Physics: A thermometer with inaccurate scale marks but uniform scales

1) When the indicator is 6, it is the actual 0, when the indicator is 86, it is the actual 100, so the temperature range of the thermometer is 100 (86-6) = (100 80) every two adjacent scales, that is, the thermometer changes every 1 grid, the actual temperature change is (100 80), and the actual temperature that can be calculated with this thermometer is t = 100 80 * (t-6), and t is the indication of this thermometer.

So when the indication is 20, substitute the above formula: t=100 80*(20-6)=.

2) Directly substitute the above equation, that is, solve the equation t=100 80*(t-6), and solve t=30

3) The minimum temperature is t=100 80*(-10-6)=-20 The maximum temperature is t=100 80*(100-6)=so the range is -20

1. Establish a plane Cartesian coordinate system with a standard thermometer and an inaccurate thermometer as the coordinate axis, and transform the known conditions into a straight line over two points.

(0,6), (100,86);

2. Find the equation of the straight line y=kx+b

3. Find the actual temperature according to the inaccurate thermometer reading, that is, substitute Y to find X; On the contrary, to give the actual temperature reading is to substitute x to find y

4. When the temperature indication is the same as the actual temperature of the object, it is to find the intersection of y=kx+b and y=x.

5. All other questions are converted into linear equation problems by analogy.

To sum up, the basic idea of this type of problem is to use the coordinate system to transform the problem.

Solution: When inserted into the ice-water mixture, the indication is 4, that is, 4 represents the actual 0; When inserted into 100 boiling water, the number is 96, which means that 96 represents the actual 100, and 0 to 100 cells represent one degree, i.e. 4 to 96, and divide it into 100 cells, and the temperature of each cell is.

So the actual temperature is.

20, so choose B

That is, each scale represents degrees.

The first question ******************** the actual temperature in the classroom is Celsius.

Second question********************x-6)*

Solution x=30

The third question ******************** measurement range is -20 degrees Celsius.

100 (86-6) = degrees, (each grid on the thermometer represents the actual degree) 20-6) * degrees.

t actual temperature = (t measure -6)*

two equal, t=(t-6)*, t=30;

10 100 substitution.

t actual temperature = (t measure -6)*

The actual temperature of t can be obtained at -20

Regardless of whether the indication is accurate or not, the liquid column of the thermometer is always uniformly rising, the best way to do this kind of problem is not to be misled by the wrong indication, you may wish to treat the wrong indication as a unit of length to solve, 6 in ice water is regarded as the height of the liquid column is 6 mm, and 86 in boiling water is regarded as the height of the liquid column is 86 mm.

Then obviously, 6mm-86mm represents the temperature from 0-100 degrees Celsius, because the liquid column of the thermometer always rises uniformly, so this 80mm=100 also means, or 1mm=

1. Then the thermometer shows that 20mm is 14mm more than 6mm (0), 14mm=.

2. Suppose that when x is displayed, the actual temperature is the same, and the actual temperature = (x-6)*, and the solution is x=30, so when 30 is displayed, the actual temperature is the same as the display.

3. The lower limit of the thermometer is -10mm, the actual temperature is (-10-6)*, the upper limit is 100mm, the actual temperature is (100-6)*, so the actual measurement range is -20

When it is inserted into boiling water at 1 standard atmosphere, the thermometer shows 84 and the actual temperature is 100

When inserted into the ice-water mixture, the thermometer is 4, the actual temperature is 0, the temperature difference = 84-4=80, the actual temperature difference = 100-0-100, then the actual temperature difference is 1, the temperature difference on the indicator is.

The 1 on the indicator represents the actual temperature of 100 80 1 = When it is inserted into a cup of hot water, the indicator is 60, then the actual temperature = (60-4) It was a greenhouse 20 at that time, then use this thermometer to measure the indicator = (20-0) If you don't understand, you can ask

The temperature of the mixture is zero, and the temperature of the standard pressure boiling water is 100 degrees, but the thermometer only uses 90-10 = 80 scales, so the actual temperature of each scale is 100 80 = 10 8 = 5 4 degrees.

Then, the indoor air temperature at that time was 60 degrees Celsius: :(x-10)*5 4 = 60 x = 58 °C

Illustrating that 0 °C is at the 10 tick line and 100°C is at the 90 tick line, then the length of the 80 tick lines represents 100°C

Each 1 tick represents 100 to 80 °C

In the problem, the distance at 60 °C is 0 °C, that is, there are n lines at the 10 tick line, t=n 100, 80=60°C

n=58

Thermometer 10 = 0

That's in the range of 100 degrees Celsius, and the thermometer is only counted as 80 and 1 of the thermometer = actual.

The temperature of the ice-water mixture is 0, and the temperature of boiling water at standard atmospheric pressure is 100; The temperature of the ice-water mixture measured by the thermometer is 10, the temperature of the standard atmospheric pressure boiling water is 90, and the middle is 80 grids, and the temperature represented by a small grid is obtained;

2) the thermometer is inserted into an object to show that the temperature is 60, and there are 50 cells at a distance of 10, and the temperature represented by 50 cells is found to be the actual temperature 0 when the thermometer is displayed as 10, which is the actual temperature of water

100 (90-10)]*x-10)=60°C When the thermometer is 60, the actual temperature is x=58°C

The actual temperature of the ice-water mixture is 0. The actual temperature of boiling water is 100. From this, it can be seen that the temperature of each scale is 100 (93-3) = 10 9 degrees. The actual temperature of a liquid is (30-3) 10 9=30.

Why use 30-3, because the 3 on the scale is the real 0 degrees, so the scale between 3 and 30 is the real temperature.

First, determine how many degrees a grid represents. The ice-water mixture is 3, and the boiling water is 93, so this thermometer is: 100 (93-3) 10 9 (grid) 30 degrees of liquid, first calculate how many grids there are to 0 degrees:

30-3 27 (grid) and then multiply by one degree of square: 27 10 9 30

B changes from 20 degrees to 80 degrees, and A changes from 15 degrees to 78 degrees. A changes by 63 degrees, and B changes by 60 degrees. So, 1 degree of B is equivalent to 63 60 = degrees of A, and 1 degree of A is equivalent to 60 63 = 20 21 degrees of B.

When A is 15 degrees, B reads 20 degrees. A grows by 5 degrees, and B grows by 5 * 20 21 = 100 21 = degrees. So, when A is 20 degrees, B is 20+ degrees.

Because B's 1 degree is equivalent to A's 63 60= degrees, A's reading grows faster than B's. When A is 15 degrees, B's reading is 20 degrees, and A is lower than B. Then as the temperature increases, the gap between A and B will gradually narrow, and eventually it will be the same.

So, there will be a temperature that makes the indication of A and B the same.

When A is 15 degrees, B reads 20 degrees, and the difference in reading is 5 degrees. For every 1 degree increase in B's reading, the difference between A and B's readings decreases. Then, when B's reading is increased by 100 degrees, the difference between the readings is 0. At this point, both readings are the same, both are 120 degrees.

When B has a signal of 20 degrees Celsius, A has a signal of 15 degrees Celsius; When B's indication is 80 degrees Celsius and A's indication is 78 degrees Celsius, then:

1. When A's indication is -2 degrees Celsius, what is B's indication?

2. Is there such a temperature, A and B are exactly the same?

Answer: Because the principle of the thermometer is that the height of the scale mark is linearly related to the temperature, let the true temperature of A (the number of B) be x, the apparent temperature (the number of A) be y, and the correlation coefficient is a and b; then we get x=a*y+b

Substituting the subject condition in: 20=a*15+b;

80=a*78+b

The solution of the continuous equation is: a=60 63=20 21, b=40 7

Then: x,y is the relationship is: x=20 21*y+40 7....1）

1. When the indication of A is -2, the indication of B is: x=20 21*(-2)+40 7=80 21=degrees.

2. The number of A and B is the same, which means x=y, and substituting (1) to get x=y=120 degrees.

Question addendum: An unflipped thermometer (reading is Celsius) is used to measure the temperature of two patients, and if the temperature of both patients is Celsius and Celsius, the temperature is ( ) and ( ) respectively

If the temperature is measured in the order of Celsius and Celsius, the measured temperature should be Celsius and Celsius, because if it is not shaken, the thermometer will show a higher temperature than the thermometer temperature.

Eat a good breakfast, a full lunch, and a small dinner. What does this distribution look like?

This is because after a night's sleep, the metabolism is already very slow, breakfast is the driving force to adjust the metabolism, if you don't eat breakfast, the metabolism still maintains a very slow level, then your consumption is much less than the consumption of people who eat breakfast, the speed will be much slower, and it is very harmful to the body, especially the appetite. Breakfast can also replenish the body's energy and prevent overeating at lunch.

Lunch should be full because the afternoon is the time when the human body consumes the most and needs to replenish energy to work. In addition, if you have a full lunch, you can also reduce the desire to snackle.

Dinner should be eaten less because they are resting at night, the consumption is small, and the digestion and absorption function at night is stronger than that during the day, so supper at night is very fat.

From the meaning of the title, the actual temperature change is 10, and the thermometer's indicator change is more Celsius than the original, which is 10+1+Celsius;

Therefore, the temperature rises by 10 degrees, and the thermometer changes more degrees Celsius, which is more Celsius than the original, so the measured value is higher than the original;

1 The difference between the temperature of boiling water and the temperature of the ice-water mixture at standard atmospheric pressure is 100, so the difference between the thermometer is .

100 degrees Celsius = 115 degrees Celsius

So the answer is: high 2; 115．

Because the scale is uniform, and because it is actually a 0 degree ice-water mixture.

The display is 4 degrees, but the boiling water that is actually 100 degrees Celsius is displayed as 94 degrees, so the displayed temperature = actual temperature*

So the measured 67 degrees should be (67-4) degrees.

The actual 50 degrees should be 50* degrees.

This kind of question can be used.

c=(c1-c2) 100*(c3-c1)!

The answer is C

Analysis: A standard thermometer assumes that there are 100 bars in between from 0 to 100, so each bar is 1

This thermometer is actually going from 4 to 99 to reflect a true 100 variation, meaning that each cell of this thermometer is actually (100 95).

And its 4 is the beginning of the real 0, which can be obtained, assuming that the temperature displayed by the thermometer is t at this time

Then there is (t-4) (100 95) =20 and we get: t=23

I hope that makes it clear!

The team will answer for you. Hope it helps!

Choose C. If the scale is uniform, there are 95 scales from 0 °C to 100 °C, and if the room temperature is 20 °C, it is regarded as rising from 0 to 20, an increase of one-fifth, that is, 95 5 = 19 scales should be added. Then the final temperature is 4+19=23 (don't forget the original scale).

Actually, I guessed at the beginning, and the idea of guessing:

This thermometer is different, it must be the second generation of officials and the second generation of rich, because it has won at the starting line (it has already shown that it is 4 °C at zero degrees), but it has the stamina but not the stamina (it cannot reach 100 °C in boiling water). Therefore, at the beginning, at room temperature, the value of this official second generation must be higher than the normal thermometer (excluding a d), but because there is no stamina, it will not be higher than 4 °C, so d is excluded. Well, I think too much, young man, come on!

As long as it is a multiple-choice question, it generally relies on the elimination method. Wait until you have figured out the correct answer before you choose, and you will already waste more than half of your time.

d is explained as follows: 1 The temperature of boiling water at standard atmospheric pressure is 100 degrees Celsius, and the mixture of ice water is 0 degrees Celsius, so the ratio formula can be obtained.

95 100 = x 20, get x = 19