Class A physical education examination, the attainment rate is 88, of which 24 students did not meet

For the mathematical "%", the whole is represented by "1" (i.e. 100%).

According to your question: the attainment rate is 88%, the non-attainment rate is 1-88%=12%, and the number of non-attainment students is 24, which means: Total number of students 12% (non-attainment rate) = non-attainment of students (i.e. 24).

Total number of students = students who do not meet the standard (i.e. 24) 12% (failure rate) Total number of students = 24 12% = 200.

Students who meet the standards = Achievement rate (88%) Total number of students (200) = 176 or: the total number of students 200 minus the 24 students who do not meet the standards is the number of students who meet the standards.

According to your question: the attainment rate is 88%, the non-attainment rate is 1-88% = 12%, and the number of non-attained students is 24, which means that the total number of students 12% (non-attainment rate) = non-attainment rate of students (i.e. 24) = the total number of attainments.

Total number of students = students who do not meet the standard (i.e. 24) 12% (failure rate) Total number of students = 24 12% = 200.

Students who meet the standards = Achievement rate (88%) Total number of students (200) = 176 or: the total number of students 200 minus the 24 students who do not meet the standards is the number of students who meet the standards.

What I think, not necessarily right. 24 12 per cent gives the total number of people, and the total number of people 200 minus the 24 people who did not meet the standard is the number of people who meet the standard.

The compliance rate is 88%. The non-compliance rate is 1-88%=12%.

corresponds to the number of people who do not meet the standard24...

24 12% = 200 people.

Thank you for your points.

He said it was wrong, it should be 24 divided by <1-88%> times 88% = the number of people who meet the standard, 1-88% is the failure rate, 24 divided by the failure rate is the total number of people, and the total number of people multiplied by the standard rate is the number of people who meet the standard.

Achievement rate = number of compliance standards Total number.

Children still listen to the teacher's lectures in class, and your problem shows that you didn't pay attention to the class in class, which is really the same as I did back then. If you still can't, just buy a few textbooks, which are all very detailed. It's OK to take that self-study

Fractional equations:

Solution: Set up class A x people, class B (110-x) people, according to the title, get:

48/x-45/110-x=

Solution x=50

Test: When x=50, x(110-x)≠0 x=50 is the solution of the original fractional equation.

Pass rate: 48 50 = 96%.

Answer: --Binary Linear Equation:

Solution: Set up class A x people, class B y people, according to the title, get:

48/x-54/y=

The solution is x=50 and y=60

Pass rate: 48 50 = 96%.

A: --

The pass rate of Class A is 96%, and the class size is 50, and 48 people are qualified.

The pass rate of Class B is 75%, and the whole class is 60 people, and 45 people are qualified.

Hope it helps. The general column formula can be calculated.

Solution: There are two classes of A and B, each with x and y people.

x+y=110

48/x-45/y=

The solution is x=50 and y=60

The pass rate of A is: 48 50 = 96%.

There are x people in class A, so class B is 95-x people.

x*40%+(95-x)*78%=95*60%

The solution is x=45, that is, there are 45 people in class A, so class B is 95-45=50 people.

Class A pass rate:

Class B is subdued by this bush rate:

The pass rate of the two classes is poor. Lack of cherry blossoms.

Solution: If there are x people in class A, the number of people in class A who meet the standard is 95% x.

If there are people in class B, the number of people in class B who meet the standard is 93% y.

The ratio of the number of people who meet the standards of the two classes of A and B is 95%x:93%y, and 95x:93y is obtained after simplification.

The idea of solving the problem should probably be: there are x people in class A and y people in class B, (there seems to be a lack of relationship or condition here, if the same).

Columnable equations: (48 x)%-45 x)%=5% to solve, get: (48 x)-(45 x)=5 100 --48-45) x=5 100 --3 x=5 100 --5x=300

x=60 people;

According to the title, then: (48 60)%=80%.

A: The pass rate of Class A is 80%, and the pass rate of Class B is 75%.

Eighty percent, provided that both classes have the same size.

48 Number of people per class) - (45 Number of people per class) = 5% = Number of people per class = 60 Then the number of qualified students in class A = 48 60 = 80%.

x=45

You replace the percentages with and and the multiplication, and then multiply it with the re-shift and merge the same terms ( solution x = 45

Fake or not.,One-dimensional equations.,What grade are you?。。。

Dismiss Class A x people.

40%x+78%×（95-x）=95×60%78%x-40%x=

x=4595-45=50 people.

A: There are 45 students in Class A and 50 students in Class B.

There are x people in class A and y people in class B.

x+y=95

40%x+yx78%=95x60%

x=45 y=50