Among the following solutions with the same amount and concentration of substances, the largest conc

Choose b because a: NH4CL = NH4+ +CL- NH4+ +H2O《=" H+

B: NH4HSO4= NH4+ +H+ +SO42- NH4+ +H2O《=" H+ Here the ionized H+ inhibits the hydrolysis of NH4+, so the NH4+ concentration is maximum.

C: NH4AC = NH4+ +AC- NH4+ +H2O《=》 H+ AC- +H2O《=》HAC- +OH- Because NH4+ hydrolysis is acidic and AC- hydrolysis is alkaline, so they promote hydrolysis with each other, so NH4+ is less than A and B.

d: +OH- Because ammonia monohydrate is only a small amount of ionization, the least amount of ammonium ions is ionized.

Ammonium ion concentrations from large to small: b》a》c》d

Good luck with your studies!!

First, the weak base of ammonia monohydrate is partially ionized with the least NH4+.

NH4Cl, NH4HSO4, CH3CoonH4, are all salts, completely ionized, and NH4+ is more.

It should have been as much NH4+, but NH4+ hydrolysis has the potential to be interfered with by the rest of the ions.

nh4+ +h2o== + h+

NH4Cl has no interference, NH4+ hydrolysis normally.

The ionization of NH4HSO4 produces H+, which inhibits the hydrolysis of NH4+, so NH4+ becomes abundant.

The ionization of CH3CoonH4 produces CH3COO-, which will promote hydrolysis with NH4+, so NH4+ decreases.

So for: b > a > c > d

Summary. Because the number of ions in C is significantly less than that in A, and there is an imbalance of positive and negative ions.

Kiss 3, hello, I'm honored to answer your questions, your question Xiaoxue teacher has been collected to do, is typing to reply takes a little time (a big disturbed reply within five minutes), please wait a while.

The following substances and solutions with the same concentration of Hudu are in the correct order of ()>mgCl2>HAC>NaClB, MgCl2>mgSO4>NaCl>>mgCl2>NaCl>>mgCl2>NaCl>HA pants. mgcl2>nacl>mgso4>hac

Kiss: Can you take a picture of it for me?

Kiss A is correct.

I don't understand. Analysis: The number of particles can be judged according to the number of particles, and the strength of ionized ions can be judged according to the number of particles, because there is no precipitation in the four substances.

So: the foot mark and the large the ionic strength.

But isn't the number of particles of magnesium chloride greater than that of magnesium sulfate, and isn't magnesium sulfate equal to sodium chloride?

Kiss: Magnesium sulfate is not precipitated by the same mole of the number of birds, magnesium sulfate ions have five moles, and chloride is slowly magnesium only three moles of five three, so the ionic strength of magnesium sulfate is large.

Sometimes some people think that magnesium sulfate is a precipitation and may not be only partially ionized, but in fact, magnesium sulfate is soluble in water, and there are more ionized ions.

Then this title is why choose A and not C.

Because the number of ions in C is significantly less than that in A, and there is an imbalance of positive and negative ions.

Summary. Hello dear, happy to answer your questions, 1The correct order of ionic strength of the following substances in the same concentration is ()>mgCl2>HAC>NACA:

Hello, according to the definition of ionic strength, the greater the ionic strength, the closer the activity coefficient of the ions in the solution is to 1, that is, the higher the activity of the ions in the solution. So oh, in a solution of the same concentration, the higher the ionic strength, the higher the activity of the ions in the solution. According to the information given in the question, the correct order of ionic strength should be:

mgcl2 > mgso4 > hac > nac。Hope it helps<>

Hello dear, happy to answer your questions, 1The correct order of ionic strength of the solution of the following substances at the same concentration is ()>mgCl2>HAC>NACA: Hello, according to the definition of ionic strength, the greater the ionic strength, the more the activity coefficient of the ions in the solution is close to 1, that is, the higher the activity of the ions in the solution.

So oh, in a solution of the same concentration, the higher the ionic strength, the higher the activity of the ions in the solution. According to the information given in the title, the correct order of ionic strength should be: MgCl2 > MgSO4 > HAC > NAC.

Hope it helps<>

Extended supplement: Ionic strength is a physical quantity that describes the intensity of the influence of the number of ions and the type of line on the properties of the electrolyte solution. The ionic strength is related to the type, quantity, and charge of the ions in the solution, as well as the temperature and pressure of the solution.

In chemical reactions and solution equilibrium, ionic strength is an important parameter. <>

The answer should be b. First of all, we need to know that ammonium is hydrolyzed, and the hydrolysis is acidic.

In option A, aluminum ions are also hydrolyzed, and they are also hydrolyzed acidic, and the hydrogen ions produced by its hydrolysis will inhibit the hydrolysis of some ammonium ions.

In option B, the bicarbonate ammonium root will be double-hydrolyzed. Because bicarbonate is hydrolyzed in solution to produce hydroxide, ammonium ion hydrolysis produces hydrogen ions, and hydrogen ions and hydroxides combine to form water, which promote each other, which is called double hydrolysis. Therefore, ammonium bicarbonate has the highest degree of hydrolysis of ammonium among all options.

In option C, ammonium bisulfate can ionize a large number of hydrogen ions and inhibit the hydrolysis of ammonium ions. So the ammonium in ammonium bisulfate is almost not hydrolyzed.

In option D, the degree of ammonium root hydrolysis in ammonium nitrate is normal.

The higher the degree of hydrolysis, the highest concentration of the substance at the same ammonium concentration. Because ammonium bicarbonate needs to provide additional ammonium ions for the double hydrolysis reaction while ensuring the ammonium ions.

Oh, I'll help you with this one.

Generally, ion questions are tested for "whether it can react" and "conservation of charge".

Well, calculate the negative charge: 2+2=4 and the positive charge: 2+1 ? =4 So you can see that? =2 - that is, the m has a positive charge of 2 units from the Qiaomeng.

Now let's see if there will be coexistence.

MgSO4 is soluble, MgNO3 can also be dissolved, it seems that Mg2+ can be short of dust - A is the correct answer.

Baso4 is insoluble, so no.

After the change, there are no other +2 ions.

Then the answer is a

What if you replace the h in the table with ferric iron ...

I choose CAThe cations in the solution are H+, NH4+, and the anions are OH- and Cl-. According to the conservation of charge, so there is.

c(cl-)+c(oh-)=c(nh4+)+c(h+)

b.According to the conservation of the quantity of matter, so C(SO3 2-) + C(HSO3-) + C(H2SO3) =

c.Due to the hydrolysis of Al3+, the amount of free Al3+ should be reduced, and there should be C(SO42-)> C(Al3+)+C(K+).

d.There is enough iron, so the reaction that occurs is 3Fe + 8Hno3 (dilute) = 3Fe (No3) 2 + 2No + 4H2O

The product is Fe(No3)2, so C(No3-)>C(Fe2+).

Divalent iron ions can undergo hydrolysis reactionFe2+ +2H2O = Fe(OH)2(S) +2H+

So c(h+)>c(oh-).

Of course, it is weakly acidic, so C(NO3-)>C(Fe2+)>C(H+)>C(OH-).

a Charge is conserved, correct.

b The material is conserved, correct.

d is correct, and finally all Fe(NO3)2 is generated, and it is weakly hydrolyzed, and the solution is acidic C error.

According to the conservation of charge, it should be 2C(SO42-) C(OH-)=3C(Al3+) C(K+) C(H+).

I should choose C.

Suppose that the mass concentration of the same substance is 1mol.

So. HCL is 1molH+ and 1molCl-Koh is 1molK+

and sell loss slip 1mol

oh-h2so4

It is. 2mol

H+ and 1molSO4

NH4Cl is 1molNH4 and 1molCl - so C should be chosen

is to choose C, the ion concentration i is equal to the square of the number of charges multiplied), where m is the concentration of the solution.

b Because the stem says that it is the amount and concentration of the same substance, not pH, the sulfuric acid is completely ionized with 2 hydrogen ions and 1 sulfate ion, and the others are 1:1

Oh, I'll help you with this one.

Generally, ion questions are tested for "whether it can react" and "conservation of charge".

Well, calculate the negative charge: 2+2=4

Positive charge: 2+1 ?=4

So you can see? =2--also filial piety bridge means that the m ion skillfully carries 2 units of positive charge.

Now let's see if there will be coexistence.

MgSO4 is soluble and dust-deficient, MgNO3 is also soluble, it seems that Mg2+ is OK --A is the correct answer.

Baso4 is insoluble, so no.

After the change, there are no other +2 ions.

Then the answer is a

Let's say it's all 1mol l.

then ammonium ions.

Concentration: 1mol l, 1mol l, 1mol l, 2mol l.