Knowing a b 5, ab 2, find the value of 2a 3ab b a ab 2b

Because a b = 5 and ab = 2

2a²-3ab-b²-a²+ab+2b²= a²-2ab+ b²=5-4=1

Because ab-2 +a +b -5 =0

then ab-2 =0, and |a²+b²-5︳=0ab-2=0，a²＋b²-5=0

ab=2，a²＋b²=5

So: 2a -3ab-b -a +ab+2b = a -2ab+ b =5-4=1

If the known condition becomes ab-2 +a +b -5 =0, the value of 2a -3ab-b -a +ab+2b can be found.

a²＋b²=5，ab=2

then a b -2ab = 1

a²＋b²+2ab=9

Because ab-2 >=0 |a b 5 >=0 and because the sum of the two equals 0

So ab-2 =0 and |a b 5 = 0 so we can get a b = 5, ab = 2, and then 2a 3ab b a ab 2b = 1

2a²－3ab－b²－a²＋ab＋2b²=a²＋b²－2ab=5-2x2=1

Change the known condition to ab-2 a b 5 =0The value of the above equation can be found.

The above equation can be changed to ab-2=0 and |a²＋b²－5︳=0.get a b = 5, ab = 2,

It's the same, from the first formula, we know that ab minus 2 is zero, so ab is 2, and the second one must be zero, because the sum of squares and absolute values must be non-negative numbers, and if they add up to zero, then the two formulas must be 0

If a=5, and b=15, then.

3a²-2b²=5...1)

a²+6b²=15...2)

a 2 = 3 then b 2 = 2

a -a b Ninze Ye + 4b Mark.

It's a +B.

a²+b²-3)²=25

a²+b²-3=±5

a + b = -2 (rounded off because a + b 0) or a + b = 8

So a +b = 8

I'm glad to answer your questions and wish you progress in your studies! The [the1900] team will answer the questions for you.

(a²+b²-3)²=25

a²+b²-3=±5

a +b = -2 (rounded off because a +b 0) so a +b = 8

And because a = b

So a = 4;b²=4

Therefore a=2 b=2;

or a=-2 b=2;

or a=-2 b=2;

or a=-2 b=2;

There are 4 sets of answers.

∵(a²+b²-3)²=25

a + b -3 = 5 or -5

a +b = 8 or -2

But a + b 0, so a +b = -2, round off so a +b = 8

Hello: The two formulas are added.

a²+ab+b²+ab=3-2

a²+2ab+b²=1

Subtract the two formulas. a²+ab-（b²+ab）=3+2

a²—b²=5

If you don't understand, you can ask.

If it helps, remember to adopt it, thank you.

Good luck with your studies!

a²+2ab+b²

a²+ab)-(b²+ab)

5 Glad to answer for you, I wish you progress in your studies!

a²+2ab+b²=(a²+ab)+（b²+ab）=3-2=1

a²a—b²=(a²+ab)-（b²+ab）=3-(-2)=3+2=5

If it helps you, please remember to adopt, o( o thank you.

Add the two formulas a +2ab+b =1

The two formulas are subtracted a — b = 5