Which one is a red ball and the other is a red ball

Updated on physical education 2024-06-15
11 answers
  1. Anonymous users2024-02-12

    That's an inexplicable question.

  2. Anonymous users2024-02-11

    Summary. Hello, glad to answer for you.

    The 6 red ball numbers of the two-color ball are arranged in order from smallest to largest, and we call the first red ball Red 1, the second red ball Red 2, and so on. This little method to be introduced is calculated using the red 3 (the third red ball).

    Step: a=red3+4;

    b = red 3 + 4 + 3;

    Take the mantissa of a and b as the reference number of the red tail in the next period.

    For example, the Double Color Ball 2016046 Bonus Ball is 07 20 25 26 27 30;

    Red 3 = 25;

    a=25+4=29, take the mantissa 9;

    b = 25 + 4 + 3 = 32, take the mantissa 2;

    In summary, the red tail of the next period can be considered between 9 and 2.

    How to set a red ball.

    Hello, glad to answer for you. The 6 red ball numbers of the two-color ball are arranged in order from smallest to largest, and we call the first red ball as Red 1, the second one as Red 2, and so on. A small method to be introduced is to use the red 3 (the third red ball) to calculate.

    The Double Color Ball 2016046 Red Ball is 07 20 25 26 27 30;Red 3 = 25;a=25+4=29, take the mantissa 9; b = 25 + 4 + 3 = 32, take the mantissa 2; In summary, the red tail of the next period can be considered between 9 and 2.

    May mine help you. I wish you a happy life and all the best!

  3. Anonymous users2024-02-10

    The first six numbers correspond to the red ball, and the next number corresponds to the blue ball. According to the comparison of the results of the two-color ball lottery to see if Lu You has won the lottery.

    The Double Colour Ball betting area is divided into a red ball number area, with the red ball number area consisting of 33 numbers from 1 to 33 and the blue ball number area consisting of 1-16 numbers making up of 1 to 16 total 16 numbers. When betting, choose 6 red ball numbers and 1 blue ball number to form a single bet, and the amount of each bet is RMB 2.

    Winning rules for each prize:

    First prize: The betting numbers are all the same as the current lottery numbers (the order is not limited, the same below), that is, the winning lottery.

    Second Prize: The bet number is the same as the 6 red ball numbers in the current draw, which means winning the prize.

    Third Prize: The betting number is the same as any 5 red ball numbers and 1 blue ball number in the current early Yuhuai lottery number, that is, the lottery is won.

    Fourth Prize: The bet number is the same as any 5 red ball numbers in the current draw, or the same as any 4 red ball numbers and 1 blue ball number.

    Fifth Prize: The bet number is the same as any 4 red ball numbers in the current draw, or the same as any 3 red ball numbers and 1 blue ball number, which means winning the prize.

    Sixth Prize: The bet number is the same as 1 blue ball number in the current draw, that is, the winning prize.

    The above content reference: China Welfare Lottery - China Welfare Lottery "Double Color Ball" game rules.

  4. Anonymous users2024-02-09

    White is 50 more than red, that is, the red ball is 50 less than the white ball, and the red ball is 50 more than the white 1 3, that is, the red ball is 3 times more than the white ball 150, the red ball is 2 times equal to 150 + 50 = 200, and the red ball is 200 2 = 100

  5. Anonymous users2024-02-08

    Classical generalization: The method of taking 2 arbitrary balls is c(4,2)=6

    One of the two balls is the width of the red ball, and the other is not the normal destruction of the red ball, and the method is c(2,1)c(2,1)=4

    The probability of two balls, one of which is a red ball and the other is not a red ball is 4 6 = 2 3

  6. Anonymous users2024-02-07

    At least one black ball" and "both black balls" can be judged at the same time, so the two events in A are not mutually exclusive events;

    "There is exactly one black ball" and "exactly two black balls" cannot occur at the same time, but they can not occur at the same time, so the two events in b are mutually exclusive but not opposite;

    At least one black ball" and "at least one red ball" can occur at the same time, so the two guessing events in c are not mutually exclusive events;

    At least one black ball" and "both red balls" are opposites Hence the selection: b

  7. Anonymous users2024-02-06

    Choosing the Right Red Ball Method:

    Divide the 33 red ball numbers into 11 zones of 3 numbers each. According to the normal lottery, each district opens a number to know the eggplant, then at least 5 district numbers can be excluded, that is to say, 15 numbers can be excluded, and the red ball number becomes 18 to 6. Sometimes it is also possible to exclude numbers from 6 districts, or more.

    But there are many partitions, and there is a problem with traveling. I don't know which district to exclude. If you make the wrong exclusion, you may not win the prize.

    If you divide the 33 red ball numbers into 3 zones, each zone has 11 numbers. In this way, the selection range is too large, which is not conducive to the selection of numbers.

    In short, it's not good to have more partitions, and it's not good to have fewer partitions.

    I divide the red ball number into 6 zones. Zone 5 and Zone 6.

    This partition is more symmetrical, which is convenient for choosing numbers. You can observe the drawn numbers in recent draws, and generally rarely draw numbers from 2 districts and numbers from 6 districts, so you can ignore these two situations for the time being. The number of opening 1 district has not been opened for the time being, so it can be ignored.

  8. Anonymous users2024-02-05

    Let the red ball be x and the white ball be y;

    then the yellow ball is 87-x-y;

    x-3=2y=(87-x-y)/2;

    x-3=2y

    87-x-y)/2=2y;

    x-2y=3

    x+5y=87;

    7y=84;

    y=12;So red ball x=27

    There are 48 yellow balls and 12 white balls.

    I don't know if the fourth grade of equations has been learned)

  9. Anonymous users2024-02-04

    Solution: Equal number: (87-3) (1+2+1 2)=84*2 7=24

    So red balls: 24 + 3 = 27. White balls: 24 2 = 12; Yellow balls: 24*2=48.

  10. Anonymous users2024-02-03

    Let the white ball be 1 part, then the red ball minus 3 is 2 parts, the yellow ball is 4 parts, one part (87 3) 7=12, the red ball 12x2+3 27, the white ball 12, the yellow ball 12x4 48

  11. Anonymous users2024-02-02

    If there are x red balls, then there are x+50 white balls, and according to the title, x-(x+50) 3=50 is obtained

    x=100x+50=150

    x+x+50=250

    A: There are 250 red and white balls.

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