Please give me a few questions, and there is one problem that I hope will help me solve.

1. If m2=n+2, n2=m+2(m≠n), then the value of m3-2mn+n3 is ( ).

a) 1 (b)0 (c)-1 (d)-2

a)m>0 (b)m 0 (c)m <0 (d) m cannot be determined whether m is positive, negative or 0

3. The area of the right triangle ABC is 120, and BAC=90, AD is the middle line on the hypotenuse, and the area of AFE is ( ) if D is DE AB in E, and CE is in F, then the area of AFE is ( ).

a)18 (b)20 (c)22 (d)24

4. The circle O1 and O2 are tangent to point A, and one of the two circles is tangent to the circle O1 at point B, if AB is parallel to another circle tangent of the two circles, the ratio of the radius of circle O1 to circle O2 is ( ).

a)2：5 (b)1：2 (c)1：3 (d)2：3

I have a document to send to your email.

1.What animal guess punch never has to win or lose?

2.What chicken doesn't have wings?

3.A bull plus a cow, guess three words.

4.A bull plus a cow, guess five words.

Do human beings really have souls, or are they merely expressions of emotions in the results of various factors involved in the calculations? The significance of the latter lies in the artificial machine soul.

1+1 is the hardest time.

Let's take a look at what is the plot of the second part of Meteor Shower?

Where there is a chicken in the world, should there be an egg?

Don't do it, there's something wrong with the description of this question. The line segment has been enclosed in a circle, the points p and q are still moving to the left, and there are left and right on the arc? Isn't the lower half of the circle to the left, and the upper half of the circle to the right?

ac=50, ab=100, is it calculated from clockwise or counterclockwise?

Point M is the midpoint of the AP, why not say that it is the midpoint of the arc AP? Isn't it a line segment AP that people who have to do the question reason?

Xiao Ming's only count is 13 points of the other three's total and rises to 7, then Xiao Ming's only number is the total number of oaks.

7 (13 7) 7 out of 20

In the same way, the small army only counts the total number of things.

1 (1 3) 1/4

Xiao Fang only counts the total number of things.

11 (11 29) 11/40

The only thing that Xiaohong did was the total.

1 20 points is as good as the old 7 4 1 11 40 8 1 they did it all.

15 1 120/8 (pcs).

Xiao Ming only counted 7/13 of the total number of the other three

So, Xiao Ming made a total of 7 20

Xiaojun only counted 1/3 of the other three's total number

So, Xiaojun made 1 of the total number of Zhiyin Brother 4

Xiao Fang only counted 11/29 of the other three combined

So, Xiaofang made a total of 11 40

Red made a total of 1 (7 20) (1 4) (1 4) (11 40) 1 8

Little Red made 15 of them.

So, the total number is 15 1 8 120

A total of 120 paper cranes were made.

Set the total number of w, Xiao Ming answered Qi rot x, Xiao Jun y, Xiao Fang z.

w=x+y+z+15

w-x) multiplied by 13 points of leakage 7=x

w-y) multiplied by 1/3 = y

w-z) multiplied by 11/29 = z

w=120

15 divided by [1-(7 13+7) imitation mu-(Songshi 1 1+3)-(11 29+11) wild limbs].

15 divided by (1-14 40-10 40-11 40) 15 divided by 5 40

15 times 40 5

Hope it helps.

Just list the square scatter program group.

Set the clear and absolute pin as x, the army as y, and the fang as z, according to the relationship, list the party and dig the tour group to solve the problem.

The logarithmic interval of log with pure dust as the base (-x2+2x+3) is

log is based on 2 and the logarithm of 3 = a, log is based on 3 and 7 is logarithm = b, and shendan a, b is used to represent the logarithm of log with 14 and 56.

It is proved that the even number of each jujube segment is not less than 6 can be expressed as the sum of two odd primes.

It's hard enough. Reputation.

I will serve you if you can make it.