Help with some practice problems for Primary 6 math.

8. Chickens and rabbits in the same cage, 26 more chickens than rabbits, a total of 274 feet, ask how many chickens and rabbits?

9. Spiders have 8 legs, butterflies have 6 legs and 2 pairs of wings, and cicadas have 6 legs and 1 pair of wings, and there are 21 of these three animals. With 140 legs and 23 pairs of wings, how many spiders, butterflies and cicadas are there?

The time and place are the same, and the height of the object is proportional to the length of the shadow.

So let's set the height of the tree x meters: x=x=6

1 .Cone volume = base area * height * 1 3

Cylindrical volume = base area * height.

It can be seen that 4 * cone volume = 4 * base area * height * 1 3 = cylinder volume = base area * 32, (the cylinder and cone base area are the same).

That is, 4 * 96 = base area * 32, then the ground area = 4 * 96 32 = 12 (square centimeters).

2.It can be seen that the volume of the cone + the volume of the cylinder = the base area * height * 1 3 + the base area * height = 54 (the base area and height of the two are equal).

Then 54 = 1 3 cylindrical volume + cylindrical volume = 4 3 cylindrical volume.

Then cylindrical volume = 54 * 3 4 = cubic centimeters).

Conical volume = 1 3 Cylindrical volume = (1 3)*

1.Cone volume = base area * height * 1 3 know base area = 3 * cone volume height = 12 * 3 3 = 12

2.To cut the largest cone, it is necessary to make the bottom area and height of the cone the largest, and the bottom circle should be tangent to the 4 sides of a surface of the cube, that is, the diameter of the bottom circle is the edge length of the cube 6 (the radius is 3), and the maximum height can only be the edge length 6, which is known by the formula Cone volume = 1 3 base area * height * = square of the radius * height * 1 3 =

1. Set the bottom area to A

The volume of the cylinder is 32a=96*4

a = 12 square centimeters.

2. Set the bottom area to be a and the height to be h

The volume of the cone is (1 3)*ah

The volume of the cylinder is Ah

So the volume of a cone of equal height is one-third of the volume of the cylinder, so the volume of the cone is 54 (1+3) = cubic centimeters, and the volume of the cylinder is cubic centimeters.

1. The bottom area of the cone is 12 * 3 = 12 square centimeters 2, this 6 cm is the diameter of the bottom surface of the cylinder, and it is also the height of the cone, so the volume of the cone is.

6*6 4)*6 3=18 cubic centimeters, I hope it can help you.

1. After pouring 4 times, the volume of water poured into it is 96 * 4 384 cubic centimeters, and the height of the water surface is 32 centimeters, so the bottom area of the cylindrical bucket is 384 32 12 square centimeters, because the cylindrical bucket is equal to the bottom of the cone, so the bottom area of the cone is 12 square centimeters.

2. A cylinder and a cone, their base area and height are equal, then the cone volume 1 3 cylindrical volume, the cone volume is regarded as 1 part, then the cylindrical volume is 3 parts, a total of 4 parts 54 cubic centimeters, then each part is 54 4 cubic centimeters, the cylindrical volume is 3 parts cubic centimeters, and the cone volume is 1 part cubic centimeter.

Fill in the blank 1: According to the formula of cone volume v 1*3*s*h then the bottom of s is 3v h 3*12 3 12 square centimeters.

Fill in the blank 2: Use a cube of wood with an edge length of 6 cm, cut the largest cone, the height of this cone is 6, and the diameter of the bottom circle is also 6, v 1 3*s*h *3 2*6 3 cubic centimeters.

Cone volume = base area * height * 1 3 = square of radius * height * 1 3 volume of the cylinder = base area height.

1 The base area of the cone is s and the height is h. 1 3sh=96 volume of the cylinder = s * 32 = 4 * 1 3sh = 4 * 96 solution s = 12

2 sh+1 3sh=54 sh= 1 3sh=1 1 3sh=12 h=3 to get s=122 r=3 volume=3*3*

Remember: the volume of the cone is one-third of the volume of the cylinder with the same height at the same bottom.1 Let the base area of the cone be x square centimeters.

32x÷4=96×3

8x=288

x=36A: The base area of the cone is 36 square centimeters.

2. Cone: 54 4=

Cylinder: 1. The volume of a cone is 12 square centimeters, the height is 3 centimeters, and the bottom area of this cone is (12) square centimeters?

2. Use a cube of wood with an edge length of 6 cm to cut the largest cone, and the volume of this cone is ( ) cubic centimeters.

12 square centimeters conical cylindrical 12 The last question will not.

Fill in the blank 1The base area is 12 divided by 1/3 in the division by 3

2.6 times 1/3 and then 6 more published!

1. Cuboid, base area, height, volume.

2, square decimeter 3,

1 cuboid, height, volume.

2 v=15*15* (36-34)

It's pi.

Hello. It's been a long time since I've done a topic like this, I don't know, right?

1. Divide the bottom surface of the cylinder into many equal small sectors, and then cut the cylinder to form an approximate (cuboid), its base area is equal to half of the side area of the cylinder, and its height is higher than the (radius) of the cylinder, in this process, (volume) remains unchanged.

2. Side area = bottom perimeter height = 2 r 5 = take = r = 2

Base area = r r=2 2 square decimeters.

3. According to the principle of buoyancy, the aquatic weeds are completely immersed in the water, and the volume of the water discharged = the volume of the aquatic weeds.

Water discharge volume = cylindrical bottom area Water surface rising height.

Where, cylindrical base area = (diameter 2) (diameter 2) So, aquatic weed volume = (30 2) (30 2) (36-34) = 1413 cubic centimeters. Above.

1. Cuboid, half of the side area, radius, volume.

2. Square decimeter Decimeter square decimeter cubic centimeter 30 2=15 centimeters Sorry, I won't play the operation symbol, which means divide, * represents multiplication, and the square is replaced by multiplying twice.

1.Box, side area, radius, volume.

2.2* *r*5=, s= *r*r=4* ,= is the pi).

3. r=30/2=15, v=π*r*r*（36—34）=450π

1.The bottom area of the cuboid is high in volume.

Let the distance be s km.

At the time of the first encounter, A walked a distance of 35 km; B travels a distance of (s-35) km;

Since the time is the same, their velocity ratio is 35: (S-35);

At the second encounter, A travels a total distance of (s+28) km from A; The total distance traveled by B from B is (2s-28) km;

The time is the same, and their velocity ratio is: (s+28):(2s-28) so that there is: 35: (s-35) (s+28):(2s-28) solution: s 77 (km).

35*3-28

77 (km).

The distance between the two places is 77 kilometers.

The two places are located at a distance of x kilometers.

The first encounter passes x km, and the second encounter passes 3x km for the time ratio of the encounter = 1:3

The time of car A is 1:3, and the distance traveled by car A is also 1:33 35=(x+28).

x=105-28

x = 77a and b are 77 km apart.

For the first encounter, A and B traveled a total of 1 full course, A traveled 1 35 kilometers for the second time, A and B traveled a total of 3 full courses, A traveled 3 35 kilometers At the same time, A traveled a full journey of 28 kilometers.

A and B are separated from each other.

35 3 28 77 km.

A and B are x kilometers apart, the speed of A is V1, and the speed of B is V235 V1=(X-35) V2

x+28)v1=(2x-28)

Solution x=77

Solution: 35 3 105 km.

105 28 77 km .........The distance between A and B.