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If it is a power amplification circuit, it is recommended that you post the circuit.
If it is a general co-ejection, the key is to find the UCEQ, and if there is no AC load (i.e., no load at the output), find the smaller value of (VCC-UCEQ) and (UCEQ-UCES).
where VCC is the supply voltage and UCES is the critical saturation voltage.
If there is an AC load, find the smaller value of (UCEQ-UCES) and (ICQ (RC RL)).
is a static working point.
To the voltage difference of the transistor saturation or cut-off, when the operating point is selected in the middle of the saturation and cut-off, the voltage difference is the maximum undistorted output voltage amplitude.
When the saturation is greater than the cut-off, the small point voltage difference is the maximum undistorted output voltage amplitude.
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Measurement of the maximum undistorted output voltage UOPP (maximum dynamic range).
As mentioned above, for maximum dynamic range, the static operating point should be adjusted to the midpoint of the AC load line. Therefore, under the normal operation of the amplifier, gradually increase the amplitude of the input signal, and at the same time adjust the RW (change the static working point), observe the UO with an oscilloscope, when the output waveform appears at the same time shaving and shrinking the phenomenon (as shown in Figure 2 5), it means that the static working point has been adjusted to the midpoint of the AC load line. Then, when the input signal is repeatedly adjusted to maximize the output amplitude of the waveform without obvious distortion, the dynamic range is equal to when the UO (RMS) is measured by an AC millivoltmeter.
Or use an oscilloscope to read out the UOPP directly.
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Upstairs there is a wrong AC load, which is the smaller value of (uceq-uces) and (icq rc rl)).
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Find the static operating point: ic
AC Load Resistance: RL'=rc//rl
The negative half cycle works at most until the cut-off, that is to say, the amount of change is at most: δic=ic-0, then the peak value of the output signal is: uop=δic*rl'
So the RMS value of the output signal is uo = uop 2
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That is, it can ensure that the entire speaker is not distorted, and then it can have the maximum current that it can withstand.
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Calculating the maximum undistorted output voltage amplitude requires an understanding of the amplifier's maximum output voltage and distortion limit.
Generally speaking, the maximum output voltage of an amplifier is determined by the supply voltage and the circuit design of the amplifier. The distortion limit is usually given by the amplifier's specifications or performance parameters.
Here's a simple formula to calculate the maximum undistorted output voltage amplitude:
Maximum undistorted output voltage amplitude = distortion limit of the amplifier) gain of the amplifier).
For example, if the gain of the amplifier is 20 and the distortion limit is 10VRMS, then the maximum undistorted high car output voltage amplitude is:
Maximum undistorted output voltage amplitude = 10 20 = VRMS
It is important to note that the above formula only applies to linear amplifiers. For nonlinear amplifiers, more sophisticated analysis methods are required to calculate the maximum undistorted output voltage amplitude.
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The maximum undistorted output voltage amplitude of the amplification circuit must be less than the operating supply voltage range of the circuit.
Maximum undistorted output voltage RMS: UOM=(VCC-ID*RC RL) 2.
Because when the no-load voltage or load is small, the saturation voltage of the tube is low, the maximum undistorted output voltage is higher, and the saturation voltage drop is large when the load is large, and the output amplitude is small. In addition, when the load is large, the voltage and current curve of the amplifier is seriously inclined upward, and the output distortion is serious, and the output voltage will be reduced under the same degree of distortion.
To put it simply, because the undistorted output voltage is basically the voltage peak between the cut-off and saturation of the load side, and the load voltage and the CE voltage of the transistor are equal to the power supply voltage after being connected in series, the output current of the load becomes larger, the voltage on the transistor is large, and the undistorted voltage of the load is naturally smaller.
What should be done to increase the maximum undistorted output amplitude of the amplifier circuit: The amplitude of an amplifier is related to many other factors, and the larger the amplitude and the simpler the better. But in reality, they are full of contradictions, and in order to improve the stability of the amplifier, the emitter negative feedback resistance and the lower bias resistance are added.
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If it is a power amplification circuit, it is recommended that you post the circuit.
If the hail collapse is a general co-ejection, the key is to find the UCEQ, if there is no AC negative source circle load (that is, no load at the output end), find the smaller value of (VCC-UCEQ) and (UCEQ-UCES).
where VCC is the supply voltage and UCES is the critical saturation voltage.
If there is an AC load, find the smaller value of (UCEQ-UCES) and (ICQ (RC RL)).
It is the voltage difference between the static operating point and the saturation or cut-off of the transistor, when the working point is selected in the middle of the saturation and cut-off, the voltage difference is the maximum undistorted output voltage amplitude.
When the saturation is greater than the cut-off, the small point voltage difference is the maximum undistorted output voltage amplitude.
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