If you have any problems in your life, please answer them to the math masters

Does C count days? That is, is the number of days C's residence counted as 0?

Is the deposit of the new tenant equal to his monthly rent of 1,500 yuan?

If the total rent is $3,000, it stands to reason that you have to pay one mortgage and three rents.

s=(500+1100+1400)*4

Therefore, the gap of the first advance is.

B can take 150 yuan, that is, 100 + 50 = 150 (because he only advanced 4500-4400 = 100 more after the rent is reduced, the rent can be reduced by about 50 yuan for the remaining 16 days).

A can take 5300-3000-150 = 2150 A loses 4500-1500-2150 = 350, which is equivalent to bearing half of the rent of the one less person in the previous 14 days.

Why B's rent has changed from 1100 to 1000, and it is calculated as 500 1000 1500.

However, the problem probably lies in the distribution of the rent paid by the residents.

On the issue of prepayment of rent, A would have had to pay $1,500 and B had to pay $3,000.

However, in fact, when C was responsible for the rent of $4,500, A paid $3,000 and B paid $1,500, so when distributing the rent of D's household, A should be compensated more than half.

In fact, A deserves 3400 and B deserves 1900

Due to conflicting descriptions, this analysis is only valid if the condition is true.

If there are any errors or omissions, please point them out.

Quantile number.

income quantile: 1,2,3,4,5,6,7,8,9 I understand it to be the 10th percentile of the income sample. It is to divide the number of statistical income samples, and divide the number of samples into 10 points in order from low to high, 1 is the 1 quantile, that is, the number of samples with income equal to or lower than this number in the sample accounts for 10% of the total number of samples; Similarly, 2 is the 2 quantile, which means that the number of samples with income equal to or lower than this number accounts for 20% of the total sample size, and so on.

<> has a model, only the stool is pure and chaotic.

Replace the original x with -x or x+3 2, respectively

In the fifth question, first give the formula first: p(a u b)=p(a) +p(b) -p(a nb).

So p(a nb)=,a) p(a b)=p(a nb) p(b)= b) p(b a) =p(a nb) p(a)=

c)p (a/c) = p(a n c) /p (c)= d) p (b/c) = p(b n c) /p (c) =

Question 5: Set Questions. Just set the formula.

Question 6: I can't understand English.

I don't understand, this person is so smart.

The even term is n 2 and the odd term is (n + 1) 2

Upstairs is not right, people are asking the sum of the "alternate sum" of all subsets, and you are asking the "alternate sum" of the set itself.

55 Ah, it's called a series of equal differences, which means that every two adjacent numbers have the same difference.

There is also a proportional series, that is, the quotient of two adjacent numbers is equal.

There are differences that can be equal, there are those that can be compared, there are two values that can be equal before and after, and there are many other things, and the general topic will give more values, pay attention to the connection between the front and back, and find the law is OK.

Find more topics in this area, and if you do more, you will naturally be handy in the future!

I wish LZ progress in his studies!

This may be an intelligence test question, just look for it according to the rules, and the previous ones are just some parts of the idea.

It should be returned. As long as it makes sense, it should be okay.

85()25 This one is regular. You have to have a corresponding group to count!

Math problems, as long as you grasp the basics, you are almost fine, if you can get all the basic points (can do), then 110 points are absolutely fine.

But the basic questions want speed, so if you want to improve, you have to do more questions, mathematics is nothing more than practice, even more natural familiarity, as soon as you see the problem there are ideas, this is the best realm of mathematics. As for the difficult problems, there is no need to delve into them, the basic questions are the fundamentals, after all, the college entrance examination papers are based on the foundation, and the difficult questions are designed for those Tsinghua University and Peking University.

There are also wrong questions, so you must pay attention to them.

With shoes, such a score is still easy to mention, mathematics is nothing more than formulas, definitions, theorems, problem solving ideas, common question types will be, it is not a problem to take the test, my suggestion is, first read the book, catch the definition, understand the theorem, understand the formula of the ** postscript formula, do not do the problem first, first eat the textbook example questions, then the teacher usually assigns the after-class exercises, and finally study the exam questions, pay attention to the types and methods of inductive solutions.

I'm also a math fan, if you really want to learn math well, first learn the textbook thoroughly, ask the teacher and classmates if you don't know it, ask the practice questions in the back, don't see that the practice questions are simple, any problem is composed of a number of simple knowledge points, don't rush to do deeper questions when you can do the practice questions, take the practice questions and look at them repeatedly, and repeatedly think about how to solve the conditions in the questions if they change. Be sure to be proficient on the basis of being able to do. So you don't think that simple topics look boring, you start with the simple, after the textbook is thorough, and then choose some mid-range topics to do, it will not depend on how the answer is solved, whether there are any knowledge points that have not been learned, so that you can see a knowledge point to get a knowledge point, one by one, you must not be ambitious.

When you are very confident, you will be doing deep questions. 2 requirements, 1, must insist 2, a certain patience from not knowing to knowing, from knowing to proficient, after proficiency many things practice makes perfect. Come on, I believe you can do it.

I'm also from here.

Stick to a question type of question, work hard, and change it when you know it. I had the same score as you before the college entrance examination, and after such hard work, I scored 107 points in the college entrance examination. You can try it for a few days. Or add me.

I'm also a liberal arts student, and my experience is that the college entrance examination is the same as the high school entrance examination, there is a set of questions with a certain pattern, and the basic type of test has been fixed, but the questions are changing, and you'd better take the simulated test questions every time, and copy the types of questions that can't be done, and practice specifically. Then solve them one by one. If it's too difficult for liberal arts, don't do it.

It is recommended that you first take a look at Tao Pingsheng's "Elementary Number Theory" or the scum "Olympiad Classics", and you will feel that ——— mathematics you are learning now is so simple

Oh, there are many aspects of the exam, and I am not sure, I usually take 130, but I only took 100 or more in the college entrance examination, and it is usually more difficult than the college entrance examination.

First of all, find the teacher to draw the basic part of the math textbook after-class exercises, two to three days a chapter, so that you can do it again first, consolidate the foundation, usually do the paper with the teacher in class, practice the question type, if you have time, do the after-class exercises again, and reach proficiency in the knowledge points, if you still have time, do it the third time, strengthen the knowledge points, and you basically don't have to do it for the fourth time.

First read the example questions in the book several times and eat them thoroughly, draw inferences from one another, and the others will be easily solved, learn to expand your thinking, and never leave it...

From the meaning of the title, worker B is paid more than worker A. So there should be as few workers as possible. The requirement is that worker B is at least twice as large as worker A, so in order to minimize the number of worker B, worker B is set to be twice as large as worker A.

Such a situation is optimal. If for every one less worker A, there is one more worker B, then the salary should also be increased by 1000-600 = 400 yuan.

So, if worker A has x people, then worker B has 2x people.

x+2x=150

x=502x=100

50 600 + 100 1000 = 130,000 (yuan) so there are 50 workers in A and 100 workers in B, and the salary is 130,000 yuan.

Solution: If you recruit X workers in type A so that the minimum monthly wage is paid, then recruit type B workers (150-x).

From the meaning of the title 150-x >= 2x

The solution gives x<=50

So 50x600 + (150-50) x1000 = 130000 (yuan) (the more people in type A, the less the salary).

Answer: When recruiting 50 workers in type A, the monthly salary can be the least, and the monthly salary is 130,000 yuan.

Am I doing this right? It should be right.,I'm also a freshman in junior high school.,Hehe)

If the worker of type A is x, then the worker of type B is (150-x), and the monthly wage is y yuan.

Because the number of people in type B is not less than twice the number of people in type A, 150-x 2x can be obtained, that is, x 50

y = 600x + 1000 (150-x) = 150000-400x, from which it can be seen that the larger the x, the smaller the y.

So when x=50, y minimum = 130,000 yuan.

Answer:..

First, it is important to understand that the smaller the number of people with high wages, the smaller the total number of people paid, the smaller the total number of wages.

Second, if the number of people in type B is not less than twice the number of people in type A, then the number of people in type A cannot exceed one-third of 150, otherwise the total number of people will exceed 150 or the number of people in type B is less than twice the number of people in type A.

Thirdly, a third of 150 is 50.

The number of people in job A should be 50, and the number of people in job B should be 100.

At this time, the total monthly salary is: 50 600 100 1000 130000 (yuan).

Set up a type of work x people, then type B is 150-x, 150-x> = 2x that is, 50-x> = 0, x< = 50 so that 600x + 1000 (150-x) is the smallest, that is, 150000-400x is the smallest, then x takes the maximum 50 above is the minimum value, which is 130000

Suppose there is a person A who recruits a type of work, and there is a person B who recruits a type of worker who recruits B type of work, then it is known from the title:

a+b=150 (1)

b>=2a (2)

Informed by (1).

a+b=150

a=150-b

Obtained from (2).

b>=2a

b>=2*(150-b)

b>=300-2*b

b+2*b>=300

3*b>=300

b>=100

And the salary paid per month = 600 * a + 1000 * b

600*a+600*b+400*b

600*（a+b)+400*b

From (1): a+b=150

600*150+400*b

So the smaller b is taken, the better, so b=100

And a = 50 monthly salary = 600 * 50 + 1000 * 100 = 130000