The first power of the first power of the application problem, the first power of the first power of

Start by converting words into numbers.

7 times 10 to the power of 7 = 7 10 7

4 points 4 meters = 3 square kilometers multiplied by 10 =

Total length of cars = number of cars Length of a single car = 7 10 7 So about can be rowed.

The next question should be asked, which is equivalent to the length of tens of thousands of "thousand" Great Walls?

Note where the quotation marks are placed, 10,000 = 1 10 4 so the answer = the total length of the car The length of the single Great Wall 10 4

A: About 7 10 7 meters.

It is equivalent to the length of 10,000 Great Walls.

The total length of the car is meters).

The length of the Great Wall is meters).

The length of the car is [times] of the Great Wall.

The 7th power of 5 is about 72 times the size of the Great Wall.

I don't have a language or a book now, so I'm sorry to dismantle the Yuansi Brigade and collapse.

OK. Set the width to x meters and the length to meters.

x 7171 71 between 65 and 75.

Between 100 and 110.

So yes.

If the width is x meters, then the x* x is between 86 meters and 87 meters, which does not meet the requirements of the international competition venue.

Let the width be x, then so x=71 is a little less 7560 71=106 so yes.

Solution: Let the width be x and the length be .

x*x=5040

x is less than 71 (because 71*71=5041).

Answer; Yes.

Question 1: The first time you fold it in half, the thickness becomes millimeters.

The second time it is folded in half, the thickness becomes millimeters.

The third time it is folded in half, the thickness becomes millimeters.

The 20th time it is folded in half, the thickness becomes millimeters.

Question 2: The first time, 1 2 articles.

The second time, 1 2 2 articles.

The third time, 1 2 3 articles.

Nth time, 1 2 n

According to the title. It's more than 1,000.

Then 2 n is closest to 1000 is 1024

At this time, n = 10 times, that is, at most 10 times, you can get more than 1000 pieces.

1) After folding in half 1 time, the thickness is mm.

After folding it in half twice, the thickness is millimeters.

After folding in half 20 times, the thickness is 2 20* mm.

2) 1000 about = 1024 = 2 10 so at least 10 times.

Once and twice.

20 times to the 20th power of 2 = 2 20 = 1048576

1000 = 1024 = 2 10 so 10 times.

1.The first time it is folded in half, the thickness becomes millimeters.

The second time it is folded in half, the thickness becomes millimeters.

The third time it is folded in half, the thickness becomes millimeters.

The 20th time it is folded in half, the thickness becomes millimeters.

2.Divide 1000 by 2 to find the maximum approximation.

The person riding in the broken car (set as Group A) gets out of the car first and walks, and the car that is not broken continues to move forward, and the person other than the driver (set up Group B) gets off at a certain distance from the hardest-hit area, and then the car returns to pick up the person who has walked a certain distance from Group A. Eventually, the car drove to its destination, and those in Group B had just arrived at their destination.

If the person in group A walks for x1 hour for the first time, and the time for the second walk (the time when the car returns to pick up) is x2 hours, the equation can be as follows:

x1=60x2+5x2

2、（15-60x1-5x1-5x2）/5=(15-5x1-5x2)/60

According to these two equations, we can calculate: x1=, x2=

Converted into minutes, it is calculated as: x1=, x2=

So, the total time is: minutes, plus the initial 18 minutes that have been traveled, and the last time is: minutes.

Based on the speed of the car, it was known that the car broke down 15 kilometers from the disaster area, and it had taken them 18 minutes by this time. At this time, the car that was not broken continued to move forward, and it took 15 minutes to reach the disaster area, and at the same time, the four people on the broken car got out of the car and walked. The car that wasn't broken arrived and immediately returned to pick up the four men.

The key to this question is to ask for the time it takes to get out of the car and meet people.

Solution: Let the encounter time be x, and the column equation (5+15) x+5 15 60=15 x=11 52

At this time, the car has already used 18 + 15 + 11 52 60 = min) The remaining distance is 11 52 60 km).

The car still needs to be divided after the rest of the journey, and it will take a lot of time to reach the disaster area) A: The shortest time to reach the disaster area on time is minutes.

Disagree with the above points.

It can be reached within the specified time, but the minimum time is about a minute.

The calculation process is as follows:

15 60 = hours.

Kilometers, kilometers. The total time of the hour is 18 + approx. = minutes.

15 60 = hours This is the time it takes for the car to reach the disaster area (15 km) in kilometers This is the distance it takes for the car to walk in kilometers during the time it arrives in the disaster area This is the total number of kilometers traveled by the car when it returns to pick up the remaining people This is the time it takes for the car to pick up the remaining people, and this is the distance it takes for the car to pick up the remaining people and return to the disaster area after returning to the disaster area.

This is the time it takes for the car to get to the disaster area.

Minutes This is the total time spent traveling.

The solution to this kind of problem is to draw a map, and the idea of each route is clear, the upstairs idea is different from mine, the upstairs idea is correct Mine is that the car arrives at the disaster area and returns to pick up the remaining people, and the upstairs idea is to let the car people get down and walk after driving a distance, and the car to pick up the remaining people, I think this route should be more time-saving

Suppose the car meets the rest of the people after returning from the hardest-hit area for t minutes.

t+(t+15) 12=15 km, get t=55 4 13*12=

Total time = 18 + 15 + 2t = minutes.