Math Problems Reward for getting it right! Math problems, I don t understand, ask for a solution,

2:1/2*4√2*√30=8√15(cm)^23:1+2+3+4+5+6+7•••100=a,100+99+……1=a, so 2a=101*100, so a=5050, so.

5: a 2 + b 2 = c 2), so the length of the other side is 36: a = 3 + 2, b = 3- 2, so ab = 7, a + b = 6, so a 2b + ab 2 = ab (a + b) = 6 * 7 = 42

7:7 - The opposite of root number 3 is -7 + 3

8: The cubic root of the root number 64 = 2, the square root is =2 2 or -2 29: The reciprocal of the root number 3 is =1 3 = 3 3

10: a=0, b is the largest negative integer =-1, c is the real number with the smallest absolute value = 0, so a-b + c = 1

1.Root number 2

Root number 155Root number 41

7.Root No. 3 7

Plus or minus 2 root number 2

Root of the Divide No. 3

1 root number 22 4 times root number 15

4 root number 10

5 root number 41

7 root number 3 minus 7

8 2 plus or minus 2 times the root number 2

9 root number 3 3

2:8√15(cm)^2

5:a 2 + b 2 = c 2), so the opposite of the other side of the length 37:7 - root number 3 is -7 + 3

8: The cubic root of the root number 64 = 2, the square root is =2 2 or -2 29: The reciprocal of the root number 3 is =1 3 = 3 3

10: a=0, b is the largest negative integer =-1, c is the real number with the smallest absolute value = 0, so a-b + c = 1

1, root number 2 cm.

2, 60 roots No. 2 square centimeters.

5. The root number is 41 cm.

7, root number 3 -7

8, 2, plus or minus 2, root number 2

9, the root of the third number three.

1.With an average of 12 units per school, 3 units will be transferred from A to School B, and 2 units will be transferred from C to School B. The total number of units is 5.

2.The average number of units per school is 10. D to E - 6 units, for a total of 12 units.

1. Adjust (3) computers from A to B school; The total number of computers transferred is (5).

2. From D calibration (-6) computers to E school; The total number of computers transferred is (12).

1.You can adjust (3) computers from A to B school; The total number of computers transferred is (5).

2.You can calibrate (-4) computers from D to E school; The total number of computers mobilized is (10).

The total price of the goods purchased by Xiao Li twice was 828 yuan;

Then Xiao Zhang needs to pay yuan.

For the sake of such a hard typing, give a recommendation.

Xiao Zhang pays yuan.

Xiao Li paid 828 yuan.

I can do the math for you.

Don't know how big the reward is?

1. Set the bottom angle x and the top angle y

2x+y=180

y/x=3/5

solution x = 900 13, y = 540 13

2. If the original copper is 2x, then the zinc is 3x

2x+120+3x+40=660

x = 100 now copper than zinc = (200 + 120) (300 + 40) = 16 173, set length 4x, width 3x, height 2x

4x+3x+2x）*4=216

x=6 Length 24, width 18, height 12

Surface area = (24 * 18 + 24 * 12 + 18 * 12) * 2 = 1872 cm2 volume = 24 * 18 * 12 = 5184 cm3

The first one uses the squared difference formula.

Root No. 3 + Root No. Shishou 2 + Root No. 3 - Root No. 2) (Root No. 3 + Root No. 3 + Root No. 2) = 2 Root No. 3 2 Root No. 2 = 4 Root No. 6

The latter ones are calculated to be 3 No. 2-4 thirds No. 3

It's all an approximate of 12, so you can just finish sawing, and the rest is calculated by volume.

12*12*12) (2*3*1)=288 block surface area = (2*3+1*3+1*2)*2=22

It's very simple, if you encounter such a problem in the future, you mainly use equations to solve it, for example, we set the length x, the width y, and the height z.

After that, 2x+3y+z 12 is used to calculate the job search.

In fact, this question is more troublesome, and you need to assume that for example, the combination of length and width, the combination of width and height, or the combination of length and height usually have to list 3 groups of two programs to solve, it is recommended to draw a diagram yourself, which is relatively simple.