The highest H concentration in the following groups of solutions is:

In A, since HCl is a monobasic acid, C(H)=

b: Sulfuric acid is a dibasic acid, so c(h)=

C: Acetic acid is a weak acid, and C(H) is <

D: Hydrosulfuric acid (H2S) is also a weak acid, and C(H) is <

So the maximum concentration of H+ is B

Because HCl:H 1:1 in A, the concentration of H+ is H2SO4:H 1:2 in mol lb, and the sulfuric acid is a strong acid, which can be seen in water.

The concentration of h is fully ionized.

Acetic acid in c is a weak acid and is not completely ionized in water. So the concentration of H+ in acetic acid will be less than.

Although H2S:H 1:2 in hydrosulfuric acid in mol LD, it is not completely ionized in water because it is a weak acid, so the actual H concentration in the solution is less than.

Therefore, the sulfuric acid of B was chosen.

a, hydrochloric acid is a strong acid, mol l of hydrochloric acid, hydrogen ion concentration is mol l.

b Sulfuric acid is a strong acid, and the concentration of sulfuric acid and hydrogen ions is.

c Acetic acid is a weak acid, acetic acid is not completely ionized, and the concentration of hydrogen acetate ions in mol L is less than that of mol L.

d Hydrosulfuric acid is a weak acid, hydrosulfuric acid is not completely ionized, and the concentration of hydrogen sulfate ions is less than mol l.

Therefore, the concentration of sulfuric acid H+ is the largest, and B is selected

b of sulfuric acid.

hcl:h＋＝1：1

H2SO4:H1:2, sulfuric acid containing H.

Acetic acid and hydrosulfuric acid are not completely ionized. Although H2S:H 1:2 in hydrosulfuric acid, the actual H concentration in solution is less than because it is not completely ionized.

Because HCl in A is a monobasic strong acid, the concentration of H+ is a dibasic strong acid in mol LB H2SO4 is a dibasic strong acid, which can be regarded as all ionized in water, so the concentration of H is.

Acetic acid in c is a weak acid and is not completely ionized in water. So the concentration of H+ in acetic acid will be less than mol L

Although H2S:H 1:2 in hydrosulfuric acid in D, it is a weak acid and is not completely ionized in water, so the actual H concentration in the solution is less than.

Therefore, the sulfuric acid of B was chosen.

a, chlorine atom has the smallest relative mass.

Answer] :d Instructions] (1) The order of pH from small to large is the order of weakening acidity and increasing alkalinity Each group of solutions can be acid solution or alkaline solution, or it can be gradually transitioned from acid solution to alkaline solution

2) HCl and H2SO4 are both strong acids, but HCl is a monobasic strong acid, and H2SO4 is a dibasic strong acid, so the amount and concentration of substances used as acids.

When the same is the case, H2SO4 ionizes H+ 1 times more than HCL, i.e., H2SO4 solution is more acidic than HCl solution so option B is wrong

In option A, the mold closed KCl is a strong acid and alkali salt, and the aqueous solution is neutral, while the HBR and Hi solutions are strongly acidic, so the crack is in line with the order of acidity weakening

In option C, the KOH and NaOH solutions are strongly alkaline, and Ca(OH)2 is a medium-strong alkaline, and the alkalinity of the solution is weak, so it does not conform to the order of alkalinity enhancement

In option D, HCl solution is strongly acidic, CH3COOH solution is weakly acidic, and NH3·H2O solution is weakly alkaline, which conforms to the order of weakened acidity and increased alkalinity

Answer] :d Solution] (1) The order of pH from small to large is the order of weakening acidity and increasing alkalinity The solution in each group can be either acid solution or alkaline solution, or it can be gradually transitioned from acid solution to alkaline solution

2) HCL and H2SO4 are both strong acids, but HCL is a monary strong acid, and H2SO4 is a dibasic strong acid, so when the amount and concentration of acid substances are the same, the H+ ionized by H2SO4 is 1 times more than the H+ ionized by HCL, that is, the acidity of H2SO4 solution is stronger than that of HCl solution, so option B is wrong

In option A, KCl is a strong acid and alkali salt, and the aqueous solution is neutral, while the HBR and HL solutions are strongly acidic, so it does not conform to the order of acidity reduction

In option C, the KOH and NaOH solutions are strongly alkaline, and Ca(OH)2 is a medium-strong alkaline, and the alkalinity of the solution is weak, so it does not conform to the order of alkalinity enhancement

In option D, HCl solution is strongly acidic, CH3COOH solution is weakly acidic, and molded NH3·H2O solution is weakly alkaline, which conforms to the order of weakened acidity and increased alkalinity

Answer] :d Instructions] (1) The order of pH from small to large is the order of weakening acidity and increasing alkalinity Each group of solutions can be acid solution or alkaline solution, or it can be gradually transitioned from acid solution to alkaline solution

2) HCL and H2SO4 are both strong acids, but HCl is a strong acid of one element, and H2SO4 is a strong acid of two kinds, so when the amount and concentration of acid substances are the same, the H+ ionized by H2SO4 is 1 times more than the H+ ionized by HCl, that is, the acidity of H2SO4 solution is stronger than that of HCl solution Therefore, B selects Dan Hui crack term wrong In option A, KCl is a strong acid and alkali salt, and the aqueous solution is neutral, while HBR and HL solutions are strongly acidic, so it does not conform to the order of weakened acid mold closure Option C, KOH and NaOH solutions are strongly alkaline, Ca(OH)2 is medium and strong alkaline, and the alkalinity of the solution is weak, so it does not conform to the order of alkalinity enhancement In option D, HCl solution is strongly acidic, CH3COOH solution is weakly acidic, and NH3·H2O solution is weakly alkaline, which conforms to the order of weakened acidity and increased alkalinity

The amount and concentration of the substance are the same.

Because there is only one NH4.

So it is necessary to consider in terms of ionization and hydrolysis.

The first three types are the same, all are ammonium salts.

Minimally, because it is a weak base, ionization is certainly the least, excluding first, NH4+ hydrolysis shows weak acidity.

A, NH4Cl, NH4+ hydrolysis showed weakly acidic, partially hydrolyzed, NH4+ secondary.

B, NH4HSO4, a strong acidic solution, strongly inhibits hydrolysis, NH4+ Max C, CH3CoonH4, weak acid and weak alkali salts, promote hydrolysis with each other, neutral solution, NH4+ is the smallest of the three.

The answer is b

Choose Ba NH4Cl strong acid weak alkali salt B NH4HSO4 strong acid weak alkali salt C weak acid weak alkali salt D weak base.

The idea is hydrolysis. A NH4++H20=NH3H20+H+ B at the same time as the hydrolysis in A, since NH4HSO4=NH4+++H++SO42- due to the presence of ionized H+, the NH4++H20=NH3H20+H+ equilibrium shifts to the left, so the NH4+ concentration is larger than that in A.

While c weak acid and weak alkali salt hydrolytic equilibrium shifts to the right, it is not as good as weak base itself is not fully ionized, not as good as c.

a, NH4Cl strong electrolyte ammonium ion concentration is the largest.

The largest concentration of NH+4 in the following solutions with the same concentration of substances is NH4HSO4, because NH4HSO4=NH4++H++SO42- is completely ionized, and the solution is acidic, which inhibits the hydrolysis of NH4+;

NH4+ and HCO3-, CH3COO- and NH4+ in NH4HCO3 and CH3COONH4 solutions promote the hydrolysis of each other, and the concentration of NH4+ decreases.

NH4+ hydrolysis in NH4NO3 solution reduces the concentration of NH4+ in solution.

NH4+ hydrolysis in NH4NO3 solution reduces the concentration of NH4+ in solution.

NH4HSO4, a proton ionized by HSO4- inhibited the hydrolysis of NH4+.

PH10,H+ Concentrated Potato Finch Must Be 10 (-10)mol L, there is only one answer.

When C(H+) = 10 (-10)mol L in solution, pH 10, there is only one answer.

There are two early state answers to this kind of question:

In solution, water ionized by C(H+) = 10 (-10) mol L, pH 10 or 4. There are 2 answers.

Because of the hand type: if it is an acid solution, pH = 4;If it is a salt that can be hydrolyzed, pH = 10

A and Da, the hydroelectric power is separated from OH-

at a concentration of 10

mol clump l, the ionized H+ in the dilute solution is 10 (-4) mol L, according to pH=-lg[H+], the H+ ionized by water is 4d

It is H+ in dilute solution, and the pH is 10 according to pH=-LG[H+].

a, bromine oxidation, sulfur dioxide reduction, the two undergo redox reaction to produce sulfuric acid.

c, metathesis reaction, copper sulfide is a black solid that is insoluble in acid, this reaction is a rare metathesis reaction of weak acid to strong acid.

Both of these are weak acids that become strong acids, and the hydrogen ions of weak acids are partially ionized, and the strong acids are all, so there are more hydrogen ions.