NA2O2 reacts with a certain amount of CO2 and water vapor mixture, how to determine the final reacti

Updated on science 2024-08-09
11 answers
  1. Anonymous users2024-02-15

    The reaction of sodium peroxide with a mixture of carbon dioxide and water can be regarded as reacting with the former first, and if there is a residue of sodium peroxide after reacting with the former, it reacts with water.

  2. Anonymous users2024-02-14

    Sodium peroxide should react with carbon dioxide first and then with water.

  3. Anonymous users2024-02-13

    Introduce and H2O into a sufficient amount of solid Na2O2, and a reaction occurs: 2Na2O2 + 2CO2 = Na2CO3 + O2, 2Na2O2 + 2H2O = 4NaOH + O2, the solid only increases, because O2 is generated, according to the law of conservation of mass M(O2) = , so N(O2) = 16g

    32g mol, according to the equation, we know that n(mixed gas)=2n(o2)=2, so the average molar mass of the mixed gas =

    1mol, so the average relative molecular weight of the gas mixture is, so C is selected

  4. Anonymous users2024-02-12

    co2 + naalo2 + 2h2o ==nahco3 + al(oh)3↓

    Because there is an excess of CO2, NAHCO3 is generated

  5. Anonymous users2024-02-11

    co2 + naalo2 + 2h2o ==nahco3 + al(oh)3↓

    Because there is an excess of CO2, NAHCO3 is generated

  6. Anonymous users2024-02-10

    Solution: Let the mass of CO2 in the original mixed gas be x, and the increased mass of the solid reacted with sodium peroxide is Y2CO2+2Na2O2=2Na2CO3+O2 mx Y2H2O+2Na2O2=4NaOH+O2 M88:56=X:

    y36:4=( )

    Solution: x=mass of water vapor=

    then the amount of CO2 in the original gas mixture =

    then the amount of H2O in the original gas mixture =

  7. Anonymous users2024-02-09

    2 CO2 2 Na2O2 = 2 Na2CO3 O2 2 H2O2 Na2O2 = 4 NaOH O2 The ratio of the amount of CO2 to O2, H2O to O2 is 2:1 Therefore, the ratio of the amount of the substance of the mixture gas to O2 is 2:1

    According to the conservation of mass: Solid mass before reaction Mixed gas = solid mass after reaction O2 mass i.e. O2 mass = solid mass before reaction Mixed gas - Solid mass after reaction = Mixed gas - Solid mass after reaction - Solid mass before reaction ) Mixed gas - Mass of solid weight gain = - g = 16g Amount of substance of oxygen n(O2) = 16 32 = mol

    n(gas mixture) = n(o2)2 = 1 mol

  8. Anonymous users2024-02-08

    First of all, calculate the quantity of O2: the amount of the substance of CO2: , due to:

    2Na2O2+2CO2==2Na2CO3+O2,Na2O+CO2==Na2CO3, then it is calculated that the amount of Na2O2 is , the amount of Na2O2 is :, then the mass fraction of Na2O2 is:, and the mass fraction of Na2O is:.

  9. Anonymous users2024-02-07

    Step-by-step reaction: 2Na2O2+2H2O=4NaOH+O2 CO2+H2O=H2CO3 (unstable).

    2NaOH + H2CO3 = Na2CO3 + 2H2O (neutralization reaction) Na2CO3 + CO2 + H2O = 2NaHCO3 (CO2 excess) Total reaction: 2Na2O2 + 2CO2 = 2Na2CO3 + O2 Na2CO3 + CO2 + H2O = 2NaHCO3 (CO2 excess).

    Na2O2 is a basic peroxide that is unstable in water, and CO2 is an acidic gas, which is generally regarded as a direct reaction, i.e., a total reaction. However, there is a small amount of water in the air, and Na2O2 is absorbent, so it is reasonable to react step by step (i.e., it is considered to have water involved). When answering, you should choose according to the meaning of the question.

    In addition, the CO2 excess reaction must involve water.

  10. Anonymous users2024-02-06

    2Na2O2+2CO2=2Na2CO3+O Na2O2 + 2H2O***** The essence of the reaction between 4NaOH + O2CO2 and Na2O2 is:

    Step 1: 2Na2O2+2H2O=4NaOH+O2 Step 2: 2NaOH+CO2=Na2CO3+H2O Total Reaction Equation:

    2CO2 + 2Na2O2 = 2Na2CO3 + O2 Therefore, Na2O2 does not react with dry CO2

  11. Anonymous users2024-02-05

    The equation of CO2, H2O and Na2O2 reaction is tricky for many students, and it is basically written by rote memorization, but the good times are short-lived, and they will soon forget! So what to do? Teacher Qianlong created an original method to share with dear students, welcome students to be serious!

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