Math problems, ask the master to solve, the right reward

24a b -6ab to defactor the factor, the common factor should be extracted as (6ab) to decompose the polynomial x (y-1) + x(1-y) = x(y-1) (x-1) into the factor: a(x-y) -b(y-x).

a（x-y)²-b(x-y)²

x-y)²(a-b)

Decomposition factor: a (x-y) -b(y-x) a (x-y)-b(x-y).

x-y(a²-b)

If x+y=2 xy=3

x+y)xy=x²y+xy²

x²y+xy²

6. Decompose the factor (find the process).

1）12x²yz-9x²y²

3x²y(4z-3y)

2）-x²-xy-xz

x(x+y+z)

7.Factoring (Finding the Process).

1）p（x-y）+q（y-x）

p(x-y)-q(x-y)

x-y)(p-q)

2）6（2a+b）（2a-3b）-3（b+2a）6（2a+b）（2a-3b）-3（2a+b）3(2a+b)[2(2a-3b-1)

3(2a+b)(4a-6b-1)

ab2、x（y-1）（x-1）

3、(a-b)（x-y）²

4、（x-y）²[a²(x-y)-b]

1) Original formula = 3x y (4z-3y).

2) Original formula = -x (x + y + z).

1) Original formula = p(x-y)-q(x-y) = (x-y) (p-q) 2) original formula = 3 (2a + b) (4a-6b-1).

According to the theorem that "two straight lines are parallel and the isotope angles are equal", the angle to the right of angle 1 and angle 2 are isotopic angles, so they are equal.

Then the sum of angle 1 and the angle to its right is 180 degrees, so the sum of angles 1 and 2 is 180 degrees.

ps: I don't understand what the use of your corner 3 is, always have to set a corner out, if you use angle 3 but two more steps

If a and b coincide, the angle is 180° in a straight line.

And then there's another angle, named angle 4, which is the other angle where A and C intersect.

Because a b is parallel so angle 2 = angle 4 because angle 1 + angle four = 180 so angle 1 + angle 2 = 180ok?

Didn't you say if the CD was a parallel line?

Because ab is a parallel line, the angle at which they are divided by a line is as large as the direction, and the opposite direction is 180 complementary, so a+b = 180

1) The two real roots of the equation x -6x+5=0 x1=1,x2=5,m(1,0)(0,5) are substituted, 1+b+c=0, c=5, b=-4, y=-x 2-4x+5

2)c(-5,0)

y=-x^2-4x+5=-(x^2+4x)+5=-(x+2)^2+9d(-2,9)

Area of ACD = 6 * 9 2 = 27

Right-angled triangle. According to the Pythagorean theorem, ae=5, af=2 5, and ef= 5 can be calculated. The trilateral length satisfies the Pythagorean theorem.

19. (1) substitution point (1, trillion only 4).

4=k×1+3

k=1y=x+3

2)x+3≤6

x Nachai 6-3

x 3 solution set.

x=。If you want to draw a picture, measure Xiaoli's height A and shadow length B, as well as the height C of the building, and praise the judgment.

Then the shadow of the Zen building ab is long d=bc a

The radius of the garden is r, then the side length of the inscribed regular triangle a=( 3)r; Perimeter l =3(3)r;

The side length of the inscribed regular triangle is b=2(3)r, and the perimeter l =6(3)r;

Their circumference ratio = l : l = 1 : 2;

The distance from the inner circumscribed triangle of the circle to each vertex is 2 3 of the height of the equilateral triangle, let the length of the side of the inscribed regular triangle be a, the height of the equilateral triangle is 3a 2, the radius of the circumscribed circle of the equilateral triangle is 3a 3, and the side length of the inscribed triangle of the same circle = 2 3a 3 tan30°=2a

The ratio of circumference is: 3a:6a=1:2, so the answer is: 1:2