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Anonymous users2024-02-051 a) 1km min = 60km h distance divided by time equals speed, that is, how to change the speed per minute and per hour needless to say?
b) 60*5=300km time multiplied by speed equals distance traveled.
2 3:2 The reciprocal ratio is their inverse ratio, or the result is 1 a:1 b=1 1 2:1 1 3=2:3
So a:b=1 2:1 3=3:2
3 n=8 The sum of the outer angles is 360 The inner angles of the triangle are 180, and each additional angle is 180 more, so the inner angle is 1080, which is an 8-sided shape.
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Anonymous users2024-02-041., 15 branches 15 km So 1 minute 1 km So 1 hour 60 km.
5 hours course 300 km.
2, 1/A : 1/B = B :A and so on 2:3, so how much do you say A : B (3 2).
3. In a regular n-sided shape, if the size of its inner angles is five times the size of the outer angles, then the outer angles are equal to 180 6 equals 30 The sum of the outer angles of all polygons is 360 degrees So n is equal to 360 30 12
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Anonymous users2024-02-031,,,a]15min=, after 15km, 60km in 1 hour, which can be expressed as 60km h
b]5*60=300km
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Anonymous users2024-02-02The modulo of vector a is 10 (i.e., the length is 10), and since the definition of the unit vector is modulo 1, dividing the vector a by its own modulo 10 gives the vector b = (3 5, -4 5) parallel to a and in the same direction, and dividing the vector a by -10 gives the vector c = (-3 5, 4 5) that is parallel to a and in the opposite direction. So the answer is b = (3 5, -4 5), c = (-3 5, 4 5). (It's easy to miss this question.)
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Anonymous users2024-02-01Take a closer look at the solution to this problem.
It is known that in the quadrilateral ABCD, AB CD, ACED is used as a parallelogram for the edge, and the DC is extended to intersect EB at F, and the verification is EF=BF
Proof: Extension of EC to M
ACED is a parallelogram (known), ad ce, ad = ce (properties of parallelograms).
ad//cm。
ab cd, quadrilateral amcd is the parallelogram (definition of parallelogram), ad=cm (property of parallelogram).
CM = CE (equivalent substitution).
ab df, ce cm=ef bf (parallel line bisecting line segment theorem).
CM = CE (verified), EF = BF.
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Anonymous users2024-01-311 30 (x+3)+5=30 x x=32 10*(1+2x) *2000(1+x)=60000 x=50%3 The current speed x, 1600 x=4+1600 (x+20) x=80 140-80=60, can also increase by 60
4 (1)14000(1-x) =12600 x=2)12600 (shed grinding slip 1-5%) 11340 The swim is good to not fall below 10000
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Anonymous users2024-01-30It can be known that the length of the road is the same as the length of the flowers and plants is 50m, in fact, the width of the rectangle is divided into the width of the road and the width of the flowers, and the width of the road can be set to be x meters, then 3 * 50 * x = 50 * (30-x), and the solution x is meters.
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Anonymous users2024-01-291500 divided by 4 is the area of the road.
If the length is not limited, it can be repaired as wide as possible, less than 50 meters.
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Anonymous users2024-01-28The total area of flowers and plants is 3 times that of the road, so the area of the open space is 4 times the area of the road, that is, the area of the road is 375 square meters. The width of the road is x, and since the direction of the road is not known, there are two cases:
If the length of the road is 50 meters, then 50x=375,x=, which is in line with the topic;
If the length of the road is 30 meters, then 30x=375,x=, also fits the topic.
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Anonymous users2024-01-27Let the runway length s, then s (v A-v B) = (60-10) = 50;s (v A-v C) = (70-30) = 40,; Therefore s (v B - v C) = 200
It is also known from the fact that A catches up with B and s (v A-v B) = 50 at the 10th second, and B is at s 5 in front of A;
It is known from the fact that A catches up with C and s (v A-v C) = 40 at 30 seconds, and C is 3s 4 in front of A. Therefore, C is 3s 4-s 5=11s 20 in front of B, and then there is s (v B-v C) = 200, and B takes 110s from the start to the first time to catch up with C.
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Anonymous users2024-01-2630 seconds, isn't the title said?
Set up x yuan. For every price increase, 10 pieces are sold less. >>>More
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is f(2-x)+f(x-2)=2, because the condition given in the question is f(x)+f(-x)=2, and if 2-x is regarded as x by commutation, then -x=x-2. Therefore, the first way to write it is correct.
I also thought about this problem when I was in high school, first of all, the front multiple-choice questions should be done quickly, the method should be used flexibly, and it is not necessary to do the whole process, you can use a special method to bring in the method and a series of quick practices, and then fill in the blanks as much as possible, basically send points in front, there are two difficult points in the back, the first 2 questions of the big topic are very basic to ensure that they are all right, and the big questions behind should have the concept of step-by-step scoring, don't look at the type of question that you have not seen it and feel that it is difficult to have no confidence, the first few steps can still be scored, The next few steps are written to where it counts, and this is a score. In general, we should pay attention to the foundation, ensure that the basic score is not lost, the time should be allocated well, if the level of multiple-choice questions is good in 30 minutes, generally, about 40, fill-in-the-blank questions should have 30 minutes to do, and then there is about an hour, the first 2 big questions are 15 minutes, and the rest of the time try to do the rest of the questions! >>>More