High school chemistry, thank you for the detailed explanation, 2

Add aluminum chloride solution dropwise to sodium hydroxide solution, at first aluminum chloride is insufficient, aluminum ions and hydroxide ions react 1:4:

Al3+ +4OH- === ALO2- +2H2O, no precipitation;

**The concentration of sodium hydroxide solution and aluminum chloride solution is not given, so the specific value cannot be calculated, and the concentration is set to C1 and C2 here, and the landlord can substitute the amount given in the question.

When all the hydroxide ions in the solution are exhausted, precipitation begins to appear in the solution, and the volume of the dropping aluminum chloride solution v1 = 10c1 4c2 is dropped

The ionic reaction that takes place is Al3+ +3AlO2- +6H2O === 4Al(OH)3 (precipitation).

When the ALO2- generated in the first step of the reaction is fully reacted, the amount of precipitated is maximized, and the volume of the aluminum chloride solution is consumed.

v2=(10c1/4c2)/3

Therefore, when the amount of precipitation is the largest, the volume of the total droplet of aluminum chloride solution is V1+V2=10C1 3C2

Here I don't know the concentration, if the concentration is the same, then al3++4oh-=alo2-+2h2o; Then 1 4 10 = 2,5mlalcl3;

If the precipitation is maximum, al3++3oh-=al(oh)3 requires 10 3=;

The ionic equation is Al3++4OH-=ALO2-+2H2O;

3alo2-+al3++6h2o=4al(oh)3↓；

If you have any questions, please ask

The concentration did not give. Can't calculate.

According to the dissolution of n in m, it can be preliminarily determined that m is water (the most common solvent), and then it is known that it is 10 electrons, and the aqueous solution of n is alkaline, so n is ammonia (the only alkaline gas in middle school chemistry).

It is known that x is ammonium and k is hydroxide.

It is inferred from y to be hydronium ions.

Z ions plus K (alkali) to form a precipitate, K excess precipitation dissolves, and Y (acid) is also dissolved, so Z is aluminum ions (precipitated aluminum hydroxide is a typical amphoteric substance).

h3o+al3++3nh3•h2o = al(oh)3↓+3nh4+

Since it is an octahedral complex, it means that the coordination number is 6.

CoClm·nnh3 can be written as [Co(NH3)NCL6-N]CLM+N-6.

Ag+ +Cl- = AgCl, 1mol complex reacts with Agno3 solution to form 1MolagCl precipitate, and the number of Cl- in the outside is 1, and the inner boundary is [Co(NH3)NCl6-N]+ positive monovalent cation.

That is: m + n - 6 = 1, +3 + 1) (6-n) = +1, we can see that n = 4, m = 3.

From 1 mol complex to generate 1 mol agcl knows that 1 mol complex ionizes 1 mol cl- that is, the ligand ion shows +1 valence, and there is a cl- outside, and because of CO3+, there are two Cl- in the complex ion CoClm-1·nnH3+, and because it is a regular octahedron, there are 6 vertices, so n=6-2=4.

(The S in the reaction product is actually S8) Find: Under the standard condition, mix A liter H2S with B liter SO2 for the above S8, each S has two bonds, and each S-S bond is connected to two S atoms, so there are a total of S-S bonds 8 in S8

2. Set the ozone swim as AL before swimming

3o2---2o3

x ax=3a/2

8-3a/2+a=

A = 3 ozone is 3L

n (gas) =

Equipped with oxygen AMOL ozone bmol

2cu + O2 = 2cuo m (poor quality) a xx = 32a

3cu+o3===3cuo m (poor quality).

b yy=48b

a+b=32a+48b=

a=b=v(stinky oak grinding beam oxygen)=

B is false, because 3NO2+2H2O=2HNO3+NO, here, although acid is generated, other substances are also generated, so NO2 is not an acidic oxide.

C false, arsenic trioxide is a basic oxide.

Manganese heptaoxide, chromium trioxide, osmium tetroxide, vanadium pentoxide, molybdenum trioxide and other minor metal ** oxides are acid oxides.

D is wrong, for example, CO, so choose A

1. Because OH- reacts with H+ at 1:1, H2SO4 contains more H+, and hydrochloric acid is as much as acetic acid, so B A=C

2. Because acetic acid is a weak acid and can only be partially ionized, when it wants to ionize as much H+ as hydrochloric acid, the concentration of acetic acid required is greater than that of H+. Hydrochloric acid is a strong monobasic acid, and the concentration of H+ is the same as that of hydrochloric acid. Sulfuric acid is a binary strong acid, one sulfuric acid can ionize two H+, so the concentration of sulfuric acid is half of the concentration of H+, so when the three acids C (H+) are the same, the order of the concentration of the substance from large to small is C a B

3. Because acetic acid is a weak acid, when the concentration and volume of H+ ionized in the three acids are the same, the concentration of acetic acid is the largest, and in the process of reacting with zinc particles, due to the consumption of H+, the acetic acid in the molecular form begins to ionize again, and constantly replenishes the concentration of H+, so that it reacts with zinc particles the fastest. The H+ in hydrochloric acid and sulfuric acid is always the same, so the reaction rate is the same. Therefore, when the three acids C(H+) are the same and the volume is the same, and zinc grains with the same shape, density and mass are added at the same time, if the same volume of hydrogen gas is produced (the same condition), the relationship between the length of the reaction time is c a=b

Hope it helps

Hydrochloric acid chemical formula HCl, complete ionization, i.e., H+ in 1molHCl is 1mol acetic acid chemical formula CH3COOH, incomplete ionization is H+ in 1molHCl, chemical formula H2SO4 in 1molHCl, complete ionization, H+ in 1molHCl is 2mol1, even if the substance is incompletely ionized because of consumption, it will be gradually ionized, that is, the total amount of H+ contained in HCl and CH3COOH is the same, and H+ in H2SO4 is the same volume, The amount of the same substance is twice the concentration of the other two substances.

2. When the three acids C(H+) are the same, it is assumed that XMOL is required, HCLXMOL, H2SO4X 2mol, and CH3COOH is more than XMOL due to incomplete ionization

3. The reaction rate depends on the concentration, because C(H+) is the same, and CH3COOH is not completely ionized, and will be gradually ionized in the reaction, so that C(H+) in the latter CH3COOH is greater than the other two.

The mass fraction of carbon elements of acetylene, styrene and benzene is the same, so any proportion of the three is mixed to obtain, and the mass fraction of carbon elements of the resulting mixture is 12 13=

If you list their molecular formulas, you will find that the simplest formula is C1 H1 The ratio of carbon to hydrogen is 1 to 1, so the mass fraction of carbon is 12 13

First, the reaction amount of Hf is calculated by the difference method, mass = volume x density. The mass increases after 8 s of reaction.

The molar mass of the gas mixture is.

The volume of co is divided into:

The mass fraction of methane is:

According to PV=NRT, the density ratio of the same temperature and pressure is equal to the molecular weight ratio, the molecular weight of H2 is 2, the average molecular weight of the mixed gas is, the molar mass of the mixed gas is 23 grams, the mass of the mixed gas is 23 grams, the CO2 is amol, ch4 is bmol, a + b = 1mol, 44a + 16b = 23 grams, the solution is a = , b =, the same temperature and pressure, the mass ratio of the substance is equal to the volume ratio. CO2 volume fraction, CH4 mass fraction.

Your answer is correct, the oxidizing agent is more oxidizing than the oxidizing product.