Write the ionic equation for the reaction containing NaHSO4, whether NaHSO4 is split into Na, H, SO4

According to the middle school textbook, it should be: na, h, so42-;

But in fact, na, HSO4 is also good, but I'm afraid you won't understand, so it's written in the textbook like the previous one. Most teachers also know only half of it, and they will be wrong if they are wrong, and even emphasize this as a knowledge point.

When you go to college and have studied basic inorganic chemistry or analytical chemistry, you will know these ......

NaHSO4 can be written as NAHso4=NA+ +H+ +SO42 when it melts in water, where the ionization of water is H2O=H+ +OH-)

Because NaHSO4 is acidic when melted in water, H+ is greater than OH-, so the liquid contains a large amount of H+

NaHSO3 melts in water and is written as NAHso3=NA+ HSO3 - because NAHso3 melts in water and is reduced, OH- is greater than H+, so the liquid contains a large amount of OH-

You can analyze the size of H+ and OH- according to the properties of the liquid.

It's hard to say, but you can write about this question in the future:

1.If it's nahso4, it's split into:

nahso4=na+ h+ so42-

2.If it's nahso3, split it into:

nahso3=na+ hso3-

If it is sulfurous acid, write h together, and vice versa) even in practice to encounter this problem).

The ionic equation for the reaction of NaHSO4 with Ba(OH).

It is a pure cavity 2H++SO4+Ba2++2OH-=2H2O+BaSO4, the ion equation, that is, the ion symbol of the real type participating in the reaction represents the ion reaction.

of the formula. The ionic equation not only represents a certain reaction between certain substances, but also represents the same type of ionic reaction. For slightly soluble substances, it is said that in ionic reactions, it usually exists in ionic form (in solution), but if it is in turbid liquid, it is necessary to write the complete chemical formula.

2:12nahso4+ba(oh)2=na2so4+baso4+2h2o

Ion 2H++SO42-+Ba2++2OH-=BASO4+2H2O1:1NaHSO4+BA(OH)2=BASO4+NAOH+H2Oion H++SO42-+BA2++OH-=BASO4+H2ORemember filial piety rolls to sell the chain to play the precipitate character, and the Shensun number can not be subscripted, just look at it

Can react. nahso4+nahso3==na2so4+h2o+so2↑

Because NaHSO4 is completely ionized, the sulfite ions produced by the ionization of celery late hydrogen ions and NaHSO3 are counter-suspicious to generate sulfurous acid, which decomposes to water and sulfur dioxide.

There is a mistake in the building.

There are two equations for those who are not springy according to the quantity.

SO42- +BA2+ +OH- =BASO4+ H20NAHSO4+BA(OH)2=BASO4+NAOH+H2O) BA(OH)2 Excessive pickpocketing.

2oh- +ba2+ +so42- =baso4+2h2o2nahso4+ba(oh)2=baso4+na2so4+2h2o) NaHSO4 excess.

6nahso3 + 4hno3 (shiny skin sparse closed key search) car calendar ===3na2so4 + 4no + 3h2so4 + 2h2o

2NaHSO3+4HNO3 (concentrated) ==NA2SO4+4NO2+H2SO4+2H2O

In the solution, NaHSO4 is completely ionized, and there are hydrogen ions present, then hydrogen gas is released, and the corresponding equation is:

zn+2nahso4=znso4+na2so4+h2；

zn+2h(+)h2+zn(2+)

NaHSO4 cannot ionize hydrogen ions in the molten state of cultivation, so the mid-year band is not contrary to Lu Ying.

Chemical equation: NaHSO4 + NaHCO3 = NA2SO4 + H2O + CO2

The ionic equation: H+ +HCO3- =H2O + CO2 is equivalent to the reaction of strong acid and sodium bicarbonate. NaHSO4 is the same as monobasic strong acids, and HSO4- is completely ionized.

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