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Anonymous users2024-02-111.A maximum of (23) can be taken.
That is, divide 7 and combine 1, 2, 3 and a number divided by 7.
There are 8 numbers that are left with 1 in addition to 7.
There are 7 numbers that are left with 2 in addition to 7.
There are 7 numbers that are 3 in addition to 7.
Take one of the numbers divided by 7 and have 1.
The maximum number can be 8+7+7+1=23.
The number of 2 2*2 cells is 7*7=49
The sum equal to 4 is 1,1,1,1
Equal to 5 is 1,1,1,2
And equal to 6 is 1,1,1,3 or 1,1,2,27 is 1,1,2,3 or 1,2,2,2 or 1,1,1,48 is 1,1,3,3 1,2,2,3 2,2,2,29 is 1,1,3,4 1,2,3,3 2,2,2,310 is 1,1,4 1,2,3,4 1,2,3,4 1,3,3 2,2,2,4 2,2,3,3
11 is 1244 1334 2224 2233 233312 is 1344 2244 2334 333313 is 1444 2344 3334
14 is 2444 3344
15 is 3444
16 is 4444
There are 11 types of and, that is, there are 11 possibilities.
There are 49 cells of the same class and (and equal to *) at least 49 11 = 4....5 So there are at least 4 of a class and the same.
and the same at least 49-11 = 38 (that is, the sum equal to * and the sum equal to ** and equal to ***. These categories and the number of homesickness).
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Anonymous users2024-02-10Solution 1: Divide 7 to sum 1, 2, 3, 4, 5, 6 and a number divided by 7.
A: There are 8 numbers that are left as 1 in addition to 7.
b: There are 7 numbers that are left with 2 in addition to 7.
c: There are 7 numbers except 7 for 3.
d: There are 7 numbers that are left with 4 in addition to 7.
e: There are 7 numbers except 7 for 5.
f: There are 7 numbers that are left with 6 in addition to 7.
You can't choose F when you choose A, you can't choose E when you choose B, and you can't choose D when you choose C
So there is a maximum of 8+7+7+1 (take one of the numbers divisible by 7 and have 1) = 23.
2 Solution: The values in the four cells are: 4, 5, 6, ,......16 There are 13 kinds in total.
There are a total of 49 2*2 field glyphs in the 8*8 grid
So there should be 49 13 = 3 ......10
So at least 3+1=4.
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Anonymous users2024-02-09Question 2. The number of 2*2 cells is 7*7=49
The sum equal to 4 is 1,1,1,1
Equal to 5 is 1,1,1,2
And equal to 6 is 1,1,1,3 or 1,1,2,27 is 1,1,2,3 or 1,2,2,2 or 1,1,1,48 is 1,1,3,3 1,2,2,3 2,2,2,29 is 1,1,3,4 1,2,3,3 2,2,2,310 is 1,1,4 1,2,3,4 1,2,3,4 1,3,3 2,2,2,4 2,2,3,3
11 is 1244 1334 2224 2233 233312 is 1344 2244 2334 333313 is 1444 2344 3334
14 is 2444 3344
15 is 3444
16 is 4444
There are 11 types of and, that is, there are 11 possibilities.
There are 49 cells of the same class and (and equal to *) at least 49 11 = 4....5 So there are at least 4 of a class and the same.
and the same at least 49-11 = 38 (that is, the sum equal to * and the sum equal to ** and equal to ***. These categories and the number of homesickness).
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Anonymous users2024-02-083x-2m+1=0
x=-2/3m-1/3
2-m=2x
x=-1/2m+1
Because they are inverse numbers to each other.
So: -2 3m-1 3=- (silver answer -1 2m+1m=4 73x-2m+1=0 in x=-5 72-m=2x in x=5 7
1 2ax + 5 = 7x-3 2.
x=-13/2/（1/2a-7）
Because of the defeat of the Ling, they are all positive integer feet trembling.
So it comes out. x=1a=1
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Anonymous users2024-02-07According to the inscription of the silent hail, ADG is a positive sail triangle (all three inner angles are 60) AD=DG=DE=EF
Angle b is 60db=de sin60=(2de 3) 3=(2ef 3) 3
bc=ab=ad+db=ef+(2ef shed3) 3=ef(3+2 3) 3
bc:ef=ef(3+2√3)/3:ef=(3+2√3)/3bc:ef=(3+2√3):3
1.Solution: Set up the original x people in the group, the time is t, and the total amount of the project is xtx+2) (t-2) = xt simplification: t-x-2 = 0 x-3) (t+6) = xt simplification: -t + 2x-6 = 0 + get: x=8 >>>More
1. If the full water of the whole water tank is 1, then the water injected per minute is 1 5, and the water flowing out per minute is 1 10. Now that x minutes have been injected, the injected water is (1 5-1-10)*x=x*1 10, and the remaining water is 1-x*1 10. Later, the same time tank is injected to be full, then the water injected later is x*1 5, which is equal to 1-x*1 10, and the result can be x=10 3. >>>More
1.Because a=1, c=0, so f(x)=x 2+bx 1, that is, f(x)-1 0, that is, x 2+bx-1 0, and then the main dimension is reversed, and b is regarded as the main element, and x is regarded as the dimension, that is, x is known, so it becomes a one-dimensional inequality about b, because x (0, 1, so the inequality is brought in, -1 0 is constant, 1 2+1 b-1 0, and b 0, in summary, b 0 2That is, 4 x + m (2 x) + 1 = 0 holds, and the equal sign shifts both sides, that is, m=-(2 x+2 -x), that is, find the range of f(x) = -(2 x+2 -x), because x r, so (2 x) (0, + commutation, so that 2 x=t, t (0, + i.e., the original formula is y=-(t+1 t), and y (-2) is obtained from t, that is, m (-2).
A swimming pool every year in June and August ** summer membership card, each membership card 80 yuan, only for personal use, voucher purchase admission ticket 1 yuan each, no voucher purchase admission ticket 3 yuan per ticket: >>>More
In the second problem, according to the symmetry, it is obtained that point b (2m-3,-1) intersects the parabola with a straight line at point b, so point b is on the parabola, so the point b is substituted into the parabola equation and m=2 >>>More