A book has 183 pages, and the pages of the book are numbered with a number, with the number 1 having

Hehe. There are 9 single digits in total (no 0 pages).

There are 90 two-digit numbers (10 99).

There are 84 three-digit numbers (100 183).

So there are 9*1+90*2+3*84=441.

Contains the number "1".

Including the following: One digit: 1, two digits 10, 11, 21, 31, 41, 51, 61, 71, 81, 91, a total of 12 "1s".

Three-digit number: Because the hundredth digit of the following page number is one.

So there are 84 first"1"

There are 10 out of 10"1"(110 119) There are nine of you who have one"1"（101，111，121，131，141，151，161，171，181）

So there are 12 + 84 + 10 + 9 = 115.

Your question is not accurate and should take into account the actual situation.

First, if you open a book, the genuine one has a blank page, but the pirated one doesn't.

Second, a book has a preface, and the preface and the page numbers of the content are separate, that is, a book has more than one first page, and you can't calculate the exact answer if you are not sure of the number of pages in the preface.

Thirdly, when we say page, we usually mean one side, a piece of paper has two sides, and one side is called a page, so to be precise, a book with singular (e.g. 183) pages cannot exist, unless it is 92 sheets, and page 184 has no content, and therefore no page numbering, such a book is 183 pages.

So this question needs to be added before it can be done.

723 + 1 = 724, 724 2 = 362 because of one page of the book.

There are 2 page numbers, so the number of pages must be even, so you need to add 1 and divide by 2 to get a total of 362 pages.

Summary. Dear, there are 2893 numbers in total, so this book has a total of 2893 pages.

Page +9, number a book, a total of 2893 numbers, this book has a total of (pro, a total of 2893 numbers, so this book has a total of 2893 pages.

Because 1 page is a number.

From pages 1 to 2893, the numbers are not repeated, so the book has a total of 2893 pages.

Dear, if you have any other questions, you can also give you an answer, I wish you a happy life! <>

There are 11 numbers from 1 to 10, 181 numbers from 11 to 100, and 300 numbers from 101 to 200

11 + 181 + 300 = 492 (pcs).

As far as is known, the number of remaining numbers is:

723-492=231 (pcs).

Each page should use 3 numbers, and you can also make it:

231 3 = 77 (pages).

Therefore, a total of 200 + 77 = 277 (pages).

So the answer is: 277

1-9 pages 9, 10 to 99 pages, wheel difference.

There are 90 2 = 180 (pieces), at this time there are 1002-9-180 = 813 numbers left, 813 3 = 271, and Sozakura Ji has a total of 99 + 271 = 370 (pages) in this book

Therefore, the answer is: 370

Pages 1-9 of 9, 1 number per page, total of 1 9 9 numbers.

Pages 10-99 of 90 have 2 handwritten letters per page, totaling 2 90 180 numbers.

789 9 180 600 Count Posture Divine Wheel Characters.

600 3 Blind nucleus, 200 pages.

9 90 200 299 pages.

In the page number of this book, the single digit of lead 1 9 needs to be messed up with a total of 9 numbers; The two-digit number 10 99 requires a total of 2 90 = 180 digits; The three-digit number 100 999 requires a total of 3 900 = 2700 digits; At this time, there are 7641-9-180-2700 = 4752 digits, and 4752 digits can be combined into four digits: 4752 4 = 1188, 1000 2....

723 counts.

The word bai is definitely greater than the number of pages.

du10, single-digit page number.

zhi uses 9 numbers, dao 2 digits page number has a total of 90 numbers, each number 2 digits capacity, accounting for 180 numbers, so the remaining 723-9-180 = 534,534 3 = 178, so the 3-digit page number has 178 pages, starting from 100, the book has a total of 277 pages.

Pages 1-9 are in units.

10-99 is a double digit.

100-999 is a three-digit number.

Let's assume the total number of pages is x

Then 723 = 9 * 1 + 90 * 2 + (x-9-90) * 3 solution equation x 277 pages.

So the book is 277 pages long.

Pages 1 to 9, with 9 numbers, pages 10 to 99, with 180 numbers, pages 100 to 999, with 3 numbers per page, with (723-189) 3=178 pages, the book has a total of 277 pages.

1 digit: 9 in total, 9 numbers are used.

2 digits: 90 in total, 2 90 = 180 digital versions.

3 digits: 900 in total, need to use 3 900 = 2700 digits, so this book is right.

It must not have reached page 999.

The 3-digit number in this book shares 723-9-180 = 534 digits, that is, there are 534 3 = 178 three-digit numbers.

Therefore, the book has a total of 9 + 90 + 178 = 277 pages.

277 pages.

With one number: 1 9:9.

Use two numbers: 10 99::90 pages * 2 = 180 numbers remaining 723-9-180 = 534 numbers.

The rest are all special three numbers, ie.

Genus remaining 534 3 = 178 pages.

Total 9 + 90 + 178 = 277 pages.

723 digits must be greater than zhi10, single-digit page numbers occupy 9 digits, and 2-digit page numbers are altogether.

There are 90 numbers in the back, and each number is answered by 2 numbers, accounting for 180 numbers, so there are 723-9-180 = 534,534 3 = 178, so there are 178 pages in 3 digits, and from 100, the book has a total of 277 pages.

There are 9 single digits.

There are 90 two-digit numbers.

723-90x2-9=534

534 3 = 178 pages.

9 + 90 + 178 = 277 pages.

A: The book has 277 pages.

1-9...9 pcs.

zhi10-19,20-29.。。90-99...9x10x2 or more.

DAO9+180=189.

100-109, 110-119, ed. 190-199...10x10x3 or more, a total of 9+180+300=489.

200-209，..290-299...10x10x3 or more, a total of 9+180+300+300=789.

290-299, 280-289, 279, 278 22, 277 pages.

1-9 9 numbers.

10-99 (99-10+1)*2=180 numbers, and 723-180-9=534 numbers.

So there are 100 + 178 - 1 = 277 pages.

277 pages.

Pages 1-9 Page 9 Numbers 9.

10-99 90 pages Number 180 723-9-180 = 534

100-278 p. 178 Numbers 534 9 + 90 + 178 = 277 pp.

723 pages printed on one side.

Printed on both sides, 362 pages.

9 for one digit, 100 for two digits, and 1000 for three digits.

9 +2*100+3*x=723x=