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The selling price should be set at $x.
Then the sales volume is 800-[(x-60) 5] *100 profit per piece x-50
Then the total profit is [800-(x-60) 5 *100]*(x-50) = 12000
The simplification equation is x 2-150x+5600=0, then (x-70)(x-80)=0
So x=70 or 80
Both solutions fit the topic.
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The price should be set at x yuan, and the clothing should be y.
The amount required for purchase is 50*Y yuan.
Sales are reduced: 100*(x-60) 5
So the total sales are: 800-100*(x-60) 5 into clothing and sales clothing are equal, so 800-100*(x-60) 5=y so the total sales are: x*y
So the profit is: x*y-50*y=12000
The solution is x=70 pieces, y=600 yuan.
or x=80 pieces, y=400 yuan.
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The set price is X yuan higher than 60 yuan.
800 - x/5 × 100) ×60 + x - 50)=12000
800-20x) 10 + x ) = 120008000 + 800x-200x-20x square = 12000400 + 40x-10x-x square = 600
x square - 30x + 200 = 0
x=10, so the price is 70 yuan.
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The price should be set at 800 yuan, and the store should buy 1,200 pieces of clothing.
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(2x+29)(2x+22)=29×22+29×22×1/44x²+44x+58x+638=638+
4x²+102x=
x²+x²+
x+x+x+ or x+ is not on topic, discard).
So x+x= A: The width of the rim is about centimeters.
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Let the average percentage of each price reduction be x
From the title: 60*(1-x) 2=
x=10%
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60 times (1 x) squared equals, and the solution is x=
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Assuming that percentage is x, then there is equation 60(1-x)2 = that solves for x equals.
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x divided by 4 squared + 64-x divided by 4 squared = 160 (x 4) 2 + [(64-x) 4] 2 = 160 (x 4) 2 + [16 - x 4] 2 = 160 (x 4) 2 + 256-8x + (x 4) 2 = 1602 (x 4) 2-8x + 96 = 0
x/4)^2-4x+48=0
x^2-64x+768=0
Find the root of the equation according to Vedic theorem.
x1=48x2=16
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Is the formula copied wrong? There's no solution to this, right? Move 64 to the right = 96, in this case the formula is: x divided by 4 squared - x divided by 4 squared = 96. It's 0=is canceled. So there is no solution.
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x divided by 4 squared + 64-x divided by 4 squared = 160x 2 16 + 256-8x + x 2 16 = 160x 2 8-8x + 96 = 0
x^2-64x+768=0
x=16, or x=48
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I don't think you mean (x 4) 2+64-x 4 2=160 first simplified yes.
x^2-x=96*16
So, (x-1 2) 2=96*16+1 4, you should know what to do.
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Suppose y=x divided by 4 squared, then the question y+64-y=160 is obviously not true.
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put"x divided by 4"Seen as an unknown a
then a 2 + (64-a) 2 = 160 finds a
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Solution: Set each shuttlecock to be $ x and each rope to be $ y.
System of equations: 5x+8y=34
3x+4y=18
Solution: x=2
y=3 A: 2 yuan per shuttlecock and 3 yuan per rope.
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Shuttlecock x, skipping rope y
5x+8y=34 |
3x+4y=18 →6x+8y=36 |Subtract the two formulas x=2 y 3
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1.It is relatively easy to solve equation 3(x-2)2=2x-4.
2.If 2x2+1 is the opposite of 4x2-2x-5, then the value of x is
3 If the unary quadratic equation ax2+bx+c=0(a≠0) has a root of -1, then the relation of a, b, and c is
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Let Xiao Ming count x times, then.
50《3x+1《54
x=17, so it's 3x+1 in total, i.e. 52.
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According to the "child tower" is equal to 0: m=-1 or m=72 Q: According to the product of a part c equal to two roots: m+2=m squared - 9m+2 can be found to be m equal to m=0 (rounded) or m=10
Under the root number, m+6=root6 (rounded off because m》7 or m"1"), the answer is the root number, m+6=4, and their answer is wrong.
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(1)△=(m-1)²-4(m+2)=0;m=-1 or m=7(2)m+2=m-9m+2; m²-10m=0;The solution yields m=0 or m=10
>=0;So -1 under the root number m+6 = root number 6
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(1) If the equation has two equal real roots, then (m-1) 2-4(m+2)=0(2) let the two roots be x1, x2.
x1+x2=m-1 , x1*x2=m+2, so m+2 is equal to m-9m+2
M-worth do the math yourself.
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