmetic square root 10 square root number 81 square root 9, arithmetic square root 9

    Root number 13 2-13 2 square root 0, arithmetic square root 02 root number 1 100 = 1 10

    Root number|-3 of 1 16|= root number 3) 4

    Positive and negative root number 25 2-12 2= 3 (root number 39) 3 from the title: x+3y-5 0,|2x-y-3|0, then:

    x+3y-5=(2x-y-3)²=0

    Introduce 4y-x-2=0;3y=5-x, so x+y=3

  5. Anonymous users2024-02-04

    1. Solution: There are x players.

    x(x-1)/2=28

    Solution: x=8Answer: There are 8 players.

    2. According to the same length of sagging, it can be seen that the length of the tablecloth is also 3 feet more than the width, and the width of the tablecloth is x feet, and the length is (x+3) feet.

    x(x+3)=2*6*3

    x^2+3x=36

    x^2+3x-36=0

    Solution: x approx. =

    So x+3=

    Answer: The length of the tablecloth is a ruler, and the width is a ruler.

    3. When the line is arranged in a square, the number of people on one side is x.

    x 2+100=(x 2+13) 2-29 solves: x=20

    So x 2+100-500 (people).

    A: There are 500 students in total.

    o(∩_o~

  6. Anonymous users2024-02-03

    1: If there are x people in the grade participating in the competition, then.

    x(x-1)=28x2

    x²-x=56

    x²-x-56=0

    x-8)(x+7)=0

    So x=8 or -7 -7 doesn't fit the topic and go so there are 8 players.

  7. Anonymous users2024-02-02

    1. There are x players, and each player takes the initiative to invite any other player to play all the games, which is x(x-1), but each player who takes the initiative to invite once will be invited once in turn, so every two people are counted twice in the game, then the real number of times should be 1 2*x(x-1)=28 receive x=8

    2. If the length of the tablecloth droop is x, the area of the tablecloth is (x+6)*(x+3), according to the title, (x+6)*(x+3)=2*6*3, and the solution is about equal to the ruler), then the length and width of the tablecloth are and.

    3. Let the number of people on the edge of the square at the beginning be x, then there is x 2+100=(x 2+13) 2-29, and the solution is x=20, then the total number of people is 20 2+100=500.

  8. Anonymous users2024-02-01

    1.(1) Let the annual profit growth rate of the company be x

    1500×(1+x)²=2160

    Then solve the equation to find x

    The profit in 2007 was 1500 (1+x).

    2) The profit in 2009 was 2160 (1+x) (the specific answer is calculated by yourself).

    2.Let the price of this table lamp **** be x

    40-30+x)(600-10x)=10000 solution x, the table lamp is priced at (40+x), and the table lamp (600-10x) should be entered

  9. Anonymous users2024-01-31

    Let the growth rate x

    1500(1+x)(1+x)=2160

    x = profit in 2007 = 1500 (1 + x) = profit in 18002009 = 2160 (1 + x) = 2592 set price for x, profit x - 30

    Sales volume = 600 - (x-40) * 10 = 1000 - 10 x total profit = (x - 30) (1000 - 10 x) > = 10000 solution inequality -10 (x - 30) (x - 100) > = 10000 when x = 65 maximum, sales 350 profit 22750 x 2-130x + 2000 < = 0

    。<=x<= 。。It's all within that.

  10. Anonymous users2024-01-30

    (1) The annual growth rate of each year is a

    So the profit of 2008 is.

    1500x(1+a)x(1+a)=2160 gives a=

    So the profit in 2007 was 1500x (1 + million yuan) (2), and the profit in 2009 was 2160x (1 + million yuan) 2

  11. Anonymous users2024-01-29

    Let the annual growth rate be x(x>=0), and the following equation can be obtained according to the title:

    1500*(1+x)2=2160

    x=then let the profit in 2007 be y, and you can get:

    y=1500×(1+

    2009 profit z=2160 (1+.)

  12. Anonymous users2024-01-28

    ACD = D obtained by AC DE

    And because Qin Zheng acd= b

    So d= b – 1.

    Because the number refers to ACB + ACD + potato first match D = 180 degrees E + D + DCE = 180 degrees and ACD = D

    So acb= e – 2 formula.

    So a= dce – 3 formula.

    ASA certified.

  13. Anonymous users2024-01-27

    1 4 * 3 + 9 * 6-2 * 2 * 3 * root number 6 * root number 3 = 66-36 * root number 2

    2 Up and down at the same time (root number 5 + 2) to get (root number 10 + 2 * root number 2) (5-4) = root number 10 + 2 * root number 2

  14. Anonymous users2024-01-26

    1.Factoring in the range of real numbers: x 5 (x+ 5)(x-5) (without procedure) 2

    Calculation: Knowing the root number of x 5 2, find the value of one-half of x x (process) x 1 x =(x+1 x) -2 by x= 5-2 to get 1 x= 5+2 x 1 x =(x+1 x) -2=( 5-2+ 5+2) -2=5-2=33Solve the equation:

    4x 15 (process) Is this the equation? process) first calculate the discriminant formula = (-2) -4 4 (-1) = 20 x=(2 20) 8x1=(1+ 5) 4 , x2=(1- 5) 4 5Knowing that a, b, and c are the three sides of abc, and that there are two equal real roots of a quadratic quadratic equation for x, x - (b-c)x=(a-b)(b-c)=0 (b-c)(a-c)=0 (b-c)(a-c)=0 (b-c)(a-c)=0 (b-c)(a-c)=0 (b-c)(a-c)=0 b=c or a=c The shape of ABC is an isosceles triangle.

Related questions
18 answers2024-04-20

Buy this to teach and learn. It's full of good topics.

7 answers2024-04-20

Original = [(-6 -4)-(15 -8)] [-2-(-7 -16)]

3 2-15 8] [-2 -7 16] Simplification. >>>More

11 answers2024-04-20

The voltage at both ends of a certain resistor is 10V

The passing current is 5A >>>More

12 answers2024-04-20

1. Calculate ** data.

In word, ** is often used to enter numbers and to calculate, we all know that it is faster to calculate values in excel, in fact, it is also very convenient to calculate data in word. >>>More