Excess barium hydroxide and sodium bisulfate reaction ion equation

For an excess of a substance, follow the principle of "less determines more", because the amount of SO4 2- is small, so SO4 2-+BA2+=BASO4, for hydrogen ions, too, H++OH-=H2O, the chemical equation should be like thisNaHSO4+BA(OH)2=BASO4 +NAOH+H2O, the solution is alkaline, not neutral. The ion equation should be BA2++OH-+H++SO42-=BASO4 +H2O, dare to question the answer!

You can start by writing the reaction equation.

ba（oh）2 + 2nahso4 ==== baso4 + na2so4 + 2h2o

Then write it as ionic.

ba2+ +2oh- +2na+ +2h+ +2so4 2- ==== baso4 + 2na+ +so4 2- +2h2o

Then remove the same on both sides, and it will be the same as what you gave.

ba2+ +2oh- +2h+ +so4 2- ===baso4 + 2h2o

No, this is the ionic equation for sodium bisulfate excess.

No, you wrote about nahso4 overdose. It should be H+ +SO42- +Ba2+ +OH-=BASO4+H2O

The ionic equation of the reaction of sodium bisulfate and hydroxide imitation barium is the same as that of the reaction of sulfuric acid piedou and barium hydroxide, which is the same as the number of b2+ +2oh- +2h+ +SO42-=baso4 +2H2O. That's it, glad to have your question.

1. Add excess sodium bisulfate to the barium hydroxide solution.

Solution. ba2+

2oh-2h+

so4(2-)=baso4↓+2h2o

Sodium bisulfate and barium hydroxide react 1:2, both with SO4(2-) and with H+.

ba(oh)2+2nahso4=baso4↓+2h2o+na2so4

2. Add an appropriate amount of barium hydroxide solution to sodium bisulfate to make sulfate.

It happens to settle completely.

ba2+oh-

h+so4(2-)=baso4↓+h2o

Sodium bisulfate and barium hydroxide react 1:1.

ba(oh)2+nahso4=baso4↓+h2o+naoh

3. Pass in FEI2 solution.

Chlorine gas is added, and the ratio of chlorine to iodine is 2:3.

4cl2+6i-

2fe2+=8cl-

2fe3+3i2

The ratio of chlorine to iodine is 2:3, which is difficult to understand. If you count it by the Cl2 molecule and I-, which is more likely, it is.

3fei2+4cl2=2fecl3+fecl2+3i2, all replaced, and then partially oxidized.

Extended Information: Chemical equation for the reaction of sodium bisulfate and barium hydroxide.

and ion equations:

1. It happens to be completely neutralized, indicating that H+ and OH just react completely, as follows:

The chemical equation is: 2NaHSO4 + BA(OH)2=BASO4 +2H2O+Na2SO4

Ion equation: 2 hydrogen ion + sulfate ion + barium ion + 2 hydroxide ion BaSO4 + 2H2O

2. It happens to be completely precipitated, indicating that the sulfate ion and the barium ion are just completely reacting, as follows:

Chemical equation: NaHSO4 + BA(OH)2 BASO4 +H2O+NaOH

The ion Yu Qingju equation coincides: hydrogen ion + sulfate vertical bigen ion + barium ion + hydroxide ion BASO4 + H2O

The reaction needs to consider the amount of reactants.

To put it simply, namely:

2nahso +ba(oh) [small amount] ==baso na so +h o

ba(oh) +nahso [small amount] = baso naoh +h o

Strong alkaline: Ba(OH) has strong alkalinity, and its alkalinity is the strongest among alkaline earth metal hydroxides, which can make phenolphthalein.

The solution turns red, purple litmus.

Turn blue. Ba(OH) absorbs carbon dioxide from the air.

Converted into barium carbonate.

ba(oh)₂ co2 ==baco3↓ +h₂o

Ba(OH) can have a neutralization reaction with acid, in which sulfuric acid forms a precipitate: BA(OH) +H2SO4==BASO4 +2HO

It is mainly used to make special soaps and insecticides, and is also used for hard water softening, beet sugar refining, boiler descaling, glass lubrication, etc., for organic synthesis and barium salt preparation.

Sodium bisulfateand barium hydroxide completely neutralizedChemistry Broad Profile EquationAs follows:

1. NaHso sufficient: 2NaHso +BA(OH) = BASO +NA SO +2HO

2. BA(OH) sufficient: NAHSO Xuwei + BA(OH) = BASO +NAOH+H O

Sodium bisulfate and barium hydroxide are completely neutralizedIonic equationsAs follows:

1. Nahso sufficient: 2H +SOBA +2OH =BASO +2HO

2. BA(OH) Sufficient: H +SO BA +OH Caution = BASO +H O

The reaction needs to consider the amount of reactants.

To put it simply, namely:

2nahso +ba(oh) [small amount] ==baso na so +h o

ba(oh) +nahso [small amount] = baso naoh +h o

Strong alkaline: Ba(OH) has strong alkalinity, and its alkalinity is the strongest among alkaline earth metal hydroxides, which can make the phenolphthalein solution turn red and the purple litmus blue.

Ba(OH) absorbs carbon dioxide from the air and converts it into barium carbonate.

ba(oh)₂ co2 ==baco3↓ +h₂o

Ba(OH) can neutralize and reverse the front with acid, and the precipitation is formed in case of sulfuric acid: BA(OH) +H2SO4==BASO4 +2HO

It is mainly used to make special soaps and pesticides, and is also used for hard water softening, beet sugar refining, boiler descaling, glass lubrication, etc., and is used for organic synthesis and preparation of barium and cale salts.

Hello, because there is an excess of H ions (there are hydrogen ions, sodium ions, and bisulfate in the sodium bisulfate solution), there is no OH root left after the reaction, and the relationship between OH root and barium ion is 2:1, so in the ion equation, OH root must be twice as much as barium ion.

Summary. Hello, happy to answer your questions.

Add a small amount of barium hydroxide solution, because the amount is small, both hydroxide groups participate in the reaction; Excess barium hydroxide solution is added, and only one hydroxide participates in the reaction;

A small amount of barium hydroxide: Ba2+ +2OH- +SO42- +2H+ =BaSO4 +2H2O;

Excess barium hydroxide: Ba2+ +OH- +SO42- +H+ = BaSO4 +H2O

Hope it helps. Please give a thumbs up, thank you! You can pay attention to Mr. Xiao Wang to facilitate the next contact. Recently, the platform has launched voice and ** functions, you can try it, it is a good choice!

What is the difference between the ion equation of adding a small amount of barium hydroxide solution to sodium bisulfate and an excess barium hydroxide solution.

Please wait a minute.

Hello, happy to answer your questions. Add a small amount of barium hydroxide solution, because the amount is small, both hydroxide groups participate in the reaction; Excessive barium hydroxide solution was added, and only one hydrogen oxygen root participated in the reaction; A small amount of barium hydroxide: Ba2+ +2OH- +SO42- +2H+ =BaSO4 +2H2O; Excess barium hydroxide:

ba2+ +oh- +so42- +h+ =baso4 +h2o hope it helps. Please give a thumbs up, thank you! You can pay attention to Mr. Xiao Wang to facilitate the next contact.

The chemical equation of Ba2+ +2H+ +2OH- +SO42-=BASO4 +2H2O is BA(OH)2+2NaHSO4=BASO4 +2H2O+Na2SO4

A small amount of sodium bisulfate is as follows:

The chemical equation for Ba2+ +H+ +OH- +SO42-=BASO4 +H2O is BA(OH)2+NaHSO4=BASO4 +H2O+NAOH