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1, the original formula = (a-b+b+a)(a-b-b-a)=-4a b 2Original formula = (m+n+2m)(m+n-2m) = (3m+n)(n-m)3 original formula = -9a 3x 2(1-2a) (-9a 3x 2)=1-2a =(1+ 2a)(1- 2a).
4.Original formula = x (a-b) + b-a = (a-b) (x -1) = (a-b) (x+1) (x-1).
6.(3x-1/11)²=9x²-6x/11+1/121=mx²+mnx+1/121
m=9mn=-6/11
n=-2/33
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1:(a-b)²-b+a)² =(a-b+b+a)(a-b-b-a)=2a·(-2b)=-4ab
2:(m+n)²-4m²=(m+n+2m)(m+n-2m)=(3m+n)(n-m)
3: (9a to the 3rd power x + 18a to the 5th power) divided by (9a to the 3rd power x).
9a³x²(1-2a²)÷9a³x²)
1-2a²4:ax²-bx²+b-a=x²(a-b)-(a-b)=(a-b)(x²-1)=(a-b)(x+1)(x-1)
5: 4x-(y 9) = (2x+1 3·y) (minus one-third y).
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Decompose the factor(m+n-2mn)(m+n-2)+(mn-1) =(m+n) -2mn(m+n)-2(m+n)+4mn+m-2mn+1
m+n)²-2(m+n)(mn+1)+(mn+1)²=(m+n-mn-1)²
m-1)²(n-1)²
Given a+b+c=7, and (a+b)-c =14, then a+b-c=2(a+b)-c =14
a+b+c)(a+b-c)=14
a+b+c=7
a+b-c=2
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They square their plus twice for their conspiracy.
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2 + b2 dispense 2ab
So, 2b2 allocation + 2 + b2 allocation +1 a 2b 2 allocation 2 from the beginning 1
That is: 4ab a 2 b 2 + 2 ab +1 is: 2 b 2-2ab +1 0
ab-1)2≦0
ab-1 = 0
So, ab initio = 1
Ab initio = 1 substitution The original formula is: 1 + 2 + b 2 allocation + 1 = 4 so, 2 + b 2 allocation = 2
Out(ab) 2 = 2-2ab + b2 = 0 so, = b.
and ab = 1
So, a = 1, b = 1 or a = -1, = - 1 I want you to be happy! I hope to help you, if you don't know, please, I want to learn and progress! o(∩_o
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It should be 1-a -b +2ab or 1-a -b -2ab 1-a -b liquid zen + 2ab
1-(a²-2ab+b²)
1-(a-b)²
1-a+b)(1+a-b)
1-a-b Zen Burial-2ab
1-(a²+2ab+b²)
1-(a+b)²
1-a-b)(1+a+b)
Happy New Year.
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4m squared minus 9n squared minus 4m plus 1
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Hello life, the solution is as follows:
1)(m 2+n 2) 2-4m 2n 2 solution: =m 4+2m 2n 2+n 4-4m 2n 2m 4-2m 2n 2+n 4 >>>More