Knowing that the unequal 2x ten m a 1, the solution set of x n 4 is one l x 2, then what is the valu

Solution: (1) The meaning of the problem is m+2-3=0 mn -2n-3=0

The solution yields m=1, n=-1, or 3

But =4+12m>0 does.

When m=1 n=-1, m+2n=1-2=-1; When m=1 n=3, m+2n=1+6=7

2) When n=-1, the inequality is x +(a+1)x-3a>0 which =a +13a+1

When a<(-13-root42) 2 or a>(-13+root42) 2, the solution set of the inequality for 0, x is x<[-a-1-root(a +13a+1)] 2 or x>[-a-1+root(a +13a+1)] 2

When a=(-13-root42) 2, =0, the solution set of the inequality of x is a real number where x is not equal to (11 + root42) 4.

When a=(-13-root42) 2, =0, the solution set of the inequality of x is a real number where x is not equal to (11 + root42) 4.

When (-13-root, 42) 20 its =a+3a+9>0 The solution set of the inequality of x is x<[3-a-root(a+3a+9)] 2 or x>[3-a+root(a+3a+9)] 2

m+n)x+(2m-3n)<0

m+n)x<(3n-2m)

Since the solution set is: x<-1 3, then m+n>0 has: x<(3n-2m) (m+n).

i.e.: (3n-2m) (m+n)=-1 3

m+n=6m-9n.--m=2n

Again: m+n>0, so: m>0, n>0

So: (m-3n)x+(n-2m)>0

n*x>2m-n=4n-n=3n

That is: -n*x> vertical code 3n

Because: n>0

So the solution set is: x<-3

Description: m+n)x<(3n-2m).

Because the solution set is: x<-1 3, it is explained that m+n>0 if m+n<0

By (m+n)x<(3n-2m).

It can be seen that the coefficient of x is a negative number, so the solution set of x will change the direction of the equal sign of Yu Chang, and it is also fast that only a certain number > x can be obtained, which obviously contradicts x<-1 3, so m+n>0

m is greater than or equal to 2x2m-1

Suppose 2m-1 is to the left of m+1, i.e. 2m-1

m+1, then x is on the right again, i.e. there is no solution.

.And. The same, i.e., 2m-1=m+1, then x has no solution (because a number cannot be both less than a certain number and at the same time greater than that number).

That is, 2m-1 is greater than or equal to m+1 to meet the topic.

It can be solved: m is greater than or equal to 2

m+n)x+(2m-3n)<0

m+n)x<(3n-2m)

Because the solution set is: x<-1 3, then the gesture hall: m+n>0 has: x<(3n-2m) (m+n).

i.e.: (3n-2m) (m+n)=-1 3

m+n=6m-9n.--Slip to m=2n

Again: m+n>0, so: m>0, n>0

So: (m-3n)x+(n-2m)>0

n*x>2m-n=4n-n=3n

i.e.: -n*x>3n

Because: n>0

So the solution set is: x<-3

I hope it will be helpful to you.

Divide by 1-m at the same time on both sides of the two traces of the original pose inequality

The unequal sign has not changed the direction of the fight.

So 1-m>0

So m<1

Because the dismantling set of the sedan chair is x>-1, the direction of the square jujube of the unequal sign has not changed, so the two sides of the inequality are divided by a positive number at the same time.

i.e. x>-1 Teacher Yan.

x+2<2m

x<2m-2

x-m<0x follow-up:

m>=2m-2, I haven't figured it out here, can you explain it in detail? Thank you.

Follow-up: The solution set of the inequality group is the largest of the two large, and the second of the small is the smallest.

For example, x>3

x>5, then the solution set of the inequality group is x>5

For example, x<2

x<1, then the solution set of the group of inequalities is x<1

The solution set in the problem is x<2m-2

So it means m>2m-2 or m=2m-2

Solution: remove the denominator to get x-m 3 (3-m), remove the parentheses to get x-m 9-3m, shift the term, merge the same kind of terms to get x 9-2m, the solution set of this inequality is x 1, 9-2m = 1, solution m = 4

So the answer is: 4

Analysis of the m 2 test question: The solution set of the inequality (m 2) x>2 m is x< 1, and the direction of the inequality sign changes to obtain the result.

It is <> from the meaning of the title

Comments: The key to solving the problem is to pay attention to the solution of the unary inequality when the neutralization coefficient is 1, when the coefficient of the unknown is negative, the unequal sign should change the direction.