The right angled trapezoidal lower is 772 meters, the upper low is 652 meters, the high is 270 meter

It's so troublesome... If there's another way, don't look at me...

As shown in the figure, add two line segments EF and GH parallel to the two bottom surfaces in the trapezoid, and set the heights of the three small trapezoids to A, B, and C respectively. Let the lengths of EF and GH be x and y, respectively. Extend the intersection of CA and DB at point O.

ab∥cd△oab∽△ocd

ab：cd=oa：oc

That is, 652:772=OA:(OA+270), and the solution is OA=1467, which is the same as AB:

EF=OA:(OA+AE), i.e., 652:x=1467:

1467+a），x=652+652÷1467×a

In the same way, y=652+652+1467 (a+b), total area (652+772) 270 2=192240 square meters.

The area of the three small trapezoids is 192240 3 = 64080 square meters.

x=652+652÷1467×a

y=652+652+1467×（a+b）

a+b+c=270

652+x）×a÷2=64080

x+y）×b÷2=64080

y+772）×c÷2=64080

Solve a, b, c.

The key to this problem is to make another high, and get the ratio of the right-angled side of the triangle to the bottom edge = 270 (772-652) = 9 4

Then, calculate the area after being divided into thirds = 1 3 [1 2 (652 + 772) 270].

Let the topmost small trapezoidal height be a, and the bottom edge = 652 + 4 9a trapezoidal area formula can obtain the value of a.

The same is true for the other small trapezoidal heights.

Summary. The area of this right-angled triangle is 8 6 2=24, square meters The upper bottom of the trapezoid is 6 m, the bottom is 10 meters, and the white right triangle inside is 6 meters, 8 meters and 10 meters respectively.

The area of this right triangle is 8 6 2=24, square meters Find the area outside the triangle.

This is a picture reading question, and there must be a picture.

Please take a photo of the original question and upload it.

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Now we can know the area of a right triangle, and we can know its base, and we can know the height of its base.

How to ask for this high.

Find the shaded area.

6+10) sqm).

Summary. So divide by 2 to get the length of the top. Then add the length of the bottom edge of the triangle to the length of the bottom bottom.

Take a picture of the original question and send it to me to see.

The upper bottom is, and the rock balance and the bottom bottom is. Envy limb process rough do 3 sin30 = 66 3 2 = 6

Because the bottom angle is 30° and the height is 3, the hypotenuse is 6

The length of the lower base of the right triangle formed is 6 cos30=

The total length minus the hypotenuse, minus the height, and the bottom of the right-angled triangle of the cherry blossom cavity. It is the sum of the remaining top bottom and bottom bottom. This is a rectangle like two longs with it.

So divide by 2 to get the length of the top. Then add the length of the bottom edge of the triangle to the length of the bottom bottom.

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Draw an auxiliary line of the trapezoid into a rectangle and a triangle, one right-angled side of the triangle is 92-57 = 35, the hypotenuse is 157, and the other right-angled side is under the root number (157 2-35 2) = 23424 under the root number, that is, the trapezoid height is 23424 under the root number

Bottom - bottom top = 35 cm.

Construct a right-angled triangle using the Pythagorean theorem.

High =157 -35 =23424

High is: 8 roots No. 366

Hope, thank you.

Right-angled trapezoid, 57 cm at the bottom, 92 cm at the bottom, make an auxiliary line to make a right-angled triangle, the bottom minus the bottom is 35 cm is a right-angled side, the hypotenuse is 157 cm is the triangular hypotenuse, and the height of the trapezoid is another right-angled side.

[157 - (92-57) +153 (cm).]

The trapezoidal shape is about 153 cm high.

Bottom - bottom top = 35 cm.

Construct a right-angled triangle using the Pythagorean theorem.

High =157 -35 =23424

Gao Wei Zhong Sakura quietly: 8 roots No. 366

Hope to sell the scum song hole, thank you.