Preliminary small problems of physical mechanics, simple theoretical mechanics problems, and solutio

Updated on educate 2024-06-26
10 answers
  1. Anonymous users2024-02-12

    Yes, the action of force is mutual and relative!

    What you said about hitting the power is actually the magnitude of the kinetic energy, which affects the kinetic energy in two ways: 1 speed and 2 mass.

    And the most important factor is speed, because the more speed you have, the more force you're going on.

    Like when you're driving, don't overload, don't speed, that's what it means.

    If you're speeding, you're overloading, then you're going to have a lot of relative force, so you're going to get seriously injured!

    Kinetic energy is learned in the third year of junior high school, and if the speed is too fast, the kinetic energy you give to the object will be very large, due to the force.

    The effect is mutual, so you're going to get a reaction force, so hit hard.

  2. Anonymous users2024-02-11

    Factors influencing the magnitude of damage from a crash. The size of the force, the impact resistance of the car. Two vehicles collide with each other, regardless of the speed, and both vehicles experience the same force.

    Under the same conditions, the harder the material of the car, the more crash-resistant. The inertia of a car with large mass is large, and inertia is the ability to maintain the original state of motion. Therefore, the large mass is also collision-resistant.

    The high speed and the large damage refer to the damage of the two vehicles. When the velocity is large, the momentum is large, and the impulse is also large. Therefore, both cars are under great force.

    In fact, the speed is also relative, and the speed does not refer to the speed of the two cars compared with each other. It's like a big truck rushing up and hitting a bicycle, and the bike crashes into a stopped truck at a speed of 100 kilometers per hour.

  3. Anonymous users2024-02-10

    The force acts mutually, so both cars will be injured in the event of a crash. However, the degree of destruction depends on the kinetic energy of the two cars, which car has the greater kinetic energy, and the greater the degree of destruction.

    The magnitude of kinetic energy is related to the mass and velocity of the object, the higher the velocity, the greater the mass, and the greater the kinetic energy.

  4. Anonymous users2024-02-09

    The faster the speed, the greater the kinetic energy, both sides are miserable, for example, two 300 km cars collide and two 100 km crashes are not the same, as for the two cars crashed, if one hangs and one is just injured, that is, the car itself is not strong enough, but the impact force received is the same proportional to the square of the speed.

  5. Anonymous users2024-02-08

    The action of force is reciprocal.

    The faster the speed in a crash, the greater the force. So the faster the better. The force is still mutual.

    In fact, speed itself is relative.

  6. Anonymous users2024-02-07

    The more powerful here is the amount of kinetic energy.

    The magnitude of kinetic energy in physics is only related to the speed and mass of the motion of the object itself. So in the case of constant quality.

    The faster the motion of the object, the greater the kinetic energy.

    So the faster you crash, the more powerful it gets.

  7. Anonymous users2024-02-06

    The more you say it, the more you mean how much damage is done on both sides: the one that can't stand still is damaged, and the fast one is okay.

  8. Anonymous users2024-02-05

    It should be that the magnitude of kinetic energy is related to the velocity and mass of the object itself.

  9. Anonymous users2024-02-04

    The rollers do not slide with the ground, so the contact point x between the rollers and the ground is relatively stationary. In this case, the distance from the contact point x to the center of the roller is the radius r, and the distance from the contact point x to the plate is 2r. So the plate acceleration is 2 times the central acceleration.

  10. Anonymous users2024-02-03

    The contact point d between the plate and the wheel has no relative sliding, and the plate acceleration at point d is a = tangential acceleration ADT at the point of wheel d.

    For wheels, the vector equation of acceleration at point d ADT+ADN+AA projects the sphere ADT magnitude horizontally.

    adt=ar+ae=εr+aa=aa+aa=2aaaa=adt/2=a/2

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