There are a total of 8 chickens and rabbits in the same cage, with a total of 22 legs, and how many

If there are x chickens, then rabbits have (8-x); According to the title:

2x+4(8-x)=22;

32-2x=22;

2x=10;

x=5;So there are 5 chickens and 3 rabbits.

Very simple equation.

Rabbit A Chicken B

1)a*4+b*2=22>>>a=(22-b*2)/4>>>a=22/4-b*2/4>>>a=

2)a+b=8

b=5a=3

Solution: There are x chickens and rabbits (8-x).

2x+4（8-x）=22

2x+32-4x=22

4x-2x=32-22

2x=10x=5

If the rabbit asks for it, then he says 8 in total, then you have 8-5=3.

A: There are 5 rabbits and 3 chickens.

Let's say all 8 are rabbits.

8x4=32 (only).

32-22=10 (only).

10 (4-2) = 5 (only).

8-5=3 (only).

Answer: There are 5 chickens and 3 rabbits.

First of all, look at the rabbit as a chicken, 16 in total. Then 22 minus 16 and divide by 2 is the number of rabbits, and then the number of chickens is five.

Elementary school solution!!

1.List method.

Chicken number 24 29 34 39

Number of rabbits 0 5 10 15

Total legs 48 78 108 138

A: There are 39 chickens and 15 rabbits.

2.Solution:

Rabbits have (138-24 2) (2+4)=15 chickens have 15+24=39.

A: There are 39 chickens and 15 rabbits.

3.Equation method.

Solution: If there are x rabbits, then there are (24+x) chickens.

4x+2（24+x)=138

6x=90x=15

24 + 15 = 39 pcs.

A: There are 39 chickens and 15 rabbits.

Premise: Chickens have 2 legs and rabbits have 4 legs.

If there are rabbits with A, then chickens have A+24.

4a+(a+24)×2=138

a=15 so there are 15 rabbits and 15 + 24 = 39 chickens.

The formula in the middle is based on the total number of legs.

1. The first digit is the same, and the sum of the two mantissa numbers is equal to 10 The two-digit multiplication method: Ten digits plus 1, the resulting sum is multiplied by the ten digits, and the number is the first product, and the single digit is multiplied, and the number is the back product, and no ten digits are made up with 0.

2. The first digit is the same, and the mantissa is not equal to 10 two-digit multiplication method: the two first digits are multiplied (that is, the square of the first digitude), the number is taken as the front product, the sum of the two mantissa numbers is multiplied by the first place, the number is taken as the middle product, the full ten is one, the two mantissa are multiplied, and the number is taken as the back product.

3. The multiplier is the same, and the multiplier is 10 two-digit multiplication method: the first multiplier is added to 1, and the sum obtained is multiplied by the first digit of the multiplier, and the number is the first product, and the two mantissa numbers are multiplied, and the number is the back product, and there are no ten digits with 0 to make up.

4. The sum of the first and last digits of the multiplier is 10, and the multiplication method of the first and last digits of the multiplier is the same: similar to the method of helping 6. The product of the two first digits multiplied plus the single digit of the multiplier, the number is taken as the first product, and the two mantissa numbers are multiplied, and the number is taken as the back product, and there is no ten digits to make up 0.

First of all, we know that chickens have 2 legs and rabbits have 4 legs.

So let's assume that there are x chickens. Then the rabbit has the X-24

The relationship between their legs is 2x+(x-24)*4=138, which gives x=39

39 chickens ,,, 63 rabbits.

(1) If there are x chickens and y rabbits, then there are 2x chicken feet and 4y rabbit feet, and the equation is obtained.

x-y=24

2x+4y=138

The solution gives x = 39 y = 15

A: There are 39 chickens and 15 rabbits.

2) If there are x chickens, then there are (x-24) rabbits, and the equation is 2x+4(x-24)=138

The solution is x=39

then the rabbit has x-24=15.

A: There are 39 chickens and 15 rabbits.

In this problem, there are two equiquantitative relations, one is that there are 24 more chickens than rabbits, and the second is that chickens and rabbits have a total of 138 legs.

If there are x chickens, then the rabbit has (8-x); According to the inscription of Heng Ting:

2x+4(8-x)=22;

32-2x=22;

2x=10;

x=5;So there are 5 chickens and 3 rabbits.

Set the rabbit to have x beside it, and the chicken has (x-5) in the Qi Sleepy only to sell the thought, get:

4x+2*(x-5）=80

Solution: x=15

15-5=10 (only).

A: There are 10 chickens and 15 rabbits.

Subtract 24 chickens, there are as many chickens and rabbits, and there are 90 left in the legs, 90 6 = 15, so there are 15 rabbits, and the chickens are 15 + 24 years old is 39.

It is known that the total number of heads and chicken thighs are more than exempt

The number of legs is many, and ask the chickens and rabbits how many they are.

Number of chickens = (4 times the total number of heads + number of feet apart) 6

Number of rabbits = total number of heads - number of chickens = total number of heads - (4 times the total number of heads + number of different feet) 6 = (2 times the total number of heads - number of different feet) 6

Number of chicken feet = 2 times the number of chickens.

Number of rabbits = total number of heads - number of chickens.

Number of rabbit feet = 4 times the number of rabbits = 4 times (total number of heads - number of chickens) = 4 times the total number of heads - 4 times the number of chickens.

The number of feet = the number of chicken feet - the number of rabbit feet = 2 times the number of chickens - (4 times the total number of chickens - 4 times the number of chickens) = 6 times the number of chickens - 4 times the total number of heads.

6 times the number of chickens = 4 times the total number of heads + the number of different feet.

Number of chickens = (4 times the total number of heads + number of feet apart) 6

Number of rabbits = total number of heads - number of chickens = total number of heads - (4 times the total number of heads + number of different feet) 6 = (2 times the total number of heads - number of different feet) 6

Suppose the number of rabbits in it is x

Then the number of chickens is the total number of heads - x

The number of feet = the number of chicken feet - the number of rabbit feet = 2 (total number of heads - x) - 4x = 2 times the total number of heads - 6x

6x = 2 times the total number of heads - the number of feet in difference.

x = (2 times the total number of heads - the number of feet in difference) 6

Let's say the number of chickens in it is x

Then the number of rabbits is the total number of heads - x

The number of feet = the number of chicken feet - the number of rabbit feet = 2x-4 times (the total number of heads - x) = 6x - 4 times the total number of heads.

6x = 4 times the total number of heads + the number of different feet.

x = (4 times the total number of heads + the number of different legs) 6

There are x chickens.

4*（20-x）-2x=44

80-6x=44

6x=36x=6pcs.

There are rabbits = 20-6 = 14.

It's very simple.

There are 24 more chickens, and there are 24 x 2 48 legs.

The rest is 90 legs, and these are the legs in which the number of chickens and rabbits is the same.

There are x rabbits, and there are also x chickens in it.

2x+4x＝90

x=15 then there are 15 rabbits.

The total number of chickens is 24+15 39.

2 chickens. 5 rabbits.

Or. 7 chickens.

2 rabbits. Divide 24 into points.

and multiples of 5.

Then when the number of chicken thighs is 4.

There are 2 chickens. Rabbit legs count 20

There are 5 rabbits. When the number of chicken thighs is 14.

There are 7 chickens. The number of rabbit legs is 10, and there are 2 rabbits.

Suppose the chickens and rabbits are trained to be sensitive.

Blow a whistle All chickens and rabbits each lift one leg That is, one remaining = 22-8 = 14 and another whistle All chickens and rabbits each lift one leg The chickens all fall down on the bright branches The rabbit stands on both legs immediately The second remaining = 14-8 = 6

So the number of rabbits = 6 2 = 3

Number of chicken key types = 8-3 = 5

Let's say it's all rabbits.

4 * 8 = 32 records.

32-22 = 10 slip bridges.

Chicken 10 Shin Meng (4-2) is not stupid = 5.

Rabbits 8-5 = 3.