A rectangular piece of wood with a square cross section is cut into one of the largest cylinders

Height=3 diameter.

So: height = 6 diameter.

So: 2 radius + 2 radius 6 radius = square centimeter.

Let the radius be x centimeters.

2× x²+2× x×6x=

x = i.e. radius =

So: diameter =

Whereas: the surface area of the box.

2 Diameter +4 (Diameter 3 Diameter).

14 diameters

42 square centimeters.

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The cylindrical surface area s1 2 r is squared + 2 r h

The surface area of the cuboid s2 2 4 r is +2 4 r h

So s2 s1 4 42 square centimeters.

If the radius of the base surface of the maximum cylinder is r cm, then its height is 6r cm, r*r=

The length and width of the original cuboid are 2r cm, and the height of the original cuboid is 6r cm.

The surface area of the original box.

2r*2r+2r*6r+2r*6r）*2=56*r*r

42 square centimeters.

According to r 2=, we know that r = 3 2

Then the diameter is 3, and the height is 3 3

The surface area is 3* 3*2+3 3* 3*4=42

Please, it's a cuboid, not a rectangle, there's a big gap!!

Solution: Let the diameter of the bottom surface of the cylinder be d, then the height of the cylinder is 3d, and the length of the bottom side of the cuboid is d, and the height is 3d.

Derived from the title: 2·d d·3d

7π/2·d²＝

d²＝3 d＝√3

The volume of the box is: d ·3d 3d 9 3cubic centimeters

It's very simple. The surface area s= d*3d+2* d*d4=, and then the volume of the cuboid is v=d*d*3d=

Solve d, bring back the above equation to solve.

square centimeters).

The surface area of the original cuboid was 42 square centimeters.

Analysis: The ratio of the area and circumference of the square to the circle is 4: )

Because it is not a cylinder made of a cube, the bottom diameter cannot be found by the surface area alone.

It must also be cylindrical high.

Send the diagram, or bring the rock silver for the relevant data.

The volume of the maximum cube cut into: 15 15 15 = 3375 (cubic centimeters).

The maximum number of cuts: 145 15 is about equal, so the most powerful multi-energy jujube beams cut 9. (Tail removal method).

There is no picture, big brother The largest cube takes the length of the cuboid length, width, and the smallest side length of the middle school as the side length of the cube.

The length of the square wood is.

4 (1 10) = 40 (decimeters).

To be processed into the largest hail mold cylinder, the diameter of the ground of this cylinder source is equal to the length of the bottom side, which is higher than the length of the square wood.

The volume of the cylinder is.

square * 40 = cubic decimeter).

The area to be removed is.

4*4*cubic decimeter).

Removed. Friends =

The surface area of the cylinder is:==

square decimeters.

Height=3 diameter.

So: height = 6 radius.

So: 2 radius + 2 radius 6 radius = square centimeter and let the radius be x centimeter.

2× x²+2× x×6x=

x = i.e. radius =

So: diameter =

Whereas: the surface area of the box.

2 Diameter +4 (Diameter 3 Diameter).

14 diameters

42 square centimeters.

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The side length of the square is the circumference of the bottom surface of the cylinder, and the height of the box is the height of the cylinder.

Let the side length of the square be a, and the height of the cuboid be h.

Surface area of the cylinder:

a²÷2+ah=30

a²+2ah=60

A is the area of the square, ah is one side of the box, because one of the cross-sections of the box is a square, so the area of its four sides is the same. That is, the surface area of the cuboid = 2a + 4ah = 2 (a + 2ah) = 2 60 = 120 square centimeters.

Solution: Let the side length of the square be a, and the height of the cuboid be h.

Surface area of the cylinder:

ah+a²/2=

The surface area of the cuboid: 2a + 4ah = 4 (ah + a 2) = 4 30 = 120 square centimeters.