The design scale of the municipal sewage treatment plant is 61000m d and the coefficient of change i

I'm in the water treatment business, so I'll give you a general idea first, and then contact me if you're interested:

The process is approximately: grid + regulating pool + lifting pump + A O pool (rear MBR device) + outlet pool + outlet lifting pump.

If it is domestic sewage (combined sewage and fecal flow), a septic tank needs to be placed in front of the screen.

Sludge needs to build a sludge treatment room, with a plate and frame filter press.

Also: Your water table is -2m, but your inlet elevation is: , won't it destroy the aquifer?

This shouldn't be a design, just a calculation problem, find an environmental worker to help you do it, it's full of trouble, you have to check the parameters, and find the formula against the textbook (water pollution control engineering and the like). The key is the calculation of the primary sedimentation tank (except SS), the secondary treatment is just to say that the index of the inlet water and the effluent can be written, and the flow chart is easy to do and find a treatment plant to simplify.

nnd This is another college graduation project.

Let's bs first, although I was like this back then, quack.

It's very simple, the quality of the raw water is so good, it's OK to deal with it casually

Quietly tell you to go online to find a smaller municipal sewage plant in the city.,Do it again.,It's super simple wow.。。 A few pools came out as soon as they were swinged.

Two units are set up in parallel: the width is 1m, the gap is 5mm, and the height is determined with the water depth and the form of the structure (the rotary tooth rake type or reverse fishing type is determined according to the specific facility situation). The power should be selected according to the specific manufacturer's product. The grid canal port is provided with a gate for maintenance.

Assuming that the amount of screening per 1000 m3 of sewage is m3, then: the amount of screening is 30000 1000=30*

Total coefficient of change kz: The ratio of the maximum daily maximum sewage volume to the average daily average sewage volume is called the total coefficient of change.

Generally, it is found empirically based on the flow rate, and there is an empirical formula, which is a calculation formula summarized by comprehensive analysis on the basis of many years of observation data. Reflects the relationship between the total coefficient of change and the average flow rate

q< kz=

q average5q average 》1000 kz=

Summary. Hello dear and happy to serve you<>

The designed wastewater treatment volume is 200m3 d, and kz is; 1.The design flow rate Q = 20000m d, select the flow coefficient k, = then: the maximum flow rate q = the number of gaps in the grid (set:

The water depth in front of the grid h=, the flow velocity through the grid v=, the width of the grid bar gap b =, the inclination angle of the grid A = 60 °, then: the number of grid bar clearances n = Q1 sin A = 60 ° = take n = 45) the width of the grid groove (b) set: the width of the grid bar S = then:

b = s (n-1) + bn = the length of the inlet channel is set as: the width of the inlet channel b, =, and the angle of the inlet channel is a, = 20 ° (the flow velocity before the inlet channel is: l, = tan a- 2 tan 20 ° 5.)

The length of the narrowing part of the junction between the grid and the outlet channel (l2) l2 = 11 = thank you for your trust, the above is my reply, I hope it can help you, I wish you a happy life. <>

What is the design water volume of wastewater treatment at 200m3 d, kz?

Hello dear and happy to serve you<>

The designed wastewater treatment volume is 200m3 d, and kz is; 1.The design flow rate Q = 20000m d, select the flow coefficient k, = then: Hengpai Luxian Tong maximum flow Q = the number of gaps in the grid (set:

The water depth in front of the grid h=, the flow velocity through the grid v=, the width of the grid bar gap b =, the inclination angle of the grid A = 60 °, then: the number of grid bar clearances n = Q1 The belt sin A = 60 ° = take n = 45) The width of the grid groove (b) is set as: the width of the grid bar S = then:

b = s (n-1) + bn = the length of the inlet channel is set as: the width of the inlet channel b, =, and the angle of the inlet channel is a, = 20 ° (the flow velocity before the inlet channel is: l, = tan a- 2 tan 20 ° 5.)

The length of the narrowing part of the junction between the grid and the outlet channel (l2) l2 = 11 = thank you for your trust, the above is my reply, I hope it can help you, I wish you a happy life. <>

Because the task book only gives 1 amount of water, it seems that kd and kh can't be calculated, can it be directly considered equal?

Hello dear and happy to serve you<>

OK.

Summary. Hello dear<>

The design scale of a municipal sewage plant is 100000m3 d, the design influent water quality SS=200mg L, BOD=250mg L, the sedimentation efficiency of the primary sedimentation tank SS is 55%, the moisture content of the primary sedimentation sludge water is 97%, and the moisture content is reduced to 80% after dewatering. If the sludge density is calculated as 1000kg m3, the daily output of dewatered sludge in the primary sedimentation tank of the sewage plant should be: b

The design scale of a municipal sewage plant is 100000m3 d, the design inlet water quality ss=200mg L, BOD=250mg L, the sedimentation efficiency of the primary sedimentation tank SS is 55%, the moisture content of the primary sedimentation and discharge muddy water is 97%, and the moisture content is reduced to 80% after lifting and dewatering. If the sludge density is calculated as 1000kg m3, which of the following should be the daily output of dewatered sludge in the primary sedimentation tank of the sewage plant?

a 55m3/d

bc 100m3/d

The design scale of a municipal sewage plant is 100000m3 d, the design influent water quality SS=200mg L, BOD=250mg L, the sedimentation efficiency of the primary sedimentation tank SS is 55%, the moisture content of the primary sedimentation sludge water is 97%, and the moisture content is reduced to 80% after lifting and dewatering. If the sludge density is calculated as 1000kg m3, which of the following should be the daily output of dewatered sludge in the primary sedimentation tank of the sewage plant?

dc 100m3/d

ba 55m3/d