Sixth grade math is a little bit faster, and sixth grade math is a little bit faster

1. Three-quarters of twenty-five Three-quarters = four-fifths (liters).

2. 1 4/25 = 25/4 = km).

3. Two hundred and fifty four-fifths = 40 (liters).

Average gasoline per 1 km per line: 3 25 3 4 = 4 25 = liters).

1 liter of petrol cars is feasible: 1 4 25 = 25 4 = km).

Traveled 250 km with gasoline: 250 (25 4) = 40 (liters).

How many liters of gasoline is used on average per 1 kilometer per line 3 25 3 4 = 4 25 (liters).

How many kilometers is feasible with a 1 liter of gasoline car 1 4 25 = 25 4 (km).

How many liters of gasoline after traveling 250 kilometers 250 4 25 = 40 (liters.

It takes a liter of petrol to travel a kilometer, a liter of petrol is feasible for a kilometer, and a liter of petrol is used to travel 250 kilometers with 40 liters.

3 25 3 4 = 4 25 (liters).

1 4 25 = 25 4 = km).

250 4 25 = 40 (liters).

A: On average, 4/25 litres of petrol is used for 1 km per line; With 1 liter of gasoline a car can be used for kilometers; Traveled 250 kilometers with 40 liters of gasoline.

I'm also 6 years old.

3 25 divided by 3 4 = 4 25 (liters) 1 divided by 4 25 = 25 4 (km) 250 divided by 4 25 = 25 1000 (km).

3 25 3 4 = liters km.

On average, 1 km per line uses petrol liters.

A 1-litre petrol car can travel 1 km.

Traveled 250 kilometers with 250* liters of gasoline.

Move the shadow in the lower-left corner to the lower-right corner.

s = area of two small squares + area of semicircles.

c = the length of a semicircular arc plus the circumference of a small square.

Calculate the number of units that were originally planned to be assembled per day: 800 20=40

Calculate the actual number of units assembled per day: 800 16 = 50

Calculate the percentage provided: (1-40 50)*100=20%.

1:20 divided by 16 minus 1 to get twenty-five percent; Step 2: 800 divided by 16 and then divided by 800 divided by 20 minus 1 to get 25 percent.

Method 1: The original planned efficiency is 800 divided by 20 = 40 per day, and the actual efficiency per day is 800 divided by 16 = 50 per day.

The efficiency increase is 50 divided by 40 —1 = 25%.

Method 2: Directly use the ratio of daily efficiency.

That is, 1/16 divided by 1/20 minus 1=25%.

1× 2.From the meaning of the title, 1 5 is used in the middle of the month, and 1-1 6-1 5 = 19 30 is used in the second half. The fraction used less in the first half than in the second half is 19 30-1 6=14 30 Divide the number by the corresponding fraction to get the unit one, so 90 14 30=

The side length of a 4 decimeter square can be seen as parallel lines of the diameter of the circle.

The ratio of upper, middle, and lower layers is 9:15:25

Upper: 4900 9 49 = 900 copies.

Middle layer: 4900 15 49 = 1500 copies.

Lower level: 4900 25 49 = 2500 copies.

Upper: Medium = 3:5

Middle: Bottom = 3:5

Up:Middle:Down = 9:15:25

4900 (9+15+25) = 100 for each book, then 900 books for the upper level.

1,500 mid-level books.

2,500 books on the lower floor.

A runs 7 meters per second, and B runs 5 meters per second. The two started in the same direction on a 200-meter circular track at the same time. After a long time, A and B met again on the runway.

50 3 seconds.

Starting in the same direction should be to subtract the speed of the two people, and the problem of meeting in the opposite direction is to add the speed.

200 divided by (7-5) = 100 seconds.

Divide 138 by 115 percent to find the original price, and multiply by 85 percent to get the current selling price.