In the construction of cable racks, how much is the slack of the wire

Updated on society 2024-08-04
4 answers
  1. Anonymous users2024-02-15

    The flexible cable is different from the ordinary fixed installation cable, please refer to the following installation and precautions in the installation: 1The laying of the drag chain cable should not be twisted, that is, the cable should not be untied from one end of the cable drum or cable reel, but the cable should be rotated or the cable reel should be rotated first, and the cable can be hung up if necessary.

    The cable used in this case can only be obtained directly from the cable coil. 2.Attention must be paid to the small bending radius of the cable.

    3.The cables must be laid loosely side by side in the e-chainĀ®, as far apart as possible, separated by spacers or penetrated into the separation cavities of the bracket space, in which the gap between the cables should be at least 10% of the cable diameter. 4.

    The cables in the e-chainĀ® must not touch each other or get trapped together. 5.Both points of the cable must be fixed, or at least at the moving end of the energy chain.

    The moving point of the general cable....

  2. Anonymous users2024-02-14

    The safe ampacity of the square millimeter copper power cord is 28A. The safe ampacity of the 4 square mm copper power cord is 35A. The safe ampacity of the 6 square mm copper power cord is 48A.

    The safe ampacities of the 10 square mm copper power cord are 65A. The safe ampacity of the 16 square mm copper power cord is 91A. The safe current carrying capacity of the 25 square mm copper power cord is 120A.

    Estimation formula: Multiply by nine by 2.5 and subtract one straight up from the top. Thirty-five times 3.5, double in a group minus five.

    The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded. The number of pipe roots is two, three, four, eight, seven and six folds full of load current. Description:

    1) The formula in this section does not directly indicate the current carrying capacity (safety current) of various insulated wires (rubber and plastic insulated wires), but is expressed by "multiplying the cross-section by a certain multiple", which is obtained by mental arithmetic. As can be seen from Table 5 3, the multiplier decreases with the increase of the cross-section.

    2.5 times by nine, up minus one by one line" is talking about 2 5mm' and below various cross-section aluminum core insulated wires, the current carrying capacity of which is about 9 times the number of cross-sections. For example, 2 5mm' wire, the current carrying capacity is 2 5 9 22 5 (a). The relationship between the current carrying capacity and the number of cross-sections of the wire from 4mm' and above is to go up along the wire number, and the multiple is gradually reduced to L, that is, 4.

    Thirty-five times three .five, double and double groups minus five ", which means that the current carrying capacity of the wire of 35mm" is 3 5 times the number of cross-sections, that is, 35 3 5 122 5 (a). From 50mm' and above wires, the multiplier relationship between the current carrying capacity and the number of cross-sections becomes two two wire numbers in a group, and the multiples are subtracted by 0 5 in turn. That is, the current carrying capacity of the mm' wire is 3 times the number of cross-sections, and the current carrying capacity of the mm" wire is 2 5 times the number of its cross-sectional area, and so on.

    The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded. The above formula is based on the aluminum core insulated wire and the open application at an ambient temperature of 25. If the aluminum core insulated wire is laid in an area where the ambient temperature is higher than 25 for a long time, the current carrying capacity of the wire can be calculated according to the above formula calculation method, and then it can be discounted; When using not aluminum wire but copper core insulated wire, its current carrying capacity is slightly larger than that of aluminum wire of the same specification, which can be calculated according to the above formula.

  3. Anonymous users2024-02-13

    Answer]: When the cable is laid with the relaxation of the slip laying and the curvature of the waves, the reserved length of the cable should be calculated according to the full length of the cable. Ki Wan shoots.

  4. Anonymous users2024-02-12

    When calculating the length of cable laying, the additional length should be considered ().

    a.The cable laying gallop and crossover increase.

    b.Dead head at the end of the power cable.

    c.Cable to motor.

    d.The cables are laid in the tray.

    e.The cable is submerged into the base liquid into the distribution box.

    Correct answer: The cable front family lays the gallop and crosses the increase; power cable terminations; Cable to motor. The cable goes into the distribution box.

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